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A Level · Cambridge (CIE) · 9701

Describe stereoisomerism and cis-trans isomerism

Distinguish stereoisomerism from structural isomerism and explain cis/trans arrangements around restricted bonds.

Section 13 · An introduction to AS Level organic chemistry

An introduction to AS Level organic chemistry · Cambridge 9701 · 13.4

AS Level; Cambridge International Chemistry 9701, 2025–2027 syllabus. Use the published functional-group scope and nomenclature limits; draw formula and mechanism evidence with correct connectivity, electron movement and stereochemistry. Written practice is self-checked

Before you begin

  • Use covalent structures, valency, molecular formulas, lone pairs, and single, double and triple bonds.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

What is unchanged between a pair of stereoisomers?

What you will learn

  • Define stereoisomerism
  • Distinguish geometrical and optical isomerism
  • Explain cis/trans isomerism in alkenes
Geometrical and optical isomerismcis-but-2-eneCCCH₃CH₃HHmethyl groups: same sidetrans-but-2-eneCCCH₃CH₃HHmethyl groups: opposite sidesA tetrahedral centre with four different groupsC*ABCDmirrorimage pairCis/trans: restricted rotation · Enantiomers: non-superimposable mirrors
Schematic organic stereoisomer comparison. Cis-but-2-ene has its two methyl groups on the same side of the double bond; trans-but-2-ene has them on opposite sides. A tetrahedral carbon with four different attachments can form two non-superimposable mirror-image enantiomers. Sketches show qualitative relationships, not exact perspective structures.

Stereoisomers keep the same connectivity

Stereoisomers have the same molecular formula and atom connectivity but different three-dimensional arrangements. Geometrical (cis/trans) and optical isomerism are two types.

In an alkene, each carbon of the C=C must be attached to two different groups for cis/trans isomerism to be possible. The groups can then occupy corresponding same-side or opposite-side arrangements.

Restricted rotation permits distinct arrangements

A π bond prevents free rotation around C=C because rotation would disrupt sideways overlap. The two arrangements therefore do not rapidly interconvert by simple rotation.

For but-2-ene, cis places the two CH₃ groups on the same side of C=C; trans places them on opposite sides. But-1-ene does not show cis/trans isomerism because one alkene carbon has two identical H atoms.

Pause and explain

What condition is needed at both C=C carbons for alkene cis/trans isomerism?

Put the idea to work

Worked example

Explain why but-2-ene has cis/trans isomers but but-1-ene does not.

Show the worked solution
  1. Both carbons of but-2-ene have two different attached groups.
  2. Its π bond restricts rotation, preserving distinct arrangements.
  3. One but-1-ene carbon has two identical H atoms, so the required condition fails.

Answer But-2-ene can have cis/trans isomers because each C=C carbon has two different groups and rotation is restricted; but-1-ene has two identical H atoms on one alkene carbon.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Define stereoisomerism in a sentence.

Give me a hint

State what stays the same and what changes.

Compare my reasoning
  1. The molecular formula is the same.
  2. The connectivity is the same.
  3. The three-dimensional arrangement differs.

Stereoisomers have the same molecular formula and connectivity but differ in spatial arrangement.

Look for these in your work

  • Formula
  • Connectivity
  • Spatial difference
2 · Independent

Describe cis and trans but-2-ene using the methyl groups.

Give me a hint

Compare the position of the two CH₃ groups relative to the C=C bond.

Compare my reasoning
  1. In cis-but-2-ene the CH₃ groups are on the same side.
  2. In trans-but-2-ene they are on opposite sides.
  3. Restricted rotation keeps the arrangements distinct.

Cis: methyl groups on the same side; trans: methyl groups on opposite sides of C=C.

Look for these in your work

  • Cis arrangement
  • Trans arrangement
  • Rotation condition
3 · Transfer

Assess whether CH₂=CHCH₂CH₃ can have cis/trans isomers.

Give me a hint

Check whether both alkene carbons have two different attached groups.

Compare my reasoning
  1. The terminal carbon has two H atoms.
  2. The groups on that C are identical.
  3. Therefore the required cis/trans distinction is absent.

No. One C of the double bond has two identical hydrogen atoms.

Look for these in your work

  • Carbon checked
  • Identical groups recognized
  • Conclusion stated

Common mistakes

  • Applying cis/trans to an alkene carbon with two identical groups
  • Confusing structural and stereoisomers
  • Saying the sigma bond causes restricted rotation
Recall without your notes

What can you explain now?

What is unchanged between a pair of stereoisomers?

Compare with the explanation

Atom connectivity

Stereoisomers differ in spatial arrangement, not connectivity.

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Make it stick

Why does a C=C bond permit geometrical isomerism while a freely rotating single bond does not?

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Keep learning Chemistry

Course scope and assessment

Four hundred and forty-two original lessons map the published learning outcomes across AS Chemistry Topics 1–22 and A Level Topics 23–37, with guided, independent and transfer practice and explained answers. Every numbered subject-content topic and listed outcome tag now has a mapped lesson sequence. Topic 32 maps all 12 hydroxy-compound outcome tags in 11 lessons; Topic 33 maps all 15 carboxylic-acid and derivative outcome tags in 16 lessons; Topic 34 maps all 22 nitrogen-compound outcome tags in 20 lessons; Topic 35 maps all 12 polymerisation outcome tags in 16 lessons; Topic 36 maps all four organic-synthesis outcome tags in 14 lessons; Topic 37 maps all 22 chromatography and NMR outcome tags in 18 lessons. Cambridge's 2028–2030 Version 1 syllabus states that there are no significant changes which affect teaching from the preceding edition; the routes are aligned to that edition. This is 37 of the 37 numbered subject-content topics. Full cumulative exam assessment, Paper 3 laboratory competence, Paper 5 investigation practice and human subject-teacher review remain outstanding. Written practice is self-checked and does not certify exam readiness.

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