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IGCSE · Cambridge (CIE) · 0444

Estimate a grouped mean using class midpoints

Calculate class midpoints · Weight midpoint values by frequencies · Explain why the result is an estimate

Section Paper 2 · Historical Extended · non-calculator

Mathematics (US) 0444 · historical 2025 study · E10.4
Exam scope and assessment notes

Extended content; not a Core requirement. Historical study of Cambridge IGCSE Mathematics (US) 0444, 2025 Version 2. The final assessment was June 2025; the syllabus was available only to schools in Arizona, USA. This is not a current exam-entry option. Original self-check teaching and explained practice are not Cambridge papers, official marks or predicted grades. Linked teaching foundations do not establish full syllabus mastery. Calibrated cumulative assessment, reliable drawn-work review and qualified mathematics-teacher review remain unfinished.

Before you begin

  • Frequency-weighted means
  • Continuous class intervals

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

What should you establish before applying the method in this lesson?

What you will learn

  • Calculate class midpoints
  • Weight midpoint values by frequencies
  • Explain why the result is an estimate
Class midpoints give an estimateTime classCountMidpoint0 ≤ t < 102510 ≤ t < 2051520 ≤ t < 30325Time in minutes · ten observationsEstimated mean = 160/10 = 16 min
The equal-width time classes 0≤t<10, 10≤t<20 and 20≤t<30 have frequencies 2,5,3 and midpoints 5,15,25. Midpoint-weighted total 160 divided by ten observations estimates mean 16 minutes. Individual times, exact mean, exact median and observed extrema are not recovered by this grouped table.

Replace unknown individual values by representatives

For classes 0≤t<10, 10≤t<20 and 20≤t<30 with frequencies 2,5,3, use midpoints 5,15,25. The estimated total is 2×5+5×15+3×25=160, over ten observations, giving estimated mean 16 minutes. The original times within the classes are unknown.

An estimate is not an exact reconstruction

Midpoint weighting represents each observation by its class center. It is useful when the within-class values are unavailable, but different actual data can have the same grouped frequencies and different exact means. An open-ended class needs additional information or an explicit representative-value assumption before this method can be applied.

Sources for this lesson

Pause and explain

Does a midpoint mean equal the exact mean of the hidden individual observations?

Put the idea to work

Worked example

Estimate the mean for the illustrated grouped table.

Show the worked solution
  1. Midpoints are 5,15,25 and the weighted total is 160.
  2. Total frequency is 10.

Answer Estimated mean 16 min.

Try a topic test

Choose Easy, Normal or Difficult. Save your answers and open worked review after finishing.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

For the illustrated frequencies 2,5,3 in ten-minute classes from 0 to 30, estimate the mean.

Give me a hint

Use midpoints 5,15,25.

Compare my reasoning
  1. Weighted total=10+75+75=160.
  2. Divide by total frequency 10.

Estimated 16 min.

Look for these in your work

  • Use class midpoints
  • Retain frequency weights
2 · Independent

Classes 0≤x<4 and 4≤x<10 have frequencies 3 and 2. Estimate the mean.

Give me a hint

Midpoints are 2 and 7, despite unequal widths.

Compare my reasoning
  1. Estimated total=3×2+2×7=20.
  2. Total frequency is five.

Estimated mean 4.

Look for these in your work

  • Find each midpoint from its own boundaries
  • Divide by the frequency total
3 · Transfer

Two values are known only to lie in 0≤x<10. Can the grouped midpoint estimate 5 be claimed as their exact mean? Give two compatible actual data sets.

Give me a hint

Compare values near the two ends of the interval.

Compare my reasoning
  1. The data 1,1 have mean 1.
  2. The data 9,9 have mean 9; both share the same grouped count.

No; (1,1) and (9,9) are counterexamples with means 1 and 9.

Look for these in your work

  • Demonstrate the lost information
  • Separate estimate from exact value

Common mistakes

  • Weight midpoints by frequencies.
  • State that the original measurements are unknown.
Recall without your notes

What can you explain now?

Does a midpoint mean equal the exact mean of the hidden individual observations?

Compare with the explanation

Not necessarily; it is an estimate.

Measurements can lie anywhere inside their stated classes.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

Does a midpoint mean equal the exact mean of the hidden individual observations?

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Mathematics (US)

Course scope and assessment

191 original lessons provide 573 guided, independent and application tasks. All 142 tier entries have linked teaching foundations: 55 Core and 87 Extended entries across 87 unique numbered sections in ten areas. Extended includes Core, so the tier-entry count is not a percentage of teaching time or student mastery. This is not full programme completion: qualified mathematics-teacher review, cumulative and exam-length assessment, and reliable drawn-work review remain unfinished. Historical study of Cambridge IGCSE Mathematics (US) 0444, 2025 Version 2. The final assessment was June 2025; the syllabus was available only to schools in Arizona, USA. This is not a current exam-entry option. Original self-check teaching and explained practice are not Cambridge papers, official marks or predicted grades. Linked teaching foundations do not establish full syllabus mastery. Calibrated cumulative assessment, reliable drawn-work review and qualified mathematics-teacher review remain unfinished.

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