Calculate unbiased estimates from raw sample data
Use the sample average and the n-minus-one variance estimate, distinguishing them from descriptive variance.
Section 6.4 · Sampling and estimation
Exam scope and assessment notes
Probability & Statistics 2 (Paper 6, A Level) · Mathematics 9709, 2026–2027, section 6.4. Paper 6 builds on Paper 5 and assumes Paper 3 calculus. Distinguish population parameters, sample statistics and repeated-sample random variables. Random selection needs a relevant frame and does not automatically remove undercoverage or non-response. Particular named sampling methods are not required. Sample-mean formulae here assume independent observations from one population with finite variance: E(X̄) = μ, Var(X̄) = σ²/n and SE = σ/√n. A mean of independent normal observations is normal; the CLT gives an approximate normal mean for an adequate large independent sample, not normal individual data. No universal sample-size cutoff guarantees that approximation. Unbiased sample variance uses n − 1, with n > 1. Mean intervals use the normal model with known variance or a large-sample approximation; a small sample with unknown variance does not justify the z method taught here. Proportion intervals use the large-sample normal approximation with adequate success and failure counts; extreme or sparse counts may invalidate it. Quoted two-sided critical values are 1.645 for 90%, 1.960 for 95% and 2.576 for 99%; retain other working unrounded. Confidence describes repeated-sampling coverage, not posterior probability for a fixed realised interval, individual observations or a guarantee. A narrower interval does not repair a biased sample. Hypothesis testing belongs to section 6.5. Written practice is self-checked; cumulative assessment and human subject-teacher review remain pending.
Before you begin
- Calculate squared deviations.
- Distinguish population and sample moments.
Work on paper. Try each question before revealing help, and explain why your method works.
Quick readiness check
Which divisor gives the unbiased variance estimate for four observations?
What you will learn
- Calculate unbiased estimates of mean and variance.
- Interpret unbiasedness over repeated samples.
Estimate centre and population spread
For the independent sample 2,4,6,8, n = 4 and x̄ = 5. Squared deviations sum to 9 + 1 + 1 + 9 = 20. The unbiased estimate of population variance is s² = 20/(4 − 1) = 20/3.
Dividing by n gives descriptive sample variance five. That is a different quantity from the unbiased estimator of population variance. s denotes √s²; the square root itself is not generally an unbiased estimator of population SD.
Unbiased does not mean exact in every sample
An unbiased estimator has expectation equal to its target over repeated samples from the stipulated model. Individual estimates fluctuate and can be above or below the population parameter. For n > 1, s² = Σ(x − x̄)²/(n − 1) is unbiased under independent same-population finite-variance sampling.
For two independent draws from equally likely values two and six, the four ordered samples give s² values 0,8,8,0. Their average is four, matching population variance four. This demonstrates repeated-sample meaning, not a guarantee that each estimate equals four.
Pause and explain
What does unbiased mean in this setting?
Worked example
Find unbiased mean and variance estimates for 2,4,6,8.
Show the worked solution
- Mean = 20/4 = 5.
- Sum squared deviations = 20.
- Divide by n − 1 = 3.
Answer Mean estimate 5; variance estimate 20/3.
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Test this topic →From guided practice to a new situation
Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.
Find unbiased mean and variance estimates from 2,4,6,8.
Give me a hint
Use the sample centre and n − 1 for variance.
Compare my reasoning
- Mean is five.
- Squared deviations sum to twenty.
- Variance estimate is twenty divided by three.
Mean 5; variance 20/3.
Look for these in your work
- Use n − 1.
- Distinguish estimate from parameter.
For sample 1,3,5, find unbiased mean and variance estimates.
Give me a hint
Centre the three values before squaring deviations.
Compare my reasoning
- Mean is three.
- Squared deviations sum to eight.
- Divide by two for variance four.
Mean 3; variance 4.
Look for these in your work
- Use all squared deviations.
- Keep the two divisors distinct.
For two independent draws from equally likely two and six, list s² for the four ordered samples and its expectation.
Give me a hint
Use divisor one and keep all ordered outcomes.
Compare my reasoning
- Samples (2,2),(2,6),(6,2),(6,6) give 0,8,8,0.
- Each pair has probability one quarter.
- Average variance estimate is four.
s² values 0,8,8,0; expectation 4, the population variance.
Look for these in your work
- Retain repeated mixed outcomes.
- Explain repeated-sampling unbiasedness.
Common mistakes
- Use n − 1 for unbiased variance, with n > 1.
- An unbiased estimate can differ from the true value.
- Do not call s an unbiased SD estimator automatically.
What can you explain now?
Must each unbiased variance estimate equal the population variance?
Compare with the explanation
No.
The estimator is correct on average over repeated samples.
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Make it stick
Unbiasedness is a repeated-sample property; use n − 1 for the variance estimate.
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