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IGCSE · Cambridge (CIE) · 0444

Verify right angles and measures using slopes and distances

Check perpendicularity with finite slopes or axis directions · Verify a right-angle claim with squared distances · Avoid applying triangle formulae to collinear data

Section Paper 2 · Historical Extended · non-calculator

Mathematics (US) 0444 · historical 2025 study · E7.2 / E7.6
Exam scope and assessment notes

Extended content; not a Core requirement. Historical study of Cambridge IGCSE Mathematics (US) 0444, 2025 Version 2. The final assessment was June 2025; the syllabus was available only to schools in Arizona, USA. This is not a current exam-entry option. Original self-check teaching and explained practice are not Cambridge papers, official marks or predicted grades. Linked teaching foundations do not establish full syllabus mastery. Calibrated cumulative assessment, reliable drawn-work review and qualified mathematics-teacher review remain unfinished.

Before you begin

  • Distance formula
  • Perpendicular slopes and triangle area

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

What should you establish before applying the method in this lesson?

What you will learn

  • Check perpendicularity with finite slopes or axis directions
  • Verify a right-angle claim with squared distances
  • Avoid applying triangle formulae to collinear data
Check the angle at the named vertexxy-2-10123456-2-1123456ABCEqual x and y unit lengths
The triangle has A(1,1), B(5,3), C(0,3). Use AB and AC to test the angle at A. The blue sides meet at the named vertex; equal axis units support the geometry. Verify with slopes or squared distances rather than appearance alone.

Two checks should agree

For A(1,1), B(5,3), C(0,3), slopes AB=1/2 and AC=−2 have product −1, establishing a right angle at A. Independently, AB²=20, AC²=5 and BC²=25, so the converse of Pythagoras gives the same result. Use the two sides meeting at the named angle, not an unrelated slope pair.

Calculate after establishing the condition

The perpendicular legs have lengths 2√5 and √5. Area=(1/2)(2√5)(√5)=5 square units, and perimeter=2√5+√5+5=5+3√5 units. If the points are collinear there is no non-degenerate triangle, even though pairwise distances can still be calculated. A drawn angle alone is not proof.

Sources for this lesson

Pause and explain

What do finite slopes 1/2 and −2 tell you about their line directions?

Put the idea to work

Worked example

Verify the right angle and find the area of the illustrated triangle.

Show the worked solution
  1. The slopes from A are 1/2 and −2, with product −1; squared lengths also satisfy 20+5=25.
  2. Area=(1/2)√20√5=5.

Answer Right angle at A; area 5 square units.

Try a topic test

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Pairs of distinct lines have slopes (3,−1/3) and (3,3). Classify each pair.

Give me a hint

Compare products for perpendicularity and equality for parallelism.

Compare my reasoning
  1. The first pair multiplies to −1, so is perpendicular.
  2. The second pair has equal finite slopes and distinct lines, so is parallel.

First: perpendicular; second: parallel.

Look for these in your work

  • Apply the right test
  • Use the distinct-line condition
2 · Independent

For the illustrated A(1,1), B(5,3), C(0,3), verify the right angle and find area and perimeter.

Give me a hint

Use slopes and exact distances.

Compare my reasoning
  1. AB slope=1/2, AC slope=−2, so the right angle is at A. Lengths are √20, √5 and 5.
  2. Area=5 square units; perimeter=5+3√5 units.

Right angle at A; area 5 square units; perimeter 5+3√5 units.

Look for these in your work

  • Establish perpendicular legs
  • Keep exact measures
3 · Transfer

For A(0,0), B(2,1), C(4,2), test a claim of a right angle at B and a positive triangle area.

Give me a hint

Compare directions and the distance relation.

Compare my reasoning
  1. AB and BC both have slope 1/2, so are collinear, not perpendicular.
  2. AB=BC=√5 and AC=2√5; no enclosed triangle exists, so area=0.

The claims are false; the points are collinear and area is 0.

Look for these in your work

  • Reject inconsistent angle claims
  • Recognise degenerate geometry

Common mistakes

  • Use the segments meeting at the angle being tested.
  • A visual resemblance to 90° is not enough.
Recall without your notes

What can you explain now?

What do finite slopes 1/2 and −2 tell you about their line directions?

Compare with the explanation

They are perpendicular.

Their product is −1, meeting the non-zero finite-slope condition.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

What do finite slopes 1/2 and −2 tell you about their line directions?

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Mathematics (US)

Course scope and assessment

191 original lessons provide 573 guided, independent and application tasks. All 142 tier entries have linked teaching foundations: 55 Core and 87 Extended entries across 87 unique numbered sections in ten areas. Extended includes Core, so the tier-entry count is not a percentage of teaching time or student mastery. This is not full programme completion: qualified mathematics-teacher review, cumulative and exam-length assessment, and reliable drawn-work review remain unfinished. Historical study of Cambridge IGCSE Mathematics (US) 0444, 2025 Version 2. The final assessment was June 2025; the syllabus was available only to schools in Arizona, USA. This is not a current exam-entry option. Original self-check teaching and explained practice are not Cambridge papers, official marks or predicted grades. Linked teaching foundations do not establish full syllabus mastery. Calibrated cumulative assessment, reliable drawn-work review and qualified mathematics-teacher review remain unfinished.

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