Use trigonometric identities to expose integrable terms
Rewrite squared sines, squared cosines, products and tangent squares before applying the standard primitives.
Section 3.5 · Integration
Exam scope and assessment notes
Pure Mathematics 2 (Paper 2, AS only) and Pure Mathematics 3 (Paper 3, A Level) · Mathematics 9709, 2026–2027. Shared sections 2.5 and 3.5 use these standard exponential, reciprocal and trigonometric integrals and identity methods. Paper 1 integration and the shared derivatives and identities are assumed. The AS route using Papers 1 + 2 cannot be carried forward to A Level. The general method of integration by substitution is not required for Paper 2; Paper 3 uses given substitutions in its separate lesson. Paper 3 also adds positive-quadratic reciprocals, partial fractions, logarithmic derivative patterns and integration by parts. Use radians for trigonometric calculus. Written practice is self-checked; human subject-teacher review remains pending.
Before you begin
- Use double-angle identities and tan² u = sec² u − 1.
- Integrate linear trigonometric composites in radians.
Work on paper. Try each question before revealing help, and explain why your method works.
Quick readiness check
Which identity rewrites cos² u?
What you will learn
- Use double-angle and reciprocal identities to rewrite a trigonometric integrand.
- Check the transformed primitive and evaluate exact positive or signed integrals.
Change the integrand before trying to reverse differentiation
The identity sin² u = (1 − cos 2u)/2 and its companion cos² u = (1 + cos 2u)/2 turn a square into a constant and a directly integrable cosine. For example, cos² 2x = (1 + cos 4x)/2, so its primitive is x/2 + sin 4x/8 + C. The angle doubles as well as the original coefficient being halved. Differentiating this primitive gives (1 + cos 4x)/2 = cos² 2x.
Similarly, sin² 3x integrates to x/2 − sin 6x/12 + C. It is incorrect to use a power-rule guess such as sin³ 3x/3: differentiating that guess introduces both a cosine factor and an inner scale. The useful identity lets us use reverse differentiation without requiring the general substitution method in this section. For ∫cos² 2x from 0 to π/4, the sine term is zero at both endpoints, leaving exact area π/8.
Choose a relationship that gives standard derivative forms
Since sin 2x = 2 sin x cos x, a product sin x cos x can be replaced by sin 2x/2. Thus 2 sin x cos x integrates to −cos 2x/2 + C. The identity tan² u = sec² u − 1 gives ∫tan² 2x dx = tan 2x/2 − x + C on intervals with cos 2x ≠ 0. Rewriting does not remove any original tangent exclusions.
A non-negative integrand such as sin² x has equal signed integral and geometric area. Over [0, π], its primitive x/2 − sin 2x/4 gives π/2. A trigonometric product may change sign on another interval, so do not assume its definite integral is total area merely because an identity simplified it. Check the original sign and boundaries before giving a geometric or contextual interpretation.
Pause and explain
Which primitive integrates cos² 2x?
Worked example
Find ∫cos² 2x dx and evaluate its integral from 0 to π/4.
Show the worked solution
- Use cos² 2x = (1 + cos 4x)/2.
- Integrate the two terms to obtain x/2 + sin 4x/8 + C and verify by differentiation.
- At both definite endpoints the sine term vanishes, giving π/8; the squared cosine is non-negative, so this is also area.
Answer x/2 + sin 4x/8 + C; exact integral and area on [0, π/4] are π/8.
Try a topic test
Choose Easy, Normal or Difficult. Save your answers and open worked review after finishing.
Test this topic →From guided practice to a new situation
Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.
Evaluate ∫ from 0 to π of sin² x dx exactly.
Give me a hint
Rewrite the square as a constant minus a doubled-angle cosine.
Compare my reasoning
- Use sin² x = (1 − cos 2x)/2.
- A primitive is x/2 − sin 2x/4.
- Both endpoint sine terms vanish, leaving π/2; the non-negative integrand makes this an area too.
π/2, also the geometric area on [0, π].
Look for these in your work
- Use the sine-square identity with the correct sign.
- Evaluate exact radian endpoints and check the integrand's sign.
Find ∫tan² 2x dx and state the original restriction.
Give me a hint
Use tan² 2x = sec² 2x − 1 before integrating.
Compare my reasoning
- The original tangent square requires cos 2x ≠ 0.
- Integrate sec² 2x to tan 2x/2 and the constant −1 to −x.
- Add C; differentiation gives sec² 2x − 1 = tan² 2x on each valid interval.
(1/2)tan 2x − x + C, with cos 2x ≠ 0.
Look for these in your work
- Use a valid reciprocal identity before integrating.
- Retain the original poles after checking the primitive.
A supplied velocity is v(t) = 2 sin t cos t cm/s for 0 ≤ t ≤ π/2 seconds, with radian phase. Find the displacement change.
Give me a hint
Use the double-angle product identity to recognise a standard sine integrand.
Compare my reasoning
- Rewrite the velocity as sin 2t.
- A displacement primitive is −cos 2t/2.
- Endpoint subtraction gives 1/2 − (−1/2) = 1 cm.
Displacement change 1 cm.
Look for these in your work
- Transform the original product using a correct identity.
- Reverse the doubled angle and evaluate the signed displacement with units.
Common mistakes
- A squared sine or cosine cannot be integrated by an unchanged power-rule guess.
- Double the complete angle and reverse its new inner coefficient.
- Keep tangent domain exclusions and distinguish signed accumulation from area.
What can you explain now?
Rewrite sin² 3x in a form with standard primitives.
Compare with the explanation
(1 − cos 6x)/2.
The sine-square identity doubles the inner angle 3x to 6x.
After trying it yourself, choose your next review. This is your self-assessment.
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Make it stick
Choose an identity for a sine square, cosine square, sine-cosine product and tangent square. Differentiate each resulting primitive to check the inner factor and sign.
If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.