State and interpret volts for electromotive force
Use volts as the e.m.f. unit and interpret a source label as joules supplied per coulomb rather than a fixed energy total.
Section 4.2.3 · Electromotive force and potential difference
Exam scope and assessment notes
Core and Extended · Physics 0972, 2026–2028. Use the stated source, operating conditions and meter ranges. Written practice is self-checked. Human subject-teacher review, supervised practical competence and cumulative assessment remain pending. Cambridge states that IGCSE 0972 has the same subject content as IGCSE 0625, with 9–1 grading. This StudyForA pathway maps the 2026–2028 syllabus only. This 9–1 graded qualification is available only in a limited number of administrative zones. Confirm that your centre can enter you for this code and exam series with Cambridge International. Cambridge has published a separate syllabus for 2029. StudyForA has not reconciled that version yet; this page supports exams in 2026, 2027 and 2028 only.
Before you begin
- Define e.m.f. as source work per unit charge.
- Recognise joules and coulombs.
Work on paper. Try each question before revealing help, and explain why your method works.
Quick readiness check
Which unit names an energy transfer?
What you will learn
- State volts as the e.m.f. unit.
- Interpret energy-per-charge source labels without treating them as total energy.
Interpret the volt
Electromotive force is measured in volts, symbol V. One volt means one joule of electrical work per coulomb of charge in the stated source account. A 6 V e.m.f. label means 6 J supplied for each 1 C, not a mechanical force of 6 N or a current of 6 A.
The numerical label is a per-charge quantity. It does not say the source contains only 6 J, or that 6 J is supplied regardless of the charge that passes. A capacity or passed-charge amount is different information. Prefixes such as mV change the voltage scale, not the physical quantity.
Read the label with its context
A source label may give a nominal value rather than an exact measurement under every operating condition. For comparisons in this lesson, use the stated e.m.f. values and conditions. Numerical work–charge calculations belong to the Supplement sequence; the Core task here is to identify and interpret the unit.
Distinguish volts from joules, coulombs and amperes. Joules describe work or energy, coulombs charge, and amperes current. In a complete explanation name which quantity is given rather than presenting a naked number. A source label alone does not prove a particular circuit current or appliance power.
Pause and explain
A stated e.m.f. of 9 V means what for each 1 C?
Worked example
Interpret a stated source e.m.f. of 6 V for a unit charge.
Show the worked solution
- E.m.f. is measured in volts.
- A volt means a joule per coulomb.
- For each 1 C, the stated source account supplies 6 J.
Answer 6 J of source electrical work per 1 C.
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Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.
State the e.m.f. unit and interpret a 6 V source for each 1 C.
Give me a hint
Translate volts into the stated source work per unit charge.
Compare my reasoning
- The e.m.f. unit is V.
- 1 V means 1 J per C.
- 6 V means 6 J per 1 C in the source account.
Volts; 6 J of source work per 1 C.
Look for these in your work
- Name volts.
- Keep the per-charge wording.
Explain the difference between source labels of 3 V and 9 V without assigning a circuit current.
Give me a hint
Compare their stated work per unit charge only.
Compare my reasoning
- 3 V corresponds to 3 J per C.
- 9 V corresponds to 9 J per C.
- Neither label alone determines the path's current.
They supply different source work per coulomb; current is not determined by either label alone.
Look for these in your work
- Compare like quantities.
- Avoid an unprovided current.
A learner says 'a 6 V source has exactly 6 J of total energy'. Correct the interpretation.
Give me a hint
Distinguish a per-charge value from a total source capacity.
Compare my reasoning
- The 6 V label means work per coulomb.
- A total energy needs additional charge or capacity information.
- The fixed 6 J total does not follow.
6 V means 6 J per C; the source's total energy is not given.
Look for these in your work
- Identify the missing amount information.
- Do not turn a voltage label into a fixed energy total.
Common mistakes
- Use V rather than N or A.
- A voltage label is not a fixed total joule amount.
- A nominal label is not every possible operating measurement.
What can you explain now?
What unit is used for e.m.f.?
Compare with the explanation
Volt (V).
The volt expresses electrical work per unit charge.
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Make it stick
State volts and explain source work per coulomb while keeping total charge and energy separate.
If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.