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IGCSE · Cambridge (CIE) · 0653

Calculate current from charge passing a point

Use I = Q/t with consistent coulombs and seconds and keep the chosen point and averaging interval explicit.

Section P4.1 · Electrical quantities

Electrical quantities · Cambridge IGCSE Combined Science 0653 · P4.1

Cross-referenced to the 2028–2029 0653 section using original teaching from the related single-science courses. A 0653-specific objective-by-objective and Core/Supplement review is in progress. Written practice is self-checked and does not demonstrate supervised laboratory competence or award an official Cambridge grade.

Before you begin

  • Use coulombs and time conversions.
  • Distinguish current from a total transferred charge.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

What is 18 mC in coulombs?

What you will learn

  • Define current as charge passing a point per unit time.
  • Calculate current with consistent charge and time units.
Original interval account uses 12 C passing a point over 4 s to give average current 3 A. It does not establish constant instantaneous current. Charge, time and rate are distinct quantities.Charge passing a pointQ = 12 CInterval t = 4 sI = Q / tAverage I = 3 AAverage does not provea constant instantaneous rate
Original interval account uses 12 C passing a point over 4 s to give average current 3 A. It does not establish constant instantaneous current. Charge, time and rate are distinct quantities.

Define the rate

Electric current is the charge passing a point per unit time: I = Q/t. With charge Q in coulombs and time t in seconds, current I is in amperes. One ampere means one coulomb per second. State the point or cross-section through which charge is counted.

For 12 C passing a marked section in 4 s, the average current over that interval is 3 A. If the current is constant, this average is also its value throughout the interval. If it varies, the total-charge calculation supplies the interval average, not every instantaneous value.

Convert both quantities

Convert prefixed charges and non-second times before dividing. For 18 mC in 6 ms, both prefixes contribute 10⁻³, so (18 × 10⁻³)/(6 × 10⁻³) = 3 A. Cancelling a prefix is justified only when the numerator and denominator use the same multiplier.

Signed charge passages must use a stated direction convention. Opposite passages can reduce the signed net total even when carriers moved. Unless such a changing-direction account is specified, introductory examples give a one-direction passed-charge magnitude. Do not infer voltage, resistance or energy from current alone.

Sources for this lesson

Pause and explain

18 mC passes a point in 6 ms. What is the current?

Put the idea to work

Worked example

12 C passes a marked wire section in 4 s. Calculate the interval average current.

Show the worked solution
  1. Use I = Q/t.
  2. Both values are already in C and s.
  3. 12/4 = 3 A.

Answer 3 A average over the stated interval.

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Choose Easy, Normal or Difficult. Save your answers and open worked review after finishing.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Calculate the current when 12 C passes a point in 4 s.

Give me a hint

Divide passed charge by its associated time interval.

Compare my reasoning
  1. I = Q/t.
  2. Q = 12 C and t = 4 s.
  3. I = 3 A.

3 A.

Look for these in your work

  • Use the same interval.
  • State amperes.
2 · Independent

Calculate average current for 30 mC in 2 s and for 18 mC in 6 ms.

Give me a hint

Convert each charge and time independently before comparing the two rates.

Compare my reasoning
  1. 0.030/2 = 0.015 A.
  2. 0.018/0.006 = 3 A.
  3. The different time scales produce different rates.

0.015 A (15 mA); 3 A.

Look for these in your work

  • Convert both examples.
  • Do not cancel unlike prefixes.
3 · Transfer

A variable current passes 20 C in 10 s. A learner claims it was exactly 2 A at every instant. Assess the claim.

Give me a hint

Ask whether the total charge determines the detailed time profile.

Compare my reasoning
  1. The interval average is 20/10 = 2 A.
  2. Many varying profiles can give the same total.
  3. Constancy is not established without further information.

Average 2 A; the instantaneous values are not established.

Look for these in your work

  • Calculate the supported average.
  • Identify the missing time-profile evidence.

Common mistakes

  • Use coulombs and seconds consistently.
  • An interval average need not be constant current.
  • Identify the chosen section and sign convention.
Recall without your notes

What can you explain now?

What does 1 A mean?

Compare with the explanation

1 C passing a point per second.

The ampere expresses a charge-flow rate rather than a stored amount of charge.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

Define and calculate charge-flow rate with consistent units and an explicit averaging interval.

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Science — Combined

Course scope and assessment

This pathway maps all 121 detailed subject-content sections in the published 0653 syllabus for exams in 2028 and 2029. It adapts original lessons from the related single-science pathways and keeps Combined Science's narrower scope: Biology B1–B16, Chemistry C1–C12 and Physics P1–P5. A 0653-specific objective-by-objective review, Core/Supplement audit, human subject-teacher review, supervised laboratory experience and cumulative assessment remain in progress. Written practice is self-checked and does not predict an official grade. The separate 2025–2027 syllabus has not been reconciled here; choose the 2028–2029 syllabus only.

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