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IGCSE · Cambridge (CIE) · 0654

Combine unit conversion with magnification calculations

Make the two lengths comparable before using the ratio.

Section B2.2 · Size of specimens

Size of specimens · Cambridge IGCSE 0654 · B2.2

Mapped to the named 0654 section using teaching from the corresponding single-science course. A 0654-specific review of every Core and Supplement objective is still in progress. Written practice is self-checked; it does not demonstrate supervised laboratory competence or award an official Cambridge grade.

Before you begin

  • Recall the distinction between plant, animal and bacterial cells. Read the supplied evidence before drawing a conclusion.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

What is 75 μm expressed in mm?

What you will learn

  • Convert mixed length units before calculating.
  • Detect a thousand-fold magnification error.
A 30 mm image and 75 μm actual specimen length require a common unit. Convert 75 μm to 0.075 mm, then 30 ÷ 0.075 gives ×400.Match units before forming aratioStart with unlike unitsImage: 30 mm · actual: 75 μmExpress both lengths in mm75 μm ÷ 1000 = 0.075 mmThen form the ratio30 ÷ 0.075 = 400Magnification: ×400
A 30 mm image and 75 μm actual specimen length require a common unit. Convert 75 μm to 0.075 mm, then 30 ÷ 0.075 gives ×400.

Convert before dividing

An image length of 30 mm and actual specimen length 75 μm must not be divided as 30 ÷ 75 without conversion. Convert 75 μm to 0.075 mm, then 30 ÷ 0.075 = 400, giving ×400. Alternatively convert 30 mm to 30 000 μm and divide by 75 μm.

Both conversion routes must agree. Magnification remains dimensionless. Write the conversion step so the origin of a factor of 1000 is visible rather than treating it as an unexplained adjustment after the answer.

Keep actual-size units explicit

An image length of 48 mm at ×1200 gives actual length 48 ÷ 1200 = 0.04 mm, which is 40 μm. The first result is correct in mm; converting to μm changes the number but not the physical length.

If a result says ×0.4 for the first enlarged image, substituting shows a unit mismatch or reversed interpretation. A scale bar may supply an actual μm length; compare its measured image length with the specimen on the same copy before converting.

Sources for this lesson

Pause and explain

A 30 mm image represents 75 μm actual length. Why is ×0.4 wrong?

Put the idea to work

Worked example

A 30 mm image represents an actual length of 75 μm. Calculate magnification.

Show the worked solution
  1. 75 μm ÷ 1000 = 0.075 mm.
  2. 30 ÷ 0.075 = 400.
  3. Or 30 000 μm ÷ 75 μm = 400.

Answer ×400.

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Choose Easy, Normal or Difficult. Save your answers and open worked review after finishing.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

An image is 18 mm; actual length is 60 μm. Find magnification.

Give me a hint

Convert 60 μm to mm.

Compare my reasoning
  1. 60 μm = 0.06 mm.
  2. 18 ÷ 0.06 = 300.

×300.

Look for these in your work

  • Correct conversion.
  • Dimensionless result.
2 · Independent

A 56 mm image is ×1400. Find actual length in μm.

Give me a hint

First calculate mm, then convert.

Compare my reasoning
  1. 56 ÷ 1400 = 0.04 mm.
  2. 0.04 × 1000 = 40 μm.

40 μm.

Look for these in your work

  • Correct division.
  • Correct unit conversion.
3 · Transfer

A 20 mm drawn bar represents 25 μm actual length. A cell measures 64 mm on the same copy. Find actual cell length and state the scaling assumption.

Give me a hint

Use cell-to-bar image ratio.

Compare my reasoning
  1. 64 ÷ 20 = 3.2 bar lengths.
  2. 3.2 × 25 = 80 μm.
  3. Both dimensions and the bar must share the same proportional scale.

80 μm, assuming a common proportional scale.

Look for these in your work

  • Ratio and conversion meaning.
  • State the same-copy scaling assumption.

Common mistakes

  • A mm-to-μm mismatch can produce a thousand-fold error.
  • State units at the conversion step.
Recall without your notes

What can you explain now?

What must be done before dividing image length in mm by actual length in μm?

Compare with the explanation

Express both lengths in the same unit.

The units must cancel in the ratio.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

Solve the same magnification once in mm and once in μm and compare.

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Sciences — Co-ordinated (Double)

Course scope and assessment

This 2028–2029 pathway maps all 152 detailed subject-content sections in the published 0654 syllabus to original teaching and staged practice. It adapts teaching from the related single-science pathways and excludes clear 0610-only topics such as classification systems, human excretion, tropic responses, food supply, population dynamics, detailed pollution and biotechnology. Some explanations may include wider single-science context. A 0654-specific objective-by-objective review, Core/Supplement audit, human subject-teacher review, supervised laboratory experience and cumulative assessment remain in progress. Written practice is self-checked and does not predict an official grade. The 2025–2027 syllabus has not been reconciled here; choose the 2028–2029 syllabus only.

StudyForA · Learn with understanding

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