Read vector notation and distinguish position from displacement
Use column and basis-vector notation, identify the starting and finishing points, and subtract their positions in the correct order.
Section 3.7 · Vectors
Exam scope and assessment notes
Pure Mathematics 3 (Paper 3, A Level) · Mathematics 9709, 2026–2027, section 3.7. Paper 1 coordinate geometry and algebra are assumed. Work in two or three dimensions as stated. The general section theorem is not included; midpoint geometry is required. The cross product, shortest distance between skew lines and their common perpendicular are not required. Scalar products include angles between lines and the foot of a perpendicular from a point to a line, including 3D solids. Written practice is self-checked; human subject-teacher review remains pending.
Before you begin
- Read signed coordinates in two and three dimensions.
- Subtract signed numbers component by component.
Work on paper. Try each question before revealing help, and explain why your method works.
Quick readiness check
If A has position a and B has position b, which expression is →AB?
What you will learn
- Translate between column vectors, component triples and i, j, k notation.
- Distinguish a position vector from a directed displacement and reverse a displacement correctly.
The notation records ordered components
The unit basis vectors i, j and k point along the positive x, y and z axes respectively. Thus a = 3i − 2j + k has components (3, −2, 1), or column notation (3, −2, 1)ᵀ. In two dimensions omit the third component or use zero when embedding the vector in a 3D coordinate system. The superscript transpose on a component row is a compact way to indicate the corresponding column vector. Keep the component order and signs.
A vector has magnitude and direction; a coordinate point identifies a location in the chosen frame. The position vector of A is the vector from the origin O to A, written →OA or a. An arrow such as →AB instead names a displacement from A to B. Bold letters, arrow notation, basis-vector notation and column vectors can describe the same directed vector. A free displacement can be translated without changing its components, while a position vector depends on the chosen origin.
Finish minus start gives the directed displacement
If A and B have position vectors a and b relative to the same origin, →AB = b − a. For A = (2, −1, 3) and B = (−1, 4, 5), →AB = (−3, 5, 2)ᵀ and →BA = (3, −5, −2)ᵀ. Adding →AB to a produces b, which checks the endpoint. Reversing a displacement changes every component's sign; merely interchanging the labels while leaving the components unchanged is incorrect.
If both points are translated by the same vector c, their displacement is (b + c) − (a + c) = b − a. Their positions change, but their separation vector does not. If a point starts at position p and undergoes displacement d, its final position is p + d. A displacement need not equal the final position unless the starting position is the origin. State the coordinate directions and units in a supplied physical model.
Pause and explain
A point starts at (2, 0, 1) and moves by (−1, 3, 2). What is its final position?
Worked example
For A = (2, −1, 3) and B = (−1, 4, 5), give →AB and →BA in column and basis-vector notation.
Show the worked solution
- Subtract start from finish: b − a = (−1 − 2, 4 − (−1), 5 − 3).
- Thus →AB = (−3, 5, 2)ᵀ = −3i + 5j + 2k.
- Reverse all signs for →BA = (3, −5, −2)ᵀ; a + →AB = b checks the first displacement.
Answer →AB = (−3, 5, 2)ᵀ; →BA = (3, −5, −2)ᵀ.
Try a topic test
Choose Easy, Normal or Difficult. Save your answers and open worked review after finishing.
Test this topic →From guided practice to a new situation
Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.
Let a = 3i − 2j + k and b = −i + 4j + 2k. Give both column vectors and calculate b − a.
Give me a hint
Write the ordered coefficients before subtracting signed components.
Compare my reasoning
- The columns are a = (3, −2, 1)ᵀ and b = (−1, 4, 2)ᵀ.
- Subtract to obtain b − a = (−4, 6, 1)ᵀ.
- Check a + (b − a) = b; the middle subtraction is 4 − (−2) = 6.
a = (3, −2, 1)ᵀ; b = (−1, 4, 2)ᵀ; b − a = (−4, 6, 1)ᵀ.
Look for these in your work
- Retain the component order and every sign.
- Check the subtraction by reconstructing the finishing vector.
A = (−2, 1) and B = (4, −3). Find →AB and →BA. Then translate both points by (5, 2) and check whether →AB changes.
Give me a hint
Calculate both new positions, then subtract them in the same direction.
Compare my reasoning
- Originally →AB = (6, −4)ᵀ and →BA = (−6, 4)ᵀ.
- The translated points are A′ = (3, 3) and B′ = (9, −1).
- B′ − A′ = (6, −4)ᵀ, so the common translation changes positions but preserves displacement.
→AB = (6, −4)ᵀ; →BA = (−6, 4)ᵀ; translated displacement remains (6, −4)ᵀ.
Look for these in your work
- Reverse the displacement by negating both components.
- Distinguish the changed positions from the unchanged displacement.
A survey uses x east, y north and z up, in metres. Markers M and N have positions (1, 2, 0.5) and (4, −2, 1.5). Find the displacement from M to N and the return displacement, and check the endpoint.
Give me a hint
Use the supplied coordinate frame and subtract M from N.
Compare my reasoning
- The outward displacement is (4 − 1, −2 − 2, 1.5 − 0.5) = (3, −4, 1) metres.
- The return displacement is (−3, 4, −1) metres.
- Adding (3, −4, 1) to M gives N; the negative north component means 4 metres south.
Outward (3, −4, 1) m; return (−3, 4, −1) m.
Look for these in your work
- Use the stated directions and units consistently.
- Verify the final position from the starting position plus displacement.
Common mistakes
- Keep x, y, z component order and subtract the starting position.
- Position and displacement have different meanings even when both are written as triples.
- Reverse every component when reversing the arrow.
What can you explain now?
Express 3i − 2j + k as a column vector.
Compare with the explanation
(3, −2, 1)ᵀ.
The three coefficients are the ordered x, y and z components.
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Make it stick
Write one vector in column and i, j, k notation. Explain the difference between a point's position and its displacement to another point, and check finish minus start.
If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.