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IGCSE · Cambridge (CIE) · 0980

Exact trigonometric values

Derive special-angle ratios and use exact fractions and surds without a calculator.

Section Paper 2 · Extended · Non-calculator

Trigonometry pathway · Cambridge 0980 (9–1) · E6.3

Extended only. This is the separate 9–1 qualification 0980. Cambridge intends Core for grades 4–1 and Extended for grades 9–5; the eligible award bands are grades 5–1 for the Core papers and grades 9–3 for the Extended papers.

Before you begin

  • Simplify surds and fractions.
  • Use right-triangle ratios.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

What is √2 divided by 2?

What you will learn

  • Know sine and cosine at 0°, 30°, 45°, 60° and 90°.
  • Know tangent at 0°, 30°, 45° and 60°.

Two special triangles explain the values

Cutting an equilateral triangle of side two in half gives a 30–60–90 triangle with sides 1, √3 and 2. Therefore sin 30° = 1/2, cos 30° = √3/2, sin 60° = √3/2 and cos 60° = 1/2. Its tangent ratios are tan 30° = 1/√3 = √3/3 and tan 60° = √3.

A right isosceles triangle with legs one has hypotenuse √2. Thus sin 45° = cos 45° = 1/√2 = √2/2 and tan 45° = 1. These are exact values; replacing √2/2 by 0.707 loses exactness. A sketch of each triangle can recover the values if memory fails.

Include the endpoint angles

On the unit circle or from limiting right-triangle positions, sin 0° = 0, cos 0° = 1, sin 90° = 1 and cos 90° = 0. Across 0°, 30°, 45°, 60°, 90°, the sine values are 0, 1/2, √2/2, √3/2, 1; the cosine values reverse this order.

Tangent is sine divided by cosine: tan 0° = 0, tan 30° = √3/3, tan 45° = 1 and tan 60° = √3. Tangent 90° is undefined because its cosine denominator is zero; it is not one of the required exact tangent values. Use the exact ratios to solve simple non-calculator triangle problems.

Pause and explain

What is exact cos 60°?

Put the idea to work

Worked example

A right triangle has hypotenuse 12 cm and angle 60°. Find the opposite side exactly.

Show the worked solution
  1. The ratio is sin 60° = opposite/12.
  2. Use exact sin 60° = √3/2.
  3. Opposite = 12 × √3/2 = 6√3 cm.

Answer 6√3 cm.

Try a topic test

Choose Easy, Normal or Difficult. Save your answers and open worked review after finishing.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Find sin 45° + cos 45° exactly.

Give me a hint

The two ratios are equal.

Compare my reasoning
  1. Each ratio is √2/2.
  2. Their sum is 2 × √2/2.
  3. Simplify to √2 without a decimal.

√2.

Look for these in your work

  • Used exact special-angle values.
  • Combined equal surd terms.
2 · Independent

Find tan 30° × tan 60° exactly.

Give me a hint

Use √3/3 and √3.

Compare my reasoning
  1. The product is (√3/3) × √3.
  2. The numerator becomes three.
  3. Three divided by three is one.

1.

Look for these in your work

  • Used the two exact tangent values.
  • Simplified the surd product.
3 · Transfer

A ramp has hypotenuse 10 m and slope 45°. Find its horizontal and vertical components exactly.

Give me a hint

Sine and cosine forty-five are equal.

Compare my reasoning
  1. Each component is 10 × √2/2.
  2. Both simplify to 5√2 m.
  3. Their squared sum is 50 + 50 = 100, verifying the hypotenuse.

Both components are 5√2 m.

Look for these in your work

  • Retained exactness.
  • Verified the two components with Pythagoras.

Common mistakes

  • Interchanging sine sixty and cosine sixty.
  • Replacing an exact requested answer with a rounded decimal.
  • Assigning a finite value to tangent ninety.
Recall without your notes

What can you explain now?

Is tan 90° a finite value?

Compare with the explanation

No; it is undefined.

Tangent divides sine by cosine, and cos 90° = 0 would require division by zero.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

Tomorrow, reconstruct the sine and cosine rows from the two special triangles, including endpoint values.

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Mathematics (9-1)

Course scope and assessment

StudyForA maps the 72 Core and Extended section entries in Cambridge IGCSE Mathematics (9–1) 0980 to original teaching and staged practice. This route covers the 2025–2027 syllabus and the 2028–2030 Version 2 syllabus; Cambridge says the 2028 update makes no significant changes affecting teaching, while its assessment overview is updated. The course keeps the 9–1 grading and paper rules separate from 0580. Questions and written work are self-checked, not Cambridge-graded; this is not a timed mock or an official grade, and subject-teacher review remains pending. 0980 is available in June and November in Administrative Zone 3 and for centres in Oman and the UAE. Confirm the exam series and your centre's entry eligibility with Cambridge and your exams officer.

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