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IGCSE · Cambridge (CIE) · 0654

Rearrange the orbital speed equation for period and radius

Find T or r from v = 2πr/T while retaining the model and units.

Section P6.1.1 · The Earth

The Earth · Cambridge IGCSE 0654 · P6.1.1

Mapped to the named 0654 section using teaching from the corresponding single-science course. A 0654-specific review of every Core and Supplement objective is still in progress. Written practice is self-checked; it does not demonstrate supervised laboratory competence or award an official Cambridge grade.

Before you begin

  • Rearrange a three-variable equation.
  • Recognise the centre-to-surface radius.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

Which balance follows by multiplying v = 2πr/T by T?

What you will learn

  • Find T or r from v = 2πr/T while retaining the model and units.
  • Rearrange the speed equation and distinguish calculated radius from surface altitude.
The three equivalent equations describe a circular or average-radius model. Radius is centre-referenced; altitude needs a separate planetary radius.Find a period or radiusv = 2πr/TDistance divided by timeT = 2πr/vCircumference divided by speedr = vT/(2π)Centre-to-orbit distanceAltitude = r − planet radius
The three equivalent equations describe a circular or average-radius model. Radius is centre-referenced; altitude needs a separate planetary radius.

Keep the multiplication together

Starting from v = 2πr/T, multiply both sides by T to obtain vT = 2πr. Divide by v for T = 2πr/v, or divide by 2π for r = vT/(2π). Writing this intermediate balance makes it harder to put a period or π in the wrong place.

A period has units of time: metres divided by metres per second gives seconds. A radius has units of distance: metres per second multiplied by seconds gives metres, with 2π dimensionless. Units can expose a rearrangement error before a numerical answer is accepted.

Interpret the radius you obtain

The calculated radius is the centre-to-orbit distance in the supplied circular or average-radius model. To find an altitude, subtract a separately supplied planetary radius. Do not call the entire orbital radius an altitude or assume a planetary radius when none is given.

A rearranged equation does not establish that the supplied orbit is physically possible around a particular body. It describes distance, path and period consistently in the model. Strongly elliptical orbits still require care about average radius and average versus local speed.

Sources for this lesson

Pause and explain

Which expression gives orbital radius from average speed and period?

Put the idea to work

Worked example

A circular model has r = 8.0 × 10⁶ m and average v = 8000 m/s. Find T.

Show the worked solution
  1. Rearrange to T = 2πr/v.
  2. Substitute 2π × 8.0 × 10⁶ ÷ 8000.
  3. Calculate 6283.19 s.

Answer Approximately 6.28 × 10³ s, or 105 minutes.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

A supplied circular orbit has r = 9.0 × 10⁶ m and v = 7500 m/s. Calculate T.

Give me a hint

Period is circumference divided by the stated average speed.

Compare my reasoning
  1. Use T = 2πr/v.
  2. Calculate 2π × 9.0 × 10⁶ ÷ 7500.
  3. Obtain 7539.82 s.

Approximately 7.54 × 10³ s.

Look for these in your work

  • Rearrange before substitution.
  • Give the period in seconds.
2 · Independent

A supplied circular model has v = 6000 m/s and T = 8000 s. Calculate r.

Give me a hint

Speed multiplied by period gives the complete path length.

Compare my reasoning
  1. Use r = vT/(2π).
  2. Calculate 6000 × 8000 ÷ (2π).
  3. Obtain 7639437 m.

Approximately 7.64 × 10⁶ m.

Look for these in your work

  • Keep 2π in the denominator.
  • State centre-referenced radius.
3 · Transfer

For that same orbit, a planet’s supplied radius is 6.0 × 10⁶ m. Estimate the satellite altitude.

Give me a hint

Use the calculated orbit radius and subtract the planet’s radius.

Compare my reasoning
  1. Keep the unrounded orbit radius 7639437 m.
  2. Subtract 6000000 m.
  3. Round 1639437 m to the required precision.

Approximately 1.64 × 10⁶ m above the surface.

Look for these in your work

  • Subtract rather than add at this stage.
  • Distinguish altitude from orbit radius.

Common mistakes

  • Do not invert the circumference-to-speed ratio.
  • Calculated radius is not automatically altitude.
  • Check that period answers have time units.
Recall without your notes

What can you explain now?

Which expression gives orbital radius from average speed and period?

Compare with the explanation

r = vT/(2π)

Multiplying speed by period gives the full path length, then dividing by 2π gives its circular radius.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

Rearrange the speed equation and distinguish calculated radius from surface altitude.

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Sciences — Co-ordinated (Double)

Course scope and assessment

This 2028–2029 pathway maps all 152 detailed subject-content sections in the published 0654 syllabus to original teaching and staged practice. It adapts teaching from the related single-science pathways and excludes clear 0610-only topics such as classification systems, human excretion, tropic responses, food supply, population dynamics, detailed pollution and biotechnology. Some explanations may include wider single-science context. A 0654-specific objective-by-objective review, Core/Supplement audit, human subject-teacher review, supervised laboratory experience and cumulative assessment remain in progress. Written practice is self-checked and does not predict an official grade. The 2025–2027 syllabus has not been reconciled here; choose the 2028–2029 syllabus only.

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