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IGCSE · Cambridge (CIE) · 0652

Rearrange density equations and convert cubic units

Find mass or volume and convert g/cm³ to kg/m³ using a cubic length conversion.

Section P1.4 · Density

Density · Cambridge IGCSE Physical Science 0652 · P1.4

Cross-referenced from the related Cambridge IGCSE Chemistry 0620 or Physics 0625 teaching to the 0652 syllabus. Exact 0652 Core/Supplement objective coverage and this final-series course’s examiner fit still need specialist review. Written practice is self-checked and does not predict a Cambridge grade or demonstrate supervised laboratory competence.

Before you begin

  • Rearrange a division equation.
  • Cube the factor in a length-unit conversion.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

How many cm³ are in 1 m³?

What you will learn

  • Use m = ρV and V = m/ρ.
  • Convert density and volume units consistently.

Isolate the required quantity

From ρ = m/V, multiply by V to get m = ρV. A material of density 2.7 g/cm³ occupying 15 cm³ has mass 40.5 g. For mass 54 g at density 2.7 g/cm³, rearrange to V = m/ρ = 20 cm³.

Check units before substituting. Multiplying g/cm³ by cm³ leaves g. Dividing g by g/cm³ leaves cm³. If the volume is supplied in m³ while density is in g/cm³, convert one of them first rather than multiplying incompatible numerical values.

A cubic conversion uses the length factor three times

One metre is 100 cm, so one cubic metre contains 100³ = 1,000,000 cm³. Thus 1 cm³ = 10⁻⁶ m³. Also 1 g = 0.001 kg, so 1 g/cm³ = 0.001/10⁻⁶ = 1000 kg/m³. A density of 2.7 g/cm³ is 2700 kg/m³.

For a cross-check, 54 g becomes 0.054 kg and 20 cm³ becomes 0.000020 m³. Dividing gives 2700 kg/m³, the same density. Do not convert cm³ to m³ by dividing by only 100: that is a length conversion, not a volume conversion.

Sources for this lesson

Pause and explain

What is 2.7 g/cm³ in kg/m³?

Put the idea to work

Worked example

Convert 2.7 g/cm³ to kg/m³ and find the volume of 54 g at that density.

Show the worked solution
  1. Multiply the density by 1000 to obtain 2700 kg/m³.
  2. Using the original matched units, V = 54/2.7.
  3. V = 20 cm³ = 0.000020 m³.

Answer 2700 kg/m³; 20 cm³ or 0.000020 m³.

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Choose Easy, Normal or Difficult. Save your answers and open worked review after finishing.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Find the mass of 15 cm³ at density 2.7 g/cm³.

Give me a hint

Multiply density by volume with matching cubic-centimetre units.

Compare my reasoning
  1. Use m = ρV.
  2. 2.7 × 15 = 40.5.
  3. The remaining unit is g.

40.5 g.

Look for these in your work

  • Rearrange correctly.
  • Cancel volume units.
2 · Independent

Find the volume of 54 g at 2.7 g/cm³, then express both density and volume in SI units.

Give me a hint

Calculate in matched units, then apply the mass and cubic-volume factors.

Compare my reasoning
  1. V = 54/2.7 = 20 cm³.
  2. Density is 2700 kg/m³.
  3. Volume is 20 × 10⁻⁶ = 0.000020 m³.

20 cm³; 2700 kg/m³; 0.000020 m³.

Look for these in your work

  • Use m/ρ for volume.
  • Apply the cubic conversion.
3 · Transfer

A liquid density is 800 kg/m³ and its volume is 250 ml. Find mass in kg and g.

Give me a hint

One ml equals one cm³; convert the volume into m³.

Compare my reasoning
  1. 250 ml = 250 cm³ = 0.000250 m³.
  2. m = 800 × 0.000250 = 0.200 kg.
  3. Convert to 200 g.

0.200 kg; 200 g.

Look for these in your work

  • Convert the volume fully.
  • Retain consistent density units.

Common mistakes

  • Cube the length conversion for volume.
  • A density conversion combines mass and volume factors.
  • Use compatible units in m = ρV.
Recall without your notes

What can you explain now?

What mass occupies 15 cm³ at 2.7 g/cm³?

Compare with the explanation

40.5 g.

Multiply the density by the volume.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

Derive the g/cm³ to kg/m³ factor from its two unit conversions without memorising it alone.

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Physical Science

Course scope and assessment

This page maps the 2025–2026 Cambridge IGCSE Physical Science 0652 syllabus: 38 Chemistry sections and 46 Physics sections. Every section links to original 0620/0625 teaching or one of five new 0652 lessons, with guided, independent and transfer practice and explained answers. Cambridge limits entry to Administrative Zone 3 and identifies November 2026 as the final exam series. The section crosswalk is complete as a first coverage map; a numbered-objective and Core/Supplement audit, independent subject-teacher review and cumulative assessment are still needed. Written practice does not award a Cambridge grade. Online activities cannot demonstrate supervised laboratory competence or complete Paper 5/6.

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