Learn in your language
Skip to content
A Level · Cambridge (CIE) · 9701

Dehydrate an alcohol to form an alkene

Remove H₂O using a heated catalyst or concentrated acid, then locate the new C=C bond.

Section 16 · Hydroxy compounds

Hydroxy compounds · Cambridge 9701 AS Chemistry · 16.1

AS Level; Cambridge International Chemistry 9701, 2025–2027 syllabus. State reagents and conditions, follow the stated reaction pathway, and distinguish each alcohol class and oxidation product. Written practice is self-checked

Before you begin

  • Use functional-group formulae and reaction types from Topic 13, alkene reactions from Topic 14, and halogenoalkane substitution from Topic 15.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

What small molecule is removed during alcohol dehydration?

What you will learn

  • Recall dehydration conditions
  • Write an alkene and water product
  • Distinguish dehydration from oxidation
Choose a route from the starting groupAlkenestarting groupH₂O(g) · H₃PO₄→ alcoholAlkenestarting groupcold dilute KMnO₄→ vicinal diolHalogenoalkanestarting groupNaOH(aq) · heat→ alcoholCarbonyl / acid / esterstarting groupreduction or hydrolysis→ alcoholMatch the reagent to both the starting group and target
Representative routes to alcohols and diols. Steam/H₃PO₄ hydrates an alkene to an alcohol; cold dilute acidified KMnO₄ forms a vicinal diol; aqueous NaOH and heat substitute a halogen with OH; reducing agents convert carbonyl or carboxyl groups into alcohols; ester hydrolysis releases an alcohol. These routes are alternatives selected from the starting functional group and target.

Eliminate water from an alcohol

Heating an alcohol with a catalyst such as Al₂O₃ or with concentrated acid can remove H₂O and form an alkene. This is dehydration, an elimination reaction.

Ethanol → ethene + water: CH₃CH₂OH → CH₂=CH₂ + H₂O. The two carbon atoms stay in the molecule and form a double bond.

Show the condition and product bond

State a heated catalyst or concentrated H₂SO₄. Do not confuse dehydration with oxidation by acidified dichromate, which changes the carbon bonded to OH into a carbonyl or carboxyl group.

For a larger alcohol, examine adjacent carbon atoms and place the C=C where hydrogen and OH are removed; there may be more than one possible alkene if the structure allows it.

Pause and explain

Which condition is suitable for alcohol dehydration?

Put the idea to work

Worked example

Show dehydration of butan-2-ol to one possible alkene.

Show the worked solution
  1. Remove the OH group from carbon 2 and H from an adjacent carbon.
  2. Form a C=C between those carbons.
  3. Include water and state suitable heating conditions.

Answer CH₃CH(OH)CH₂CH₃ → CH₃CH=CHCH₃ + H₂O; heat with Al₂O₃ or concentrated H₂SO₄.

Try a topic test

Choose Easy, Normal or Difficult. Save your answers and open worked review after finishing.

Test this topic →

From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Write one dehydration equation for propan-1-ol.

Give me a hint

Remove OH from carbon 1 and H from the adjacent carbon.

Compare my reasoning
  1. Keep three carbon atoms.
  2. Form a terminal C=C bond.
  3. Add H₂O as the eliminated molecule.

CH₃CH₂CH₂OH → CH₃CH=CH₂ + H₂O; heat with Al₂O₃ or concentrated H₂SO₄.

Look for these in your work

  • Alkene named
  • Water included
  • Condition stated
2 · Independent

Compare dehydration of ethanol with oxidation of ethanol.

Give me a hint

One route removes water; the other adds oxygen or removes hydrogen.

Compare my reasoning
  1. Dehydration forms ethene and water.
  2. Oxidation forms ethanal or ethanoic acid depending on conditions.
  3. Name the distinct reagents and apparatus.

Dehydration gives ethene using heat/catalyst or concentrated acid; oxidation uses acidified oxidant and gives ethanal or ethanoic acid.

Look for these in your work

  • Products distinguished
  • Condition sets separated
  • Reaction types correct
3 · Transfer

A proposed product from ethanol dehydration is CH₃CH₃. Identify the missing structural feature.

Give me a hint

The product should be unsaturated after water is removed.

Compare my reasoning
  1. Dehydration forms a C=C bond.
  2. Ethane has only single C–C bonds and would require hydrogenation.
  3. The product is ethene, CH₂=CH₂.

The alkene product is ethene, CH₂=CH₂; the proposed ethane is saturated and incorrect.

Look for these in your work

  • Product class checked
  • Double bond added
  • Formula corrected

Common mistakes

  • Calling dehydration oxidation
  • Omitting water
  • Writing an alkene with no C=C
Recall without your notes

What can you explain now?

What small molecule is removed during alcohol dehydration?

Compare with the explanation

Water

Dehydration eliminates H₂O as the alkene forms.

After trying it yourself, choose your next review. This is your self-assessment.

Your review choice appears on Today. Sign in to sync it across devices.

Make it stick

Which bond is formed when an alcohol is dehydrated, and what molecule is lost?

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Chemistry

Course scope and assessment

Four hundred and forty-two original lessons map the published learning outcomes across AS Chemistry Topics 1–22 and A Level Topics 23–37, with guided, independent and transfer practice and explained answers. Every numbered subject-content topic and listed outcome tag now has a mapped lesson sequence. Topic 32 maps all 12 hydroxy-compound outcome tags in 11 lessons; Topic 33 maps all 15 carboxylic-acid and derivative outcome tags in 16 lessons; Topic 34 maps all 22 nitrogen-compound outcome tags in 20 lessons; Topic 35 maps all 12 polymerisation outcome tags in 16 lessons; Topic 36 maps all four organic-synthesis outcome tags in 14 lessons; Topic 37 maps all 22 chromatography and NMR outcome tags in 18 lessons. Cambridge's 2028–2030 Version 1 syllabus states that there are no significant changes which affect teaching from the preceding edition; the routes are aligned to that edition. This is 37 of the 37 numbered subject-content topics. Full cumulative exam assessment, Paper 3 laboratory competence, Paper 5 investigation practice and human subject-teacher review remain outstanding. Written practice is self-checked and does not certify exam readiness.

StudyForA · Learn with understanding

Original teaching content and links to official sources. Check your exam year and qualification before using a resource.