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A Level · Cambridge (CIE) · 9702

Describe molecular internal energy

Treat internal energy as a property of the system's state and identify its molecular kinetic- and potential-energy contributions.

Section 16 · Thermodynamics

Thermodynamics · Cambridge International AS & A Level Physics 9702 · 16.1

A Level; Cambridge International Physics 9702, 2025–2027 syllabus, Topic 16. These original explanations and calculations are study aids; full timed assessment and human subject-teacher review remain outstanding.

Before you begin

  • Use temperature, molecular kinetic energy, pressure, volume and energy-transfer conventions.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

What does internal energy include in the molecular model?

What you will learn

  • Understand internal energy as determined by the state of a system
  • Express internal energy as the sum of molecular kinetic and potential energies
  • Distinguish molecular internal energy from the motion of the system as a whole

Internal energy belongs to the state of the system

The internal energy U of a system is determined by its state. For a material, it is the sum of the random kinetic energies of its molecules and the potential energies associated with interactions between those molecules.

Internal energy is a microscopic energy store. It is distinct from the kinetic energy of the whole object moving through the room and from its gravitational potential energy in an external field.

Molecular motion and arrangement both matter

Random molecular motion contributes kinetic energy; intermolecular separation and arrangement contribute potential energy. Changing the state can change these contributions even when the system is not moving as a whole.

Use the system boundary consistently. Energy transferred across that boundary can change U, while the internal energy itself describes the microscopic state inside it.

U = total random molecular kinetic energy + intermolecular potential energy

Pause and explain

A stationary gas has internal energy because its molecules move randomly and interact. Which statement is correct?

Put the idea to work

Worked example

A sealed gas sample is stationary in a container. Identify the contributions to its internal energy and one energy store that is not part of this internal energy.

Show the worked solution
  1. Consider molecular motion and interactions inside the gas.
  2. Name the two microscopic contributions.
  3. Distinguish energy of the sample as a whole.

Answer Internal energy is the sum of random molecular kinetic and intermolecular potential energies. The kinetic energy of the whole container moving as one object is not part of this internal energy.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

State the two molecular contributions summed to give the internal energy of a substance.

Give me a hint

Consider molecular motion and interactions between molecules.

Compare my reasoning
  1. Random molecular motion contributes kinetic energy.
  2. Molecular interactions and arrangement contribute potential energy.
  3. The sum of these microscopic energies is internal energy.

Internal energy is the sum of random molecular kinetic energy and intermolecular potential energy.

Look for these in your work

  • Kinetic contribution stated
  • Potential contribution stated
  • Sum identified
2 · Independent

A moving cart contains a warm gas in a sealed canister. Distinguish the gas's internal energy from the cart's motion.

Give me a hint

Separate microscopic motion within the gas from bulk motion of the whole system.

Compare my reasoning
  1. Internal energy describes random molecular kinetic and intermolecular potential energies.
  2. Cart motion is the centre-of-mass kinetic energy of the object as a whole.
  3. These are distinct energy stores.

The gas's U is microscopic; the cart's bulk kinetic energy is a separate macroscopic store.

Look for these in your work

  • Microscopic scale identified
  • Bulk motion identified
  • Energy stores distinguished
3 · Transfer

Two samples have the same chemical substance but different states. Explain why their internal energies need not be equal.

Give me a hint

Compare molecular motion and arrangement in the two states.

Compare my reasoning
  1. Internal energy is determined by the system's state.
  2. The states can have different molecular kinetic-energy distributions or intermolecular potential energies.
  3. Their total microscopic energies can therefore differ.

Different states can have different molecular energy contributions, so their internal energies need not match.

Look for these in your work

  • State dependence recalled
  • Molecular contributions compared
  • Conclusion follows

Common mistakes

  • Including the centre-of-mass motion of the entire object in internal energy
  • Describing internal energy as kinetic energy only
  • Treating internal energy as a substance label rather than a state property
Recall without your notes

What can you explain now?

What does internal energy include in the molecular model?

Compare with the explanation

Random molecular kinetic and intermolecular potential energies

Both molecular motion and interaction energy contribute.

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Make it stick

Which microscopic energy contributions make up a system's internal energy?

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Physics

Course scope and assessment

One hundred and sixty-two original lessons cover all 12 published subject-content outcomes in Topic 1 (sections 1.1–1.4), all nine outcomes in Topic 2 (section 2.1), all 13 outcomes in Topic 3 (sections 3.1–3.3), all 13 outcomes in Topic 4 (sections 4.1–4.3), all 11 outcomes in Topic 5 (sections 5.1–5.2), all 10 outcomes in Topic 6 (sections 6.1–6.2), all 16 outcomes in Topic 7 (sections 7.1–7.5), all 12 outcomes in Topic 8 (sections 8.1–8.4), all 15 outcomes in Topic 9 (sections 9.1–9.3), all 16 outcomes in Topic 10 (sections 10.1–10.3), all 18 outcomes in Topic 11 (sections 11.1–11.2), all seven outcomes in Topic 12 (sections 12.1–12.2), all 12 outcomes in Topic 13 (sections 13.1–13.4), all eight outcomes in Topic 14 (sections 14.1–14.3), and all nine outcomes in Topic 15 (sections 15.1–15.3), plus all four outcomes in Topic 16 (sections 16.1–16.2), and all ten outcomes in Topic 17 (sections 17.1–17.3), plus all 12 outcomes in Topic 18 (sections 18.1–18.5), all nine outcomes in Topic 19 (sections 19.1–19.3), all 19 outcomes in Topic 20 (sections 20.1–20.5), and all eight outcomes in Topic 21 (sections 21.1–21.2), and all 17 outcomes in Topic 22 (sections 22.1–22.4), and all 13 outcomes in Topic 23 (sections 23.1–23.2), and all 16 outcomes in Topic 24 (sections 24.1–24.3), and all 11 outcomes in Topic 25 (sections 25.1–25.3), of the 2025–2027 syllabus. Each lesson has guided, independent and application practice with explained answers. All 25 syllabus topics now have mapped teaching and practice; the 2028–2030 changes outside Topics 23–25 still need reconciliation. Online study cannot demonstrate supervised Paper 3 laboratory competence. Paper 5 planning and analysis, full timed cumulative assessment and human subject-teacher review remain outstanding.

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