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A Level · Cambridge (CIE) · 9701

Translate organic structural and displayed formulas

Read condensed structural and displayed formulas by preserving atom connectivity and functional-group attachment.

Section 29 · An introduction to A Level organic chemistry

An introduction to A Level organic chemistry · Cambridge International Chemistry 9701 · 29.1

A Level; Cambridge International Chemistry 9701, 2028–2030 syllabus, Topic 29. Follow the formula, naming and optical-isomerism limits stated in the syllabus. Benzene-ring displayed formulas are not expected; use the supplied convention for aromatic skeletal formulas. Do not extend the optical-isomerism scope to naming diastereoisomers or meso compounds. Written practice is self-checked

Before you begin

  • Use covalent formula conventions, functional groups, reaction terminology, and the AS organic chemistry foundations.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

What does a displayed formula make explicit?

What you will learn

  • Distinguish general, structural and displayed formulas
  • Read atom connectivity from condensed groups
  • Check valency and functional-group attachment when translating formulas

Each formula representation carries different detail

A general formula describes a pattern for a family; a structural formula shows how atoms or groups are connected in a condensed form; a displayed formula shows individual atoms and bonds. They can represent the same molecule at different levels of detail.

Translate by preserving connections. In CH₃CH₂COCl, the carbonyl carbon is bonded to CH₂ and Cl. Writing CH₃COCH₂Cl instead changes the connectivity and produces a different class of compound.

Use valency as a check

Carbon normally forms four covalent bonds, oxygen two and hydrogen one in these neutral structures. Nitrogen bonding depends on its class; check the number of carbon groups and hydrogens rather than assuming all nitrogen compounds are alike.

For aromatic molecules, Cambridge does not expect benzene-ring displayed formulas to be drawn. Use the convention given for the ring and show the attached substituents clearly.

Pause and explain

In CH₃CH₂COCl, which group is bonded to the carbonyl carbon besides chlorine?

Put the idea to work

Worked example

Interpret CH₃CH₂COCl and state which atoms are connected to the carbonyl carbon.

Show the worked solution
  1. Identify the COCl ending as C(=O)Cl.
  2. The carbonyl carbon is preceded by CH₂ and bonded to Cl.
  3. The structure is CH₃–CH₂–C(=O)–Cl.

Answer The carbonyl carbon is bonded to the ethyl group and to chlorine; the molecule is propanoyl chloride.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Write a clear condensed structural formula for butanoyl chloride and identify its functional group.

Give me a hint

Use a four-carbon chain ending in –C(=O)Cl.

Compare my reasoning
  1. Count four carbons including the carbonyl carbon.
  2. Place the carbonyl at the end of the chain.
  3. Attach Cl to the carbonyl carbon.

CH₃CH₂CH₂COCl; it is an acyl chloride.

Look for these in your work

  • Four carbons counted
  • Connectivity preserved
  • Functional group named
2 · Independent

A student writes CH₃CH₂COCH₃ for butanoyl chloride. What is wrong with the formula?

Give me a hint

Compare the formula's carbonyl neighbours with the required –COCl group.

Compare my reasoning
  1. The written formula has carbon groups on both sides of C=O.
  2. It contains no chlorine.
  3. It is a ketone pattern, not an acyl chloride.

It is a ketone-like structure with no chlorine; butanoyl chloride should be CH₃CH₂CH₂COCl.

Look for these in your work

  • Connectivity checked
  • Missing Cl identified
  • Correct pattern supplied
3 · Transfer

Translate the condensed part –CONHCH₃ into a connectivity description and classify it.

Give me a hint

Expand the carbonyl and identify the group bonded directly to its carbonyl carbon.

Compare my reasoning
  1. Write –C(=O)–NH–CH₃.
  2. Nitrogen is bonded to the carbonyl carbon and carries one H and one methyl group.
  3. That is a secondary amide.

The sequence is –C(=O)–NH–CH₃; it is a secondary amide because N is bonded to the acyl carbon, one methyl group and one H.

Look for these in your work

  • Carbonyl expanded
  • N substituents identified
  • Amide class correctly assigned

Common mistakes

  • Reordering groups and changing which atoms are bonded
  • Treating a condensed formula as a molecular formula
  • Adding a benzene displayed formula when the syllabus does not expect it
  • Forgetting carbon valency when checking a translated formula
Recall without your notes

What can you explain now?

What does a displayed formula make explicit?

Compare with the explanation

The atoms and the bonds between them

A displayed formula shows individual atoms and their connections.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

How can you check that translating a condensed formula has preserved the molecule rather than changed its connectivity?

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Chemistry

Course scope and assessment

Four hundred and forty-two original lessons map the published learning outcomes across AS Chemistry Topics 1–22 and A Level Topics 23–37, with guided, independent and transfer practice and explained answers. Every numbered subject-content topic and listed outcome tag now has a mapped lesson sequence. Topic 32 maps all 12 hydroxy-compound outcome tags in 11 lessons; Topic 33 maps all 15 carboxylic-acid and derivative outcome tags in 16 lessons; Topic 34 maps all 22 nitrogen-compound outcome tags in 20 lessons; Topic 35 maps all 12 polymerisation outcome tags in 16 lessons; Topic 36 maps all four organic-synthesis outcome tags in 14 lessons; Topic 37 maps all 22 chromatography and NMR outcome tags in 18 lessons. Cambridge's 2028–2030 Version 1 syllabus states that there are no significant changes which affect teaching from the preceding edition; the routes are aligned to that edition. This is 37 of the 37 numbered subject-content topics. Full cumulative exam assessment, Paper 3 laboratory competence, Paper 5 investigation practice and human subject-teacher review remain outstanding. Written practice is self-checked and does not certify exam readiness.

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