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A Level · Cambridge (CIE) · 9702

Count gas particles with the mole

Treat amount of substance as an SI base quantity and connect a mole to the Avogadro constant.

Section 15 · Ideal gases

Ideal gases · Cambridge International AS & A Level Physics 9702 · 15.1

A Level; Cambridge International Physics 9702, 2025–2027 syllabus, Topic 15. These original explanations and calculations are study aids; full timed assessment and human subject-teacher review remain outstanding.

Before you begin

  • Use pressure, volume, temperature in kelvins, energy and scientific notation.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

What is the SI base unit for amount of substance?

What you will learn

  • Use amount of substance as an SI base quantity measured in moles
  • Relate one mole of particles to the Avogadro constant
  • Convert between particle number N and amount n

The mole measures amount of substance

Amount of substance is an SI base quantity with the base unit mole, symbol mol. The amount n tells how many specified elementary entities are present; state whether the entities are molecules, atoms, ions or another particle type.

A mole is not a mass unit. A sample's mass also depends on the mass of each entity, whereas the amount in moles counts entities through the Avogadro constant.

Use the Avogadro constant to count entities

One mole contains a number of particles equal to the Avogadro constant, NA = 6.02 × 10²³ mol⁻¹. The particle count is N = nNA; rearranging gives n = N/NA.

Check that N is a number of the entity named in the question and that n is in mol. The subscript in NA distinguishes the Avogadro constant from particle number N.

N = nNA · n = N/NA · NA = 6.02 × 10²³ mol⁻¹

Pause and explain

How many particles are in one mole?

Put the idea to work

Worked example

How many molecules are in 0.50 mol of a gas?

Show the worked solution
  1. Use N = nNA.
  2. N = 0.50 × 6.02 × 10²³.
  3. Give a particle count.

Answer N = 3.01 × 10²³ molecules.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Calculate the number of molecules in 0.25 mol of a gas.

Give me a hint

Multiply the amount in moles by NA.

Compare my reasoning
  1. N = nNA.
  2. N = 0.25 × 6.02 × 10²³.
  3. State the number of molecules.

N = 1.505 × 10²³ molecules, about 1.51 × 10²³.

Look for these in your work

  • Relation selected
  • Amount multiplied
  • Particles identified
2 · Independent

A gas sample contains 1.204 × 10²⁴ molecules. Calculate its amount of substance.

Give me a hint

Divide particle number by Avogadro's constant.

Compare my reasoning
  1. n = N/NA.
  2. n = 1.204 × 10²⁴ / 6.02 × 10²³.
  3. Give mol.

n = 2.00 mol.

Look for these in your work

  • Relation rearranged
  • Powers of ten handled
  • Mole unit stated
3 · Transfer

Two sealed containers each hold one mole of a different gas. Compare their particle counts without assuming their masses are equal.

Give me a hint

The mole counts specified entities; mass depends on what each particle is made of.

Compare my reasoning
  1. Each sample has n = 1 mol.
  2. Each therefore contains NA particles of its named gas.
  3. Their masses may differ because the particle species may have different masses.

Both contain 6.02 × 10²³ specified particles, even though their total masses need not match.

Look for these in your work

  • Equal amount interpreted
  • Avogadro count applied
  • Mass distinguished from amount

Common mistakes

  • Treating mol as a mass unit
  • Using the reciprocal when calculating N from n
  • Leaving unclear which particles are being counted
Recall without your notes

What can you explain now?

What is the SI base unit for amount of substance?

Compare with the explanation

The mole, mol

Amount of substance is measured in moles.

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Make it stick

How does the Avogadro constant connect amount in moles to a count of particles?

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Course scope and assessment

One hundred and sixty-two original lessons cover all 12 published subject-content outcomes in Topic 1 (sections 1.1–1.4), all nine outcomes in Topic 2 (section 2.1), all 13 outcomes in Topic 3 (sections 3.1–3.3), all 13 outcomes in Topic 4 (sections 4.1–4.3), all 11 outcomes in Topic 5 (sections 5.1–5.2), all 10 outcomes in Topic 6 (sections 6.1–6.2), all 16 outcomes in Topic 7 (sections 7.1–7.5), all 12 outcomes in Topic 8 (sections 8.1–8.4), all 15 outcomes in Topic 9 (sections 9.1–9.3), all 16 outcomes in Topic 10 (sections 10.1–10.3), all 18 outcomes in Topic 11 (sections 11.1–11.2), all seven outcomes in Topic 12 (sections 12.1–12.2), all 12 outcomes in Topic 13 (sections 13.1–13.4), all eight outcomes in Topic 14 (sections 14.1–14.3), and all nine outcomes in Topic 15 (sections 15.1–15.3), plus all four outcomes in Topic 16 (sections 16.1–16.2), and all ten outcomes in Topic 17 (sections 17.1–17.3), plus all 12 outcomes in Topic 18 (sections 18.1–18.5), all nine outcomes in Topic 19 (sections 19.1–19.3), all 19 outcomes in Topic 20 (sections 20.1–20.5), and all eight outcomes in Topic 21 (sections 21.1–21.2), and all 17 outcomes in Topic 22 (sections 22.1–22.4), and all 13 outcomes in Topic 23 (sections 23.1–23.2), and all 16 outcomes in Topic 24 (sections 24.1–24.3), and all 11 outcomes in Topic 25 (sections 25.1–25.3), of the 2025–2027 syllabus. Each lesson has guided, independent and application practice with explained answers. All 25 syllabus topics now have mapped teaching and practice; the 2028–2030 changes outside Topics 23–25 still need reconciliation. Online study cannot demonstrate supervised Paper 3 laboratory competence. Paper 5 planning and analysis, full timed cumulative assessment and human subject-teacher review remain outstanding.

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