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IGCSE · Cambridge (CIE) · 0980

Inverse ratios for right-triangle angles

Use inverse sine, cosine or tangent and round an angle in degrees to one decimal place.

Section Paper 4 · Extended · Calculator

Trigonometry pathway · Cambridge 0980 (9–1) · C6.2 / E6.2

Core and Extended. This is the separate 9–1 qualification 0980. Cambridge intends Core for grades 4–1 and Extended for grades 9–5; the eligible award bands are grades 5–1 for the Core papers and grades 9–3 for the Extended papers.

Before you begin

  • Label opposite, adjacent and hypotenuse.
  • Use degree mode and inverse calculator functions.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

Which inverse function uses opposite divided by adjacent?

What you will learn

  • Choose an inverse ratio from two known sides.
  • Check an acute result and avoid treating inverse sine as a reciprocal.

Recover the angle from a ratio

If opposite and adjacent legs are 3 and 4 cm, tan θ = 3/4 and θ = tan⁻¹(3/4) ≈ 36.9°. If opposite and hypotenuse are known, use sin⁻¹(O/H); for adjacent and hypotenuse use cos⁻¹(A/H). Write the ratio in the chosen angle's order before applying the inverse function.

The inverse notation sin⁻¹ here means the angle whose sine is the supplied ratio, not 1/sin. For a right triangle's acute angle, sine and cosine inputs must lie strictly between zero and one. A ratio greater than one suggests a swapped hypotenuse or incompatible measurements.

Check the geometry and accuracy

The two acute angles sum to 90°. For a 3–4–5 triangle, the angle opposite side three is about 36.9° and the angle opposite four is about 53.1°. A larger side faces the larger angle, giving another useful check without repeating every calculation.

Use full calculator precision for the ratio and intermediate angle. Give final decimal angles in degrees to one decimal place unless a question specifies otherwise. A right-angle mark is essential to these ratios; two arbitrary sides of a non-right triangle need the sine or cosine rule later in Extended.

Pause and explain

A right triangle has O = 3 and H = 6. Find the chosen acute angle.

Put the idea to work

Worked example

A right triangle has opposite leg 3 cm and adjacent leg 4 cm relative to θ. Find θ.

Show the worked solution
  1. tan θ = 3/4 = 0.75.
  2. Use inverse tangent in degrees: θ ≈ 36.8699°.
  3. Round the final angle to one decimal place: 36.9°.

Answer 36.9°.

Try a topic test

Choose Easy, Normal or Difficult. Save your answers and open worked review after finishing.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

A right triangle has A = 4 and H = 8. Find θ.

Give me a hint

Use the adjacent-to-hypotenuse ratio.

Compare my reasoning
  1. cos θ = 4/8 = 0.5.
  2. θ = cos⁻¹(0.5) = 60°.
  3. The other acute angle is 30°, confirming the right-triangle total.

60°.

Look for these in your work

  • Selected cosine from the known sides.
  • Used an inverse function for an angle.
2 · Independent

A right triangle has O = 8 and A = 15. Find θ to one decimal place.

Give me a hint

Apply inverse tangent to 8/15.

Compare my reasoning
  1. tan θ = 8/15.
  2. Inverse tangent gives approximately 28.0725°.
  3. The final angle is 28.1°, smaller than 45° because O is shorter than A.

28.1°.

Look for these in your work

  • Kept the ratio in the correct order.
  • Rounded the final degree angle only.
3 · Transfer

A ramp rises 1.5 m over a horizontal distance of 4 m. Find its angle to horizontal.

Give me a hint

Horizontal run is adjacent, not hypotenuse.

Compare my reasoning
  1. tan θ = 1.5/4.
  2. θ = tan⁻¹(0.375) ≈ 20.5560°.
  3. To one decimal place the slope angle is 20.6°.

20.6°.

Look for these in your work

  • Used run and rise as perpendicular legs.
  • Reported the angle in degrees.

Common mistakes

  • Reporting the ratio as an angle.
  • Using inverse sine for two known legs.
  • Rounding the ratio early or using radian mode.
Recall without your notes

What can you explain now?

What does sin⁻¹(0.5) mean in an angle calculation?

Compare with the explanation

The angle whose sine is 0.5.

The inverse function reverses sine on the appropriate angle range; it is not a reciprocal.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

Tomorrow, choose two sides of a right triangle and recover each acute angle independently.

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Mathematics (9-1)

Course scope and assessment

StudyForA maps the 72 Core and Extended section entries in Cambridge IGCSE Mathematics (9–1) 0980 to original teaching and staged practice. This route covers the 2025–2027 syllabus and the 2028–2030 Version 2 syllabus; Cambridge says the 2028 update makes no significant changes affecting teaching, while its assessment overview is updated. The course keeps the 9–1 grading and paper rules separate from 0580. Questions and written work are self-checked, not Cambridge-graded; this is not a timed mock or an official grade, and subject-teacher review remains pending. 0980 is available in June and November in Administrative Zone 3 and for centres in Oman and the UAE. Confirm the exam series and your centre's entry eligibility with Cambridge and your exams officer.

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