Integrate natural exponential composites by reversing their inner scale
Divide by a non-zero linear inner coefficient, keep the integration constant and check accumulated quantities against their rate.
Exam scope and assessment notes
Pure Mathematics 2 (Paper 2, AS only) and Pure Mathematics 3 (Paper 3, A Level) · Mathematics 9709, 2026–2027. Shared sections 2.5 and 3.5 use these standard exponential, reciprocal and trigonometric integrals and identity methods. Paper 1 integration and the shared derivatives and identities are assumed. The AS route using Papers 1 + 2 cannot be carried forward to A Level. The general method of integration by substitution is not required for Paper 2; Paper 3 uses given substitutions in its separate lesson. Paper 3 also adds positive-quadratic reciprocals, partial fractions, logarithmic derivative patterns and integration by parts. Use radians for trigonometric calculus. Written practice is self-checked; human subject-teacher review remains pending.
Before you begin
- Differentiate natural exponential composites with the chain rule.
- Use an integration constant and evaluate a definite integral.
Work on paper. Try each question before revealing help, and explain why your method works.
Quick readiness check
What is d(e^(3x))/dx?
What you will learn
- Integrate constant multiples, sums and differences of e^(ax + b), including negative a.
- Use an initial condition or definite integral and distinguish an accumulated increase from a total.
Reverse the exponential's chain multiplier
For a ≠ 0, ∫e^(ax + b) dx = e^(ax + b)/a + C. Differentiation multiplies by a, so integration divides by it. The exponential retains its complete original argument; it does not become a power with a new exponent. A negative inner coefficient produces a negative divisor. For example, ∫e^(−2x) dx = −e^(−2x)/2 + C, whose derivative is the positive integrand.
Integrate constant multiples and sums term by term. Thus ∫[3e^(2x) − 4e^(−x)] dx = (3/2)e^(2x) + 4e^(−x) + C. The second sign becomes positive because the outside −4 is divided by inner coefficient −1. One arbitrary constant suffices for the whole antiderivative on its connected domain. If a = 0, the integrand eᵇ is constant and its integral is eᵇx + C; do not divide by zero.
Check both a derivative and any supplied condition
If y′ = 6e^(2x) and y(0) = 5, first obtain y = 3e^(2x) + C. The initial value gives 5 = 3 + C, so y = 3e^(2x) + 2. Differentiation checks the rate, while substitution checks the original value; these are separate requirements. A definite integral uses F(b) − F(a), so the same additive constant cancels.
For a supplied inflow q(t) = 4e^(t/2) litres per minute on 0 ≤ t ≤ 2, an antiderivative is 8e^(t/2). The added volume is 8(e − 1) litres. If a vessel starts with 7 litres and has no outflow, its final total is 7 + 8(e − 1) = 8e − 1 litres. Integrating a rate gives an increase; an initial stock must be added separately when the question asks for a total.
Pause and explain
How should ∫e^(0x + b) dx be handled?
Worked example
Integrate 3e^(2x) − 4e^(−x) and verify the signs by differentiation.
Show the worked solution
- Divide the first coefficient by inner rate 2 to obtain (3/2)e^(2x).
- Divide the second coefficient −4 by inner rate −1 to obtain +4e^(−x).
- Add C and differentiate both terms, recovering 3e^(2x) − 4e^(−x).
Answer (3/2)e^(2x) + 4e^(−x) + C.
Try a topic test
Choose Easy, Normal or Difficult. Save your answers and open worked review after finishing.
Test this topic →From guided practice to a new situation
Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.
Integrate 5e^(3x + 1) − 2e^(−4x) and check your answer.
Give me a hint
Divide each coefficient by its own signed inner rate.
Compare my reasoning
- The first term integrates to (5/3)e^(3x + 1).
- The second term integrates to (1/2)e^(−4x), because −2/(−4) = 1/2.
- Add C; differentiation gives 5e^(3x + 1) − 2e^(−4x), recovering both signs.
(5/3)e^(3x + 1) + (1/2)e^(−4x) + C.
Look for these in your work
- Retain each original exponential argument and signed inner scale.
- Verify both terms by differentiation and retain C.
A curve has y′ = 6e^(2x) and passes through (0, 5). Find its equation and check both conditions.
Give me a hint
Find an antiderivative before substituting the original point.
Compare my reasoning
- Integration gives y = 3e^(2x) + C.
- At x = 0, 5 = 3 + C, so C = 2.
- The curve y = 3e^(2x) + 2 has the required derivative and value 5 at zero.
y = 3e^(2x) + 2.
Look for these in your work
- Reverse the inner factor 2 before determining C.
- Check both the derivative and the original point.
A vessel initially holds 7 litres. Its supplied inflow is q(t) = 4e^(t/2) litres per minute for 0 ≤ t ≤ 2, with no outflow. Find the added volume and final total exactly.
Give me a hint
Use a definite integral for the increase, then include the initial stock only in the total.
Compare my reasoning
- An antiderivative of q is 8e^(t/2).
- The added volume is 8e − 8 = 8(e − 1) litres.
- Adding the initial 7 litres gives final total 8e − 1 litres.
Added volume 8(e − 1) litres; final total 8e − 1 litres.
Look for these in your work
- Use the interval endpoints in the correct order.
- Distinguish accumulated increase, initial stock and final total with matching units.
Common mistakes
- Reverse the inner multiplier by division, including its sign.
- Keep C for an indefinite integral, and use a supplied value only after integrating.
- An integral of a flow rate gives added volume, not automatically the final stock.
What can you explain now?
Find ∫e^(−2x) dx.
Compare with the explanation
−e^(−2x)/2 + C.
Differentiating multiplies by −2, cancelling the divisor and returning the original positive exponential.
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Make it stick
Explain why a linear exponential integral divides by its inner coefficient. Check a negative-coefficient example and distinguish a flow integral from a final stored quantity.
If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.