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IGCSE · Cambridge (CIE) · 0980

Two-event Venn diagrams and overlap

Read disjoint regions of a two-set diagram and distinguish either event from both events.

Section Paper 2 · Extended · Non-calculator

Probability pathway · Cambridge 0980 (9–1) · C8.1 / E8.1 / C8.3 / E8.3

Core and Extended. Core uses two-event Venn diagrams without requiring set notation; Extended may use union and intersection symbols. This is the separate 9–1 qualification 0980. Cambridge intends Core for grades 4–1 and Extended for grades 9–5; the eligible award bands are grades 5–1 for the Core papers and grades 9–3 for the Extended papers.

Before you begin

  • Read two-set Venn regions.
  • Calculate a probability from counts.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

What does 'both events' mean in a Venn diagram?

What you will learn

  • Count an overlap only once in an either-event probability.
  • Use the universal total including neither-event outcomes.

Regions must not overlap in the count

In a group of forty, twelve study French only, eight Spanish only, six both and fourteen neither. The number studying French is eighteen, not twelve. The number studying at least one language is 12 + 6 + 8 = 26; the overlap is included once.

Adding total French eighteen to total Spanish fourteen double-counts the six students in both sets. Subtract the overlap once to obtain twenty-six. Extended notation uses A ∩ B for both and A ∪ B for either or both; 'or' is normally inclusive in these probability questions.

Choose the event and the denominator separately

Probability of both languages is 6/40 = 3/20. Probability of neither is 14/40 = 7/20. The denominator is the entire randomly sampled group, including students outside both circles. The diagram's enclosing rectangle represents that whole group.

If the question restricts selection to French learners, the denominator changes to eighteen; that is a conditional probability and is Extended. Do not silently use a restricted denominator for an ordinary random choice from the whole group.

Pause and explain

A group of 40 has 12 A-only, 8 B-only, 6 both and 14 neither. Find P(A or B).

Put the idea to work

Worked example

Forty learners: French only 12, Spanish only 8, both 6, neither 14. Find P(at least one language).

Show the worked solution
  1. The favourable disjoint regions contain 12 + 6 + 8 = 26 learners.
  2. The whole group contains forty.
  3. Probability is 26/40 = 13/20, with the overlap counted once.

Answer 13/20.

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Choose Easy, Normal or Difficult. Save your answers and open worked review after finishing.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Using the group of forty above, find P(both languages).

Give me a hint

Use the overlap and the universal total.

Compare my reasoning
  1. The overlap contains six.
  2. The total group is forty.
  3. Probability is 6/40 = 3/20.

3/20.

Look for these in your work

  • Selected the overlap.
  • Kept the whole-group denominator.
2 · Independent

Using the same group, find P(French) and P(not French).

Give me a hint

French includes French-only and both.

Compare my reasoning
  1. French count is 12 + 6 = 18, giving 9/20.
  2. Not French count is 8 + 14 = 22, giving 11/20.
  3. The two probabilities add to one.

9/20 and 11/20.

Look for these in your work

  • Included the overlap in French.
  • Checked complementary probabilities.
3 · Transfer

In 50 learners, 20 study art, 18 music and 7 both. Find the number and probability studying neither.

Give me a hint

First count the union with the overlap subtracted once.

Compare my reasoning
  1. At least one count is 20 + 18 − 7 = 31.
  2. Neither count is 50 − 31 = 19.
  3. Probability is 19/50.

19 learners; probability 19/50.

Look for these in your work

  • Removed the double-counted overlap.
  • Used the universal complement.

Common mistakes

  • Double-counting the overlap.
  • Leaving neither out of the denominator.
  • Confusing inclusive or with exactly one.
Recall without your notes

What can you explain now?

Does ordinary 'A or B' exclude the overlap?

Compare with the explanation

No; it normally includes either or both.

Exclude the overlap only when the wording explicitly says exactly one event.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

Tomorrow, label all four disjoint Venn regions before computing a probability.

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Mathematics (9-1)

Course scope and assessment

StudyForA maps the 72 Core and Extended section entries in Cambridge IGCSE Mathematics (9–1) 0980 to original teaching and staged practice. This route covers the 2025–2027 syllabus and the 2028–2030 Version 2 syllabus; Cambridge says the 2028 update makes no significant changes affecting teaching, while its assessment overview is updated. The course keeps the 9–1 grading and paper rules separate from 0580. Questions and written work are self-checked, not Cambridge-graded; this is not a timed mock or an official grade, and subject-teacher review remains pending. 0980 is available in June and November in Administrative Zone 3 and for centres in Oman and the UAE. Confirm the exam series and your centre's entry eligibility with Cambridge and your exams officer.

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