Expand compound angles and evaluate exact trigonometric values
Choose the correct signs in addition and subtraction formulae, simplify angle-shifted expressions and keep exact surd values.
Section 3.3 · Trigonometry
Exam scope and assessment notes
Pure Mathematics 2 (Paper 2, AS only) and Pure Mathematics 3 (Paper 3, A Level) · Mathematics 9709, 2026–2027. Paper 1 knowledge is assumed. The AS route using Papers 1 + 2 cannot be carried forward to A Level. Shared sections 2.3 and 3.3 cover all six trigonometric functions, reciprocal squared identities, compound and double angles, and amplitude-phase forms used in simplification, exact evaluation and equations. State angle units, keep original domains and find every solution in the supplied interval. Written practice is self-checked.
Before you begin
- Use exact 30°, 45° and 60° values and simplify surds.
- Keep denominator restrictions while manipulating trigonometric expressions.
Work on paper. Try each question before revealing help, and explain why your method works.
Quick readiness check
Which expansion is correct for cos(A + B)?
What you will learn
- Use expansions for sin(A ± B), cos(A ± B) and tan(A ± B) with valid domains.
- Select suitable special-angle combinations for exact values and simplify shifted expressions.
Addition and subtraction have different sign patterns
The sine formulae are sin(A + B) = sin A cos B + cos A sin B and sin(A − B) = sin A cos B − cos A sin B. For cosine, cos(A + B) = cos A cos B − sin A sin B and cos(A − B) = cos A cos B + sin A sin B. The sign in a cosine expansion is opposite to the angle's written sign. These sine and cosine identities are valid for all real angles, with both inputs measured in the same unit.
Where the terms are defined, tan(A + B) = (tan A + tan B)/(1 − tan A tan B) and tan(A − B) = (tan A − tan B)/(1 + tan A tan B). For these expressions require cos A ≠ 0, cos B ≠ 0 and the relevant denominator non-zero; the original tangent of the combined angle must also be defined. The zero denominator for A = B = 45° correctly signals that tan 90° is undefined. If an individual tangent is undefined but the combined angle's tangent is valid, use sine and cosine expansions instead of this quotient formula.
Expand before collecting coefficients
To evaluate sin 75° exactly, use 75° = 45° + 30°. The addition formula gives (√2/2)(√3/2) + (√2/2)(1/2) = (√6 + √2)/4. For tan 15°, use 45° − 30° to obtain (1 − 1/√3)/(1 + 1/√3) = (√3 − 1)/(√3 + 1) = 2 − √3. Using tangent addition instead gives tan 75° = (1 + 1/√3)/(1 − 1/√3) = (√3 + 1)/(√3 − 1) = 2 + √3, with non-zero denominator. Rationalisation preserves an exact value; an early decimal approximation would obscure the surd result.
For cos(x − 30°) − 3 sin(x − 60°), expand both shifted functions in degrees. The first is (√3/2)cos x + (1/2)sin x. The second, including its −3 multiplier, is −(3/2)sin x + (3√3/2)cos x. Collecting gives 2√3 cos x − sin x. Distribute an outside negative multiplier across both terms before combining, and keep x in degree measure throughout this identity.
Pause and explain
For A = B = 45°, the denominator of the tangent addition formula is zero. What does this mean?
Worked example
Simplify cos(x − 30°) − 3 sin(x − 60°) into a combination of sin x and cos x, with x measured in degrees.
Show the worked solution
- Expand cos(x − 30°) as (√3/2)cos x + (1/2)sin x.
- Expand −3 sin(x − 60°) as −(3/2)sin x + (3√3/2)cos x.
- Collect the cosine and sine coefficients separately to obtain 2√3 cos x − sin x.
Answer 2√3 cos x − sin x, for degree input x.
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Test this topic →From guided practice to a new situation
Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.
Find sin 75° exactly using 45° + 30°.
Give me a hint
Use the sine addition formula and keep the special-angle values as surds.
Compare my reasoning
- Write sin 75° = sin 45° cos 30° + cos 45° sin 30°.
- Substitute to get (√2/2)(√3/2) + (√2/2)(1/2).
- Combine over denominator 4 to obtain (√6 + √2)/4.
sin 75° = (√6 + √2)/4.
Look for these in your work
- Choose the correct addition formula and signs.
- Retain an exact surd result rather than round its terms.
Find tan 15° exactly using 45° − 30°.
Give me a hint
The tangent subtraction denominator has a plus sign; rationalise only after forming the full quotient.
Compare my reasoning
- Use (tan 45° − tan 30°)/(1 + tan 45° tan 30°) = (1 − 1/√3)/(1 + 1/√3).
- Multiply numerator and denominator by √3 to get (√3 − 1)/(√3 + 1).
- Rationalise with √3 − 1 to obtain (4 − 2√3)/2 = 2 − √3; the original denominator is non-zero.
tan 15° = 2 − √3.
Look for these in your work
- Use the subtraction formula's positive denominator sign.
- Check the domain and simplify the exact quotient correctly.
A unit vector initially points at 30° from the positive x-axis and is rotated anticlockwise by 45°. Find its new exact coordinates and verify its length.
Give me a hint
The new direction is 75°; use the compound cosine and sine formulae for the two coordinates.
Compare my reasoning
- The new angle is 30° + 45° = 75°, so its coordinates are (cos 75°, sin 75°).
- The exact pair is ((√6 − √2)/4, (√6 + √2)/4).
- The sum of their squares is [(8 − 4√3) + (8 + 4√3)]/16 = 1, retaining unit length.
((√6 − √2)/4, (√6 + √2)/4); squared length 1.
Look for these in your work
- Connect rotation to a compound angle and the correct coordinate order.
- Check the exact squared length without rounding the surds.
Common mistakes
- The cosine addition formula has a minus sign, while its subtraction formula has a plus sign.
- Use one consistent angle unit in each compound expression.
- A tangent quotient formula needs both individual tangents and its denominator to be defined.
What can you explain now?
Find cos 75° exactly by expanding 45° + 30°.
Compare with the explanation
(√6 − √2)/4.
Cosine addition subtracts the product of the two sines from the product of the two cosines.
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Make it stick
Write all six compound-angle formulae with their signs. Give one exact-value calculation and explain a case where the tangent quotient representation cannot be used.
If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.