Recognise when a binomial model is justified
Identify a fixed success count with independent trials and a constant success probability, and explain which assumption fails in counterexamples.
Section 5.4 · Discrete random variables
Exam scope and assessment notes
Probability & Statistics 1 (Paper 5, AS & A Level) · Mathematics 9709, 2026–2027, section 5.4. A probability table needs non-negative probabilities summing to one. E(X) is a probability-weighted mean; Var(X) = E(X²) − [E(X)]², with squared units. A binomial model B(n,p) counts successes in a fixed non-negative integer number n of independent two-outcome trials with a constant success probability p. A geometric model Geo(p) counts the trial of the first success, starting at 1, with independent trials and a constant 0 < p ≤ 1. Formula proofs are not required. The expectation of the geometric distribution is required; its variance is not required by section 5.4. Normal approximations belong to section 5.5 and are not used here. Exact model probabilities do not establish real-world independence or constant rates without evidence. Written practice is self-checked; human subject-teacher review remains pending.
Before you begin
- Distinguish independence from identical marginal probabilities.
- Define an indicator or count variable.
Work on paper. Try each question before revealing help, and explain why your method works.
Quick readiness check
What does X count in B(n,p)?
What you will learn
- State the four binomial modelling assumptions.
- Use B(n,p) notation and reject unsuitable trial mechanisms.
Count successes in a fixed experiment
X ~ B(n,p) means X counts successes in n independent trials with the same success probability p, with each trial classified as success or failure. n is a fixed non-negative integer and 0 ≤ p ≤ 1. The support is 0, 1, …, n; X records how many successes, rather than the trial on which the first success occurs.
For four stipulated independent trials with success probability 1/3 each, X ~ B(4,1/3). Calling an outcome ‘success’ is a mathematical classification: a chosen die result, a correct answer or a flagged item can be designated success. Define the event and justify the assumptions from the supplied mechanism, rather than assuming real students’ answers are independent and equally difficult.
A count alone is not enough
Drawing two balls without replacement from three red and two blue, with red called success, does not produce a binomial model: the later probability changes with the first draw and the trials are dependent. It still has a valid discrete distribution, which can be obtained by enumerating pairs or using a tree.
Three independent trials with success probabilities 1/2, 2/3 and 3/4 are not binomial because their probabilities are not constant. Independence alone is insufficient. A variable counting trials until success instead has a changing stopping time, so it does not have a fixed n; it may fit a geometric model under its own assumptions. Do not force a named model when its defining conditions fail.
Pause and explain
Two draws without replacement from three red and two blue: is the red count binomial?
Worked example
Four independent trials each have success probability 1/3. Define X and its distribution.
Show the worked solution
- Let X be the number of successful trials.
- There are four fixed trials, two outcome classifications, independence and common p = 1/3.
- Write X ~ B(4,1/3), with values 0–4.
Answer X ~ B(4,1/3); X counts successes, with support 0, 1, 2, 3, 4.
Try a topic test
Choose Easy, Normal or Difficult. Save your answers and open worked review after finishing.
Test this topic →From guided practice to a new situation
Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.
A stipulated model has ten independent trials, each with success probability 0.20. X counts successes. State the distribution and support.
Give me a hint
Check fixed count, two classifications, independence and common probability.
Compare my reasoning
- There are ten fixed trials with success/failure outcomes.
- Independence and constant p = 0.20 are supplied.
- Write X ~ B(10,0.20), with X = 0, 1, …, 10.
X ~ B(10,0.20); support 0–10.
Look for these in your work
- Define X as a success count.
- Identify all required assumptions.
Draw two balls without replacement from three red and two blue, counting red as success. Assess a binomial model.
Give me a hint
Compare the second red probability after a red with its probability after a blue.
Compare my reasoning
- After red, second red is 2/4; after blue, it is 3/4.
- The trial probabilities depend on the first result and are not constant.
- The red count is not binomial; use the without-replacement distribution instead.
Not binomial: dependence and changing success probability violate the model.
Look for these in your work
- Give specific conditional probabilities.
- Identify the failed assumptions rather than just naming the alternative.
Three trials are independent but have success probabilities 1/2, 2/3 and 3/4. X counts successes. Is X binomial? Find the all-success probability without assuming a binomial model.
Give me a hint
Independence allows a product but does not make the probabilities identical.
Compare my reasoning
- The constant-p requirement fails, so X is not binomial.
- Multiply the supplied independent success probabilities.
- P(all succeed) = (1/2)(2/3)(3/4) = 1/4.
Not binomial; all-success probability 1/4.
Look for these in your work
- Separate independence from a common probability.
- Use each trial’s actual probability in the product.
Common mistakes
- A success count needs all four model assumptions.
- Without replacement can destroy both independence and constant probability.
- A waiting-time variable has a different definition from a fixed-trial count.
What can you explain now?
Are independent trials with different success probabilities binomial?
Compare with the explanation
No; the constant-p condition fails.
Independence and identical success probability are separate assumptions.
After trying it yourself, choose your next review. This is your self-assessment.
Your review choice appears on Today. Sign in to sync it across devices.
Make it stick
Define the count and check fixed n, two classifications, independence and constant p before writing B(n,p).
If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.