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IGCSE · Cambridge (CIE) · 0606

Differentiate composite functions with the chain rule

Differentiate a function of a linear or inner expression by multiplying by the derivative of that inner expression.

Section 14 · Calculus

Cambridge IGCSE Additional Mathematics 0606 · 2028–2030 · Version 1 · 14

Cambridge IGCSE Additional Mathematics 0606, 2028–2030 syllabus, Version 1. Paper 1 is non-calculator; Paper 2 requires a scientific calculator. These original lessons provide self-checked topic practice, not a Cambridge grade or a timed paper. Full-paper assessment and human specialist review are still outstanding.

Before you begin

  • Cambridge assumes knowledge of IGCSE Mathematics or an equivalent course. Check the domain before using an inverse or logarithm, and retain exact values where the question asks for them.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

In the chain rule for F(g(x)), what extra factor appears?

What you will learn

  • Use the chain rule for composite functions
  • Differentiate powers and standard functions of ax + b
  • Keep radians in composite trigonometric functions

Differentiate the outside and multiply by the inside rate

If y = F(g(x)), then dy/dx = F′(g(x))g′(x). First differentiate the outer function while leaving the inner expression in place; then multiply by the derivative of the inner expression.

For y = (ax + b)ⁿ, dy/dx = an(ax + b)ⁿ⁻¹. For sin(ax + b), the derivative is a cos(ax + b); the factor a comes from differentiating the inside.

The same rule handles exponential, logarithmic and trigonometric forms

d(e^(ax+b))/dx = a e^(ax+b), d(ln(ax+b))/dx = a/(ax+b), and d(tan(ax+b))/dx = a sec²(ax+b), wherever each original function is defined.

For sin and cos of a composite angle, use radians and multiply by the inner derivative. Do not leave out a constant factor just because the inner expression is in brackets.

Pause and explain

Differentiate (2x + 1)³.

Put the idea to work

Worked example

Differentiate y = (3x − 2)⁵.

Show the worked solution
  1. Differentiate the outer fifth power to get 5(3x − 2)⁴.
  2. The inner derivative of 3x − 2 is 3.
  3. Multiply by the inner derivative.

Answer dy/dx = 15(3x − 2)⁴.

Try a topic test

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Differentiate y = √(5x + 1), writing the answer with a positive power if possible.

Give me a hint

Write the square root as a power and apply the chain rule.

Compare my reasoning
  1. y = (5x + 1)^(1/2).
  2. dy/dx = (1/2)(5x + 1)^(−1/2) × 5.
  3. Simplify the constant factor.

dy/dx = 5/[2√(5x + 1)].

Look for these in your work

  • Power rewritten
  • Inner derivative included
  • Equivalent form simplified
2 · Independent

Differentiate y = e^(3x−2) + ln(2x + 5).

Give me a hint

Apply the inner derivative to both terms and retain the logarithm's domain.

Compare my reasoning
  1. d(e^(3x−2))/dx = 3e^(3x−2).
  2. d(ln(2x+5))/dx = 2/(2x+5).
  3. The logarithm requires 2x + 5 > 0.

dy/dx = 3e^(3x−2) + 2/(2x + 5), for x > −5/2.

Look for these in your work

  • Exponential chain factor included
  • Logarithm chain factor included
  • Domain condition stated
3 · Transfer

Differentiate y = sin(2x + π/3) for x measured in radians.

Give me a hint

The outer derivative is cosine; multiply by the derivative of the angle.

Compare my reasoning
  1. The derivative of sin(u) is cos(u) du/dx.
  2. Here u = 2x + π/3 and du/dx = 2.
  3. Multiply by 2 and retain the original form.

dy/dx = 2 cos(2x + π/3).

Look for these in your work

  • Radians used
  • Inner angle differentiated
  • Chain factor included

Common mistakes

  • Forgetting the inner derivative
  • Expanding a large power before differentiating unnecessarily
  • Changing the inner expression while applying the outer rule
  • Using degree-mode trig derivatives
Recall without your notes

What can you explain now?

What is the derivative of sin(4x)?

Compare with the explanation

4 cos(4x)

Differentiate sine, then multiply by d(4x)/dx = 4.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

What are the two steps in the chain rule, and where does the inner derivative appear?

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Mathematics — Additional

Course scope and assessment

All 14 topics in the Cambridge IGCSE Additional Mathematics 0606 syllabus have mapped teaching: Functions, Quadratic functions, Factors of polynomials, Equations/inequalities/graphs, Simultaneous equations, Logarithmic and exponential functions, Straight-line graphs, Coordinate geometry of the circle, Circular measure, Trigonometry, Permutations and combinations, Series, Vectors in two dimensions, and Calculus. Lessons include guided, independent and application practice with explained answers. No full timed Paper 1 or Paper 2, Cambridge marking or human specialist review is provided; self-checks do not certify a grade.

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