Differentiate trigonometric composites using radian measure
Use the sine, cosine and tangent derivatives with their inner factors, signs and original tangent exclusions.
Section 3.4 · Differentiation
Exam scope and assessment notes
Pure Mathematics 2 (Paper 2, AS only) and Pure Mathematics 3 (Paper 3, A Level) · Mathematics 9709, 2026–2027. Paper 1 knowledge is assumed. The AS route using Papers 1 + 2 cannot be carried forward to A Level. Shared sections 2.4 and 3.4 cover exponential, natural logarithmic and trigonometric derivatives, composites, products and quotients, and first derivatives of parametric and implicit curves, including tangents and normals. Paper 3 additionally requires the derivative of inverse tangent; use its separate lesson for that method. Derivatives of inverse sine and inverse cosine are not required in section 3.4. Trigonometric differentiation uses radians. Keep original domains and check zero derivative denominators separately. Written practice is self-checked.
Before you begin
- Use sine, cosine, tangent and secant and understand radian measure.
- Apply the chain rule and evaluate exact trigonometric values.
Work on paper. Try each question before revealing help, and explain why your method works.
Quick readiness check
What is d(cos x)/dx for radian x?
What you will learn
- Differentiate sin x, cos x and tan x in radians and apply the chain rule.
- Connect a derivative's value to a curve gradient or a signed motion rate, keeping domains and units.
The standard trigonometric derivatives assume radians
With radian input x, d(sin x)/dx = cos x, d(cos x)/dx = −sin x and d(tan x)/dx = sec² x. Tangent and its derivative require cos x ≠ 0. For an inner rule u(x), multiply by u′: the derivatives are u′ cos u, −u′ sin u and u′ sec² u, with the tangent domain cos u ≠ 0. Keep a cosine derivative's negative sign separate from any outside coefficient.
These formulae are for radians. If a function is defined using a degree variable d, write its radian input explicitly: sin(πd/180) differentiates with respect to d to (π/180)cos(πd/180). A calculator's display mode does not remove this scale factor. In the usual syllabus calculus questions, use the radian input and retain every stated inner factor.
A curve height and its gradient are different outputs
For y = 3 sin 2x − 4 cos x + tan 3x, differentiation gives y′ = 6 cos 2x + 4 sin x + 3 sec² 3x, where cos 3x ≠ 0. The sign of the second term is positive because the outside −4 multiplies the cosine derivative's negative sign. For y = sin x, at x = π/2 the curve height is 1 but its derivative cos x is 0. At x = π/6 the height is 1/2 and the gradient is √3/2.
A supplied signed displacement S(t) = 4 sin(πt/6) cm, with t in seconds, has velocity S′(t) = (2π/3)cos(πt/6) cm/s. At t = 3 seconds the displacement is 4 cm and the velocity is zero; at t = 6 seconds the velocity is −2π/3 cm/s. A negative signed velocity indicates decreasing displacement, not a negative speed. The phase coefficient π/6 is an inner rate measured in radians per second.
Pause and explain
What is the derivative of tan(x²) where the original function is defined?
Worked example
Differentiate y = 3 sin 2x − 4 cos x + tan 3x, using radians and stating the original tangent restriction.
Show the worked solution
- The sine term gives 3(2)cos 2x = 6 cos 2x.
- The cosine term gives −4(−sin x) = 4 sin x; the tangent composite gives 3 sec² 3x.
- Add the terms and retain cos 3x ≠ 0, the original tangent's denominator restriction.
Answer y′ = 6 cos 2x + 4 sin x + 3 sec² 3x, with cos 3x ≠ 0.
Try a topic test
Choose Easy, Normal or Difficult. Save your answers and open worked review after finishing.
Test this topic →From guided practice to a new situation
Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.
Differentiate y = 2 cos 3x + sin x in radians and evaluate y′ at x = 0.
Give me a hint
Differentiate the cosine composite with both its negative sign and factor 3.
Compare my reasoning
- The first term gives −6 sin 3x and the second gives cos x.
- Thus y′ = −6 sin 3x + cos x for every real x.
- At zero, sine is 0 and cosine is 1, so y′(0) = 1.
y′ = −6 sin 3x + cos x; y′(0) = 1.
Look for these in your work
- Keep the composite factor and cosine derivative sign.
- Evaluate the derivative rather than the original curve height.
Differentiate y = tan(x²) in radians and state the restriction on its finite derivative.
Give me a hint
Use the tangent chain derivative and check its cosine denominator.
Compare my reasoning
- Set u = x², with inner derivative 2x.
- The outer derivative is sec² u, so y′ = 2x sec²(x²).
- Require cos(x²) ≠ 0; this preserves the original tangent domain, including valid input x = 0.
y′ = 2x sec²(x²), with cos(x²) ≠ 0.
Look for these in your work
- Retain the unchanged composite argument.
- State the original tangent's excluded inputs through its cosine condition.
A supplied signed displacement is S(t) = 4 sin(πt/6) cm, with t in seconds. Find the velocity at t = 3 and 6 seconds and interpret the sign.
Give me a hint
Differentiate with respect to time and retain the phase's inner rate π/6.
Compare my reasoning
- The velocity is S′(t) = (2π/3)cos(πt/6) cm/s.
- At t = 3 the cosine is zero, giving 0 cm/s; at t = 6 it is −1, giving −2π/3 cm/s.
- The negative value means displacement is decreasing at that instant; its speed is the positive magnitude 2π/3 cm/s.
Velocity 0 cm/s at t = 3; −2π/3 cm/s at t = 6; speed at t = 6 is 2π/3 cm/s.
Look for these in your work
- Use the phase's radian rate in the chain rule.
- Distinguish signed velocity from its non-negative speed magnitude.
Common mistakes
- The standard derivatives use radians, not an unconverted degree variable.
- A cosine derivative contributes a negative sign.
- Keep the inner rate and the original tangent denominator restriction.
What can you explain now?
Give the height and gradient of y = sin x at x = π/2.
Compare with the explanation
Height 1; gradient 0.
Evaluate sine for the height and its derivative cosine for the gradient.
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Make it stick
State the three trigonometric derivative rules and their angle-unit assumption. Explain how to differentiate a composite tangent and distinguish a sine height from its cosine gradient.
If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.