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A Level · Cambridge (CIE) · 9702

Calculate magnetic flux and flux linkage

Define magnetic flux through a surface, use Φ = BA and relate flux through one turn to total flux linkage.

Section 20 · Magnetic fields

Magnetic fields · Cambridge International AS & A Level Physics 9702 · 20.5

A Level; Cambridge International Physics 9702, 2025–2027 syllabus, Topic 20. These original explanations and calculations are study aids; full timed assessment and human subject-teacher review remain outstanding.

Before you begin

  • Use current, charge, force, velocity, vectors, area and SI units; distinguish conventional current from electron flow.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

For a uniform field perpendicular to a flat surface, what is the magnetic flux?

What you will learn

  • Define flux using field strength and area perpendicular to the field
  • Use Φ = BA
  • Calculate flux linkage for a coil of N turns

Flux counts field through a perpendicular area

Magnetic flux Φ through a surface is the product of magnetic flux density B and the cross-sectional area perpendicular to the field. For a uniform field normal to a flat area, Φ = BA. Its unit is the weber (Wb), with 1 Wb = 1 T m².

If a surface is tilted, only its projected area perpendicular to B contributes; equivalently Φ = BA cos θ when θ is the angle between B and the surface normal. Use the perpendicular-area wording to avoid confusing this angle with the plane of the surface.

A coil links the flux through its turns

For a coil of N turns with the same flux Φ through each turn, the magnetic flux linkage is NΦ. Its unit is Wb-turn. A change in flux linkage is what matters for electromagnetic induction in a coil.

When calculating flux, use the component of B normal to the area and convert area to square metres. A field parallel to the plane has zero perpendicular component and therefore zero flux through that ideal surface.

Φ = BA⊥ · flux linkage = NΦ

Pause and explain

A 100-turn coil has flux 0.004 Wb through each turn. What is its flux linkage?

Put the idea to work

Worked example

A 0.020 m² coil is in a 0.50 T uniform field perpendicular to its plane. Find the flux through one turn and the linkage for 200 turns.

Show the worked solution
  1. The field is normal to the plane, so the full area is perpendicular to B.
  2. Use Φ = BA.
  3. Multiply by the number of turns for flux linkage.

Answer Φ = 0.50 × 0.020 = 0.010 Wb; linkage = 200 × 0.010 = 2.0 Wb-turn.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

A 0.030 m² surface is in a 0.40 T field normal to its plane. Calculate Φ.

Give me a hint

Use Φ = BA with SI area.

Compare my reasoning
  1. The field is normal, so A⊥ = 0.030 m².
  2. Φ = 0.40 × 0.030.
  3. State webers.

Φ = 0.012 Wb.

Look for these in your work

  • Perpendicular area identified
  • Product calculated
  • Weber unit stated
2 · Independent

A 250-turn coil has 0.0060 Wb through each turn. Find its flux linkage.

Give me a hint

Multiply the flux per turn by N.

Compare my reasoning
  1. NΦ = 250 × 0.0060.
  2. NΦ = 1.5.
  3. State Wb-turn.

Flux linkage = 1.5 Wb-turn.

Look for these in your work

  • Turn count applied
  • Product calculated
  • Linkage unit stated
3 · Transfer

A uniform field lies parallel to the plane of a flat loop. What is the magnetic flux through the loop, and why?

Give me a hint

Use the area component perpendicular to B.

Compare my reasoning
  1. If B is parallel to the plane, the area normal is perpendicular to B.
  2. The projected area perpendicular to B is zero.
  3. Thus Φ = BA⊥ = 0.

The flux is zero because no area component is perpendicular to the field.

Look for these in your work

  • Surface orientation interpreted
  • Perpendicular area found
  • Flux conclusion stated

Common mistakes

  • Using area in cm² without conversion
  • Using the angle to the plane instead of the surface normal
  • Confusing flux Φ with flux linkage NΦ
  • Multiplying by turns when asked for flux through one turn
Recall without your notes

What can you explain now?

For a uniform field perpendicular to a flat surface, what is the magnetic flux?

Compare with the explanation

Φ = BA

Use field strength times the area perpendicular to B.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

How do surface orientation and number of turns distinguish flux from flux linkage?

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Physics

Course scope and assessment

One hundred and sixty-two original lessons cover all 12 published subject-content outcomes in Topic 1 (sections 1.1–1.4), all nine outcomes in Topic 2 (section 2.1), all 13 outcomes in Topic 3 (sections 3.1–3.3), all 13 outcomes in Topic 4 (sections 4.1–4.3), all 11 outcomes in Topic 5 (sections 5.1–5.2), all 10 outcomes in Topic 6 (sections 6.1–6.2), all 16 outcomes in Topic 7 (sections 7.1–7.5), all 12 outcomes in Topic 8 (sections 8.1–8.4), all 15 outcomes in Topic 9 (sections 9.1–9.3), all 16 outcomes in Topic 10 (sections 10.1–10.3), all 18 outcomes in Topic 11 (sections 11.1–11.2), all seven outcomes in Topic 12 (sections 12.1–12.2), all 12 outcomes in Topic 13 (sections 13.1–13.4), all eight outcomes in Topic 14 (sections 14.1–14.3), and all nine outcomes in Topic 15 (sections 15.1–15.3), plus all four outcomes in Topic 16 (sections 16.1–16.2), and all ten outcomes in Topic 17 (sections 17.1–17.3), plus all 12 outcomes in Topic 18 (sections 18.1–18.5), all nine outcomes in Topic 19 (sections 19.1–19.3), all 19 outcomes in Topic 20 (sections 20.1–20.5), and all eight outcomes in Topic 21 (sections 21.1–21.2), and all 17 outcomes in Topic 22 (sections 22.1–22.4), and all 13 outcomes in Topic 23 (sections 23.1–23.2), and all 16 outcomes in Topic 24 (sections 24.1–24.3), and all 11 outcomes in Topic 25 (sections 25.1–25.3), of the 2025–2027 syllabus. Each lesson has guided, independent and application practice with explained answers. All 25 syllabus topics now have mapped teaching and practice; the 2028–2030 changes outside Topics 23–25 still need reconciliation. Online study cannot demonstrate supervised Paper 3 laboratory competence. Paper 5 planning and analysis, full timed cumulative assessment and human subject-teacher review remain outstanding.

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