Define geometric waiting times starting at the first trial
Count the trial of the first success from 1 and distinguish it from the number of failures before success.
Exam scope and assessment notes
Probability & Statistics 1 (Paper 5, AS & A Level) · Mathematics 9709, 2026–2027, section 5.4. A probability table needs non-negative probabilities summing to one. E(X) is a probability-weighted mean; Var(X) = E(X²) − [E(X)]², with squared units. A binomial model B(n,p) counts successes in a fixed non-negative integer number n of independent two-outcome trials with a constant success probability p. A geometric model Geo(p) counts the trial of the first success, starting at 1, with independent trials and a constant 0 < p ≤ 1. Formula proofs are not required. The expectation of the geometric distribution is required; its variance is not required by section 5.4. Normal approximations belong to section 5.5 and are not used here. Exact model probabilities do not establish real-world independence or constant rates without evidence. Written practice is self-checked; human subject-teacher review remains pending.
Before you begin
- Identify success and failure outcomes.
- Recognise independence and conditional probabilities.
Work on paper. Try each question before revealing help, and explain why your method works.
Quick readiness check
For outcomes failure, failure, success, what is the first-success trial?
What you will learn
- Define the Cambridge geometric variable and its support.
- Check independence and constant probability in a stopping experiment.
The random variable is the trial number
T ~ Geo(p) counts the trial on which the first success occurs. Trials are independent and each has the same success probability p, with 0 < p ≤ 1. The possible values are 1, 2, 3, …, because success may occur on the very first trial. Cambridge section 5.4 uses this convention.
If the observed sequence is failure, failure, success, then T = 3, while the number of failures before success is T − 1 = 2. These variables have different supports. A formula for the failure count cannot be copied unchanged onto T. Define which variable an event describes before using a calculator or another textbook’s convention.
A stopping rule does not guarantee a geometric model
Rolling a fair die independently until the first six gives T ~ Geo(1/6). The number of rolls is random and the first-six probability remains 1/6 on each roll. This contrasts with a binomial experiment, where the total number of trials is fixed in advance and the variable counts successes.
Drawing without replacement from two red and three blue until the first red is not geometric: removal changes conditional probabilities, creates dependence and limits the first-red trial to at most 4. At p = 1, T = 1 with certainty. At p = 0, no finite first-success trial exists, so it does not define the geometric variable used here. The infinite support for 0 < p < 1 is a model property, not a promise about real-world trial conditions staying constant forever.
Pause and explain
Independent fair die rolls stop at the first six. Which model describes its trial number T?
Worked example
Independent trials each have success probability 1/4. The first outcomes are failure, failure, success. State T and the failure count.
Show the worked solution
- T counts the trial of the first success, starting at one.
- The first success occurs on trial three, so T = 3.
- There were T − 1 = 2 failures beforehand.
Answer T = 3; failures before success = 2.
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Test this topic →From guided practice to a new situation
Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.
Trials are independent with success probability 1/4. Outcomes are failure, failure, success. State T and the number of failures before success.
Give me a hint
Include the successful trial in T, then subtract one for failures.
Compare my reasoning
- The first success is on trial three.
- Thus T = 3 under the first-trial convention.
- The preceding failure count is T − 1 = 2.
T = 3; two failures before success.
Look for these in your work
- State the first-success convention.
- Keep the two variable definitions distinct.
A fair die is rolled independently until the first six. Define T, its distribution and support.
Give me a hint
The common probability is that of a six on one roll.
Compare my reasoning
- Let T be the trial number of the first six.
- Each independent roll has p = 1/6.
- Write T ~ Geo(1/6), with support 1, 2, 3, … .
T ~ Geo(1/6); support 1, 2, 3, … .
Look for these in your work
- Define the waiting variable explicitly.
- Explain the constant probability and independence.
Draw without replacement from two red and three blue until the first red. Is its first-red trial geometric? State the possible trial numbers.
Give me a hint
Compare conditional probabilities after removals and the latest possible first red.
Compare my reasoning
- Initially red has probability 2/5; after one blue it becomes 2/4.
- Removal changes probabilities and makes trials dependent, so the model is not geometric.
- The first red can occur on trials 1, 2, 3 or 4; three blues are the maximum preceding failures.
Not geometric; possible first-red trials are 1–4.
Look for these in your work
- Identify the failed assumptions using the mechanism.
- Distinguish finite support from geometric support.
Common mistakes
- The first-success variable starts at 1.
- Failure count and first-success trial differ by one.
- Without replacement does not supply a constant independent success probability.
What can you explain now?
What value does T take if the first trial succeeds?
Compare with the explanation
T = 1.
The variable counts the successful trial itself, not just preceding failures.
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Make it stick
For Geo(p), define T as the first-success trial beginning at 1, then check independent trials and constant positive p.
If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.