Define and calculate force per unit area
Use the normal contact force and actual area to calculate average pressure in pascals.
Section P1.8 · Pressure
Exam scope and assessment notes
Mapped to the named 0973 section using teaching from the corresponding single-science course. A 0973-specific review of every Core and Supplement objective is still in progress. Written practice is self-checked; it does not demonstrate supervised laboratory competence or award an official Cambridge grade. This qualification reports two grades on the 9–1 scale; confirm the entry route for your zone and exam series.
Before you begin
- Measure force in newtons.
- Distinguish an area from a length or a volume.
Work on paper. Try each question before revealing help, and explain why your method works.
Quick readiness check
Which unit measures an area?
What you will learn
- Define pressure as force per unit area and recall p = F/A.
- Identify the force acting normally on the chosen contact area.
Pressure spreads a force over an area
Pressure is force per unit area: p = F/A. For a flat contact in this model, F is the force pushing normally, or perpendicularly, on the stated area A. Use newtons and square metres to obtain pascals, where 1 Pa = 1 N/m². A normal 120 N force spread over 0.0060 m² gives 120/0.0060 = 20 000 Pa, or 20 kPa.
This quotient gives average pressure across the stated contact. Local pressure need not be uniform if a real surface is uneven. A force alone is not a pressure, and a width alone is not an area. Do not put a sideways force into a normal-pressure calculation or assume that the whole visible object touches the surface.
Choose the contact and force together
A standing person's total downward contact force can equal their weight in a simple steady model with no other vertical support. If two feet share the contact, use the combined area with the combined force, or each foot's share with its own area. Giving each foot the whole weight and then adding those pressures would not describe the same account.
When another support carries some weight, the contact of interest need not carry the full weight. Identify the named contact force from the supplied balance before using its area. A larger mass is relevant only after converting it into the appropriate force using supplied gravitational field strength and support conditions.
Sources for this lesson
Pause and explain
Can a sideways force alone be used as the normal force on a flat horizontal contact?
Worked example
A flat contact carries a normal 120 N force over 0.0060 m². Find average pressure.
Show the worked solution
- Identify F = 120 N and A = 0.0060 m².
- Use p = F/A = 120/0.0060.
- The result is 20 000 N/m² = 20 000 Pa = 20 kPa.
Answer 20 000 Pa or 20 kPa.
Try a topic test
Choose Easy, Normal or Difficult. Save your answers and open worked review after finishing.
Test this topic →From guided practice to a new situation
Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.
Calculate average pressure for 120 N acting normally over 0.0060 m².
Give me a hint
Divide the specified normal force by its contact area.
Compare my reasoning
- Force is 120 N.
- Area is 0.0060 m².
- p = 120/0.0060 = 20 000 Pa.
20 000 Pa.
Look for these in your work
- Use force per area.
- State the pressure unit.
Find pressure for 0.40 kN over 0.020 m²; then explain whether a total 600 N on two feet with combined contact area 0.030 m² gives the same pressure.
Give me a hint
Convert the force prefix and keep each total force with its total area.
Compare my reasoning
- 0.40 kN = 400 N, so 400/0.020 = 20 000 Pa.
- The two-foot total gives 600/0.030 = 20 000 Pa.
- The supplied totals give equal average pressures.
20 000 Pa in both cases.
Look for these in your work
- Convert kilonewtons.
- Match total force and total area.
A 600 N load is partly supported elsewhere, leaving 200 N on a contact of area 0.010 m². A calculation uses the whole 600 N. Correct it.
Give me a hint
Use the force actually assigned to the contact of interest.
Compare my reasoning
- The named contact carries 200 N.
- Pressure is 200/0.010 = 20 000 Pa.
- 600/0.010 would incorrectly assign the other support's share to this contact.
20 000 Pa; use 200 N, not the whole 600 N.
Look for these in your work
- Identify the stated support share.
- Keep the pressure calculation tied to its contact.
Common mistakes
- Use area, not width or volume.
- Use the force on the named contact.
- Average pressure need not describe every local point.
What can you explain now?
What does 1 Pa mean?
Compare with the explanation
1 N per square metre.
A pascal is the pressure associated with one newton per square metre.
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Make it stick
Define pressure and the pascal, calculate an average, and identify the actual normal contact force and area.
If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.