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IGCSE · Cambridge (CIE) · 0444

Add compound volumes and omit internal joining faces

Add volumes of non-overlapping joined solids · Identify surfaces hidden at a join · Distinguish a closed hemisphere from its exposed curved half

Section Paper 4 · Historical Extended · calculator

Mathematics (US) 0444 · historical 2025 study · E6.5
Exam scope and assessment notes

Extended content; not a Core requirement. Historical study of Cambridge IGCSE Mathematics (US) 0444, 2025 Version 2. The final assessment was June 2025; the syllabus was available only to schools in Arizona, USA. This is not a current exam-entry option. Original self-check teaching and explained practice are not Cambridge papers, official marks or predicted grades. Linked teaching foundations do not establish full syllabus mastery. Calibrated cumulative assessment, reliable drawn-work review and qualified mathematics-teacher review remain unfinished.

Before you begin

  • Cylinder and sphere formulae
  • Surface face accounting

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

What should you establish before applying the method in this lesson?

What you will learn

  • Add volumes of non-overlapping joined solids
  • Identify surfaces hidden at a join
  • Distinguish a closed hemisphere from its exposed curved half
The joining face is internaljoin is internalr = 3 cmh = 5 cmBottom disk remains exposed
An axial section shows a radius-3 cm cylinder of height 5 cm joined to a hemisphere of the same radius. The dashed joining disk is internal. The curved cylinder, curved hemisphere and bottom disk form the exterior, with area 57π cm²; the combined volume is 63π cm³. Use three-dimensional formulae rather than measuring this two-dimensional outline.

Separate volume from exposed area

A cylinder joined to a hemisphere of the same radius has volume πr²h+(2/3)πr³: the hemisphere is half the sphere volume. The pieces meet at one circular interface without overlapping volumes. If their interiors overlap, simply adding complete volumes would double count that overlap.

The interface is internal

For an exterior coating, include the cylinder curved surface 2πrh, the hemisphere curved surface 2πr² and the exposed bottom disk πr². Omit both copies of the joining disk. The exterior total is 2πrh+3πr². A standalone closed hemisphere would include its own flat circular base; joining it hides that base.

The radius-3 cm cylinder of height 5 cm with hemispherical cap has total volume 63π cm³ and exposed area 57π cm². The illustration is an axial section; use the three-dimensional formulae rather than the area of its outline.

Sources for this lesson

Pause and explain

How many copies of the joining disk remain on the exterior of the joined solid?

Put the idea to work

Worked example

Find volume and exposed area of the illustrated cylinder with hemispherical cap, r=3 cm and cylinder h=5 cm.

Show the worked solution
  1. Volume=45π+18π=63π cm³.
  2. Exterior area=30π+18π+9π=57π cm².

Answer 63π cm³; 57π cm².

Try a topic test

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

A cylinder r=3 cm, h=5 cm has a hemispherical cap of radius 3 cm. Find the total volume.

Give me a hint

Add the full cylinder to half a sphere.

Compare my reasoning
  1. Cylinder=45π cm³; cap=(2/3)π×27=18π cm³.
  2. Total=63π cm³.

63π cm³.

Look for these in your work

  • Use half the sphere volume
  • Avoid overlapping regions
2 · Independent

Find that solid's exposed area, including the cylinder bottom.

Give me a hint

Keep the curved parts and one exposed disk.

Compare my reasoning
  1. Cylinder curve=30π cm²; cap curve=18π cm².
  2. Bottom=9π cm²; total=57π cm².

57π cm².

Look for these in your work

  • Omit the hidden interface
  • Include the exposed bottom
3 · Transfer

Adding the areas of a closed cylinder and a closed hemisphere gives 75π cm² for this model. Explain how to correct it.

Give me a hint

Each closed piece includes a joining disk of area 9π.

Compare my reasoning
  1. Remove both internal disk copies: 2×9π=18π cm².
  2. 75π−18π=57π cm².

Subtract 18π cm² to obtain 57π cm².

Look for these in your work

  • Explain double counting
  • Check the exposed-face sum

Common mistakes

  • Two complete surface-area formulae include the joining disk twice.
  • Do not use a section outline as a 3D surface area.
Recall without your notes

What can you explain now?

How many copies of the joining disk remain on the exterior of the joined solid?

Compare with the explanation

None.

Both contacting disk faces are internal.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

How many copies of the joining disk remain on the exterior of the joined solid?

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Mathematics (US)

Course scope and assessment

191 original lessons provide 573 guided, independent and application tasks. All 142 tier entries have linked teaching foundations: 55 Core and 87 Extended entries across 87 unique numbered sections in ten areas. Extended includes Core, so the tier-entry count is not a percentage of teaching time or student mastery. This is not full programme completion: qualified mathematics-teacher review, cumulative and exam-length assessment, and reliable drawn-work review remain unfinished. Historical study of Cambridge IGCSE Mathematics (US) 0444, 2025 Version 2. The final assessment was June 2025; the syllabus was available only to schools in Arizona, USA. This is not a current exam-entry option. Original self-check teaching and explained practice are not Cambridge papers, official marks or predicted grades. Linked teaching foundations do not establish full syllabus mastery. Calibrated cumulative assessment, reliable drawn-work review and qualified mathematics-teacher review remain unfinished.

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