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IGCSE · Cambridge (CIE) · 0980

Arc lengths and sector boundaries

Take the correct fraction of a circle and include straight edges when finding a sector perimeter.

Section Paper 3 · Core · Calculator

Mensuration pathway · Cambridge 0980 (9–1) · C5.3 / E5.3

Core and Extended. Core sector angles are factors of 360°. Extended uses general angles and includes minor and major sectors; the major-sector transfer task below is Extended. This is the separate 9–1 qualification 0980. Cambridge intends Core for grades 4–1 and Extended for grades 9–5; the eligible award bands are grades 5–1 for the Core papers and grades 9–3 for the Extended papers.

Before you begin

  • Use circle circumference and area.
  • Simplify fractions of 360°.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

What fraction of a full turn is 90°?

What you will learn

  • Calculate arc length and sector area.
  • Distinguish minor and major sectors and their boundaries.
120°r = 6arc 4πOFull perimeter = 4π + 12
A 120° sector of radius 6 has arc length 4π and area 12π. The entire boundary includes two radii, so perimeter is 4π + 12. Sketch not to scale.

The central angle determines the fraction

A sector of central angle θ occupies θ/360 of a complete circle. Its arc length is (θ/360) × 2πr and its area is (θ/360) × πr². For radius 6 cm and angle 120°, the fraction is one third, giving arc 4π cm and area 12π cm². Arc length and sector area share a fraction but use different full-circle measures.

A minor sector uses the smaller central angle; the complementary major sector uses 360° minus that angle. Extended questions may use angles that do not divide 360 neatly. Retain the exact fraction and pi until the last calculation. A chord-bounded segment has a different area from a sector and needs subtraction of the enclosed triangle when applicable.

Trace every boundary edge

A sector's full perimeter is its curved arc plus two radii: L + 2r. For the 120° sector above it is 4π + 12 cm. A semicircle has curved length πr and perimeter πr + 2r. Do not take a fraction of the full circumference and call that the complete perimeter of the cut-out piece.

For a major sector, the same two radii form the straight edges, while the longer arc follows the major angle. In a joined compound shape, some of these straight edges may become internal and should be omitted from the outside perimeter. Mark the exposed boundary before adding lengths.

arc L = θ/360 × 2πr; sector A = θ/360 × πr²; perimeter = L + 2r

Pause and explain

A 90° sector has radius 8 cm. What is its full perimeter?

Put the idea to work

Worked example

Find the exact arc length, area and perimeter of a 120° sector with radius 6 cm.

Show the worked solution
  1. The fraction is 120/360 = 1/3, so arc length is (1/3) × 12π = 4π cm.
  2. Area is (1/3) × 36π = 12π cm².
  3. Add two radii for perimeter: 4π + 12 cm.

Answer Arc 4π cm; area 12π cm²; perimeter (4π + 12) cm.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Find arc length and area of a 90° sector of radius 8 cm.

Give me a hint

Use one quarter of each full-circle measure.

Compare my reasoning
  1. Circumference is 16π cm, so the arc is 4π cm.
  2. Circle area is 64π cm², so sector area is 16π cm².
  3. Differentiate the length and area units.

4π cm; 16π cm².

Look for these in your work

  • Used the same quarter fraction.
  • Applied it to the correct full-circle measures.
2 · Independent

A semicircle has radius 5 cm. Find its area and full perimeter.

Give me a hint

The diameter remains on the cut edge.

Compare my reasoning
  1. Area is half of 25π, or 25π/2 cm².
  2. The curved arc is 5π cm.
  3. Add the 10 cm diameter: perimeter is 5π + 10 cm.

Area 25π/2 cm²; perimeter (5π + 10) cm.

Look for these in your work

  • Halved the circular area.
  • Included the straight diameter edge.
3 · Transfer

Extended: a circle of radius 10 cm has a minor sector angle 72°. Find the remaining major sector's area and perimeter.

Give me a hint

The remaining angle is 360° − 72°.

Compare my reasoning
  1. The major angle is 288°, fraction 4/5.
  2. Its area is (4/5) × 100π = 80π cm².
  3. Its arc is (4/5) × 20π = 16π cm; add two radii to give 16π + 20 cm.

Area 80π cm²; perimeter (16π + 20) cm (Extended).

Look for these in your work

  • Used the major angle.
  • Included exposed radius edges.

Common mistakes

  • Confusing an arc with a full perimeter.
  • Using the minor angle for a major sector.
  • Applying circumference units to sector area.
Recall without your notes

What can you explain now?

What must be added to a sector arc to obtain its full perimeter?

Compare with the explanation

Two radii.

The sector boundary contains the curved arc and both straight lines from its endpoints to the centre.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

Tomorrow, trace and label the boundary of a sector before calculating. Explain which edges count.

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Mathematics (9-1)

Course scope and assessment

StudyForA maps the 72 Core and Extended section entries in Cambridge IGCSE Mathematics (9–1) 0980 to original teaching and staged practice. This route covers the 2025–2027 syllabus and the 2028–2030 Version 2 syllabus; Cambridge says the 2028 update makes no significant changes affecting teaching, while its assessment overview is updated. The course keeps the 9–1 grading and paper rules separate from 0580. Questions and written work are self-checked, not Cambridge-graded; this is not a timed mock or an official grade, and subject-teacher review remains pending. 0980 is available in June and November in Administrative Zone 3 and for centres in Oman and the UAE. Confirm the exam series and your centre's entry eligibility with Cambridge and your exams officer.

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