Use curve shape to judge trapezium overestimates and underestimates
Compare straight chords with a curve, distinguish curvature from whether it rises or falls, and preserve the sign of the estimated integral.
Exam scope and assessment notes
Pure Mathematics 2 (Paper 2, AS only) · Mathematics 9709, 2026–2027. Paper 1 integration and Paper 2 derivatives and identities are assumed. The AS route using Papers 1 + 2 cannot be carried forward to A Level. Section 2.5 covers reverse differentiation of linear-composite exponentials, reciprocals and trigonometric functions, integration using trigonometric relationships, and trapezium estimates with sketch-based over/under-estimation. The general method of integration by substitution is not required here. Use radians for trigonometric calculus. Written practice is self-checked.
Before you begin
- Calculate a trapezium estimate and an elementary definite integral.
- Read a graph's bending direction and distinguish integral from geometric area.
Work on paper. Try each question before revealing help, and explain why your method works.
Quick readiness check
Does an increasing graph alone tell you the sign of its trapezium error?
What you will learn
- Use a sketch to decide whether trapezium chords lie above or below a curve.
- Explain signed over/under-estimation, exact straight-line cases and the limitation when curvature changes.
The chord's position decides the estimate direction
When a curve bends upward throughout an interval, like y = x², its chords lie on or above the curve, so the trapezium estimate is at least the signed integral. When it bends downward, like y = 4 − x² on [0, 2], the chords lie on or below it, giving an underestimate. For smooth examples, the signs f″ ≥ 0 and f″ ≤ 0 respectively confirm those shapes, but the simple sketch comparison itself explains the area relationship.
With two equal intervals on [0, 2], x² gives T = 3 while its exact integral is 8/3, an overestimate by 1/3. For 4 − x², the corresponding T is 5 while the exact integral is 16/3, an underestimate by 1/3. A straight line agrees exactly with its chord, so the trapezium rule is exact on each such strip. Rising or falling alone does not determine the direction: an increasing curve can bend either upward or downward.
A signed overestimate need not mean a larger geometric area
For x² − 4 on [0, 2], the curve is below the axis and bends upward. Its two-strip estimate is −5, greater than exact signed integral −16/3, so it is a signed overestimate. The corresponding positive geometric areas are 5 and 16/3: the straight-sided area magnitude is smaller. State which quantity is being compared rather than replace every negative ordinate by its magnitude without explaining the changed question.
If the curve changes bending direction, some chords may lie above and others below. A single whole-interval sketch label need not establish the total error's sign; inspect the separate strips or compare with an independently known integral. For sin x on [0, 2π] with four equal intervals, symmetry gives signed trapezium estimate 0 and exact integral 0 even though the curve bends differently in its two halves. This cancellation does not imply that its total geometric area is zero: that exact area is 4. A smaller mesh often improves these smooth examples, but an observed change between estimates is not a guaranteed error bound.
Pause and explain
For a below-axis upward-bending curve, what does a chord above it imply?
Worked example
Compare two-strip trapezium estimates with exact integrals for x² and 4 − x² on [0, 2], explaining the direction from their sketches.
Show the worked solution
- For x², ordinates 0, 1, 4 give T = 3, above exact integral 8/3; the chords lie above the upward-bending curve.
- For 4 − x², ordinates 4, 3, 0 give T = 5, below exact integral 16/3; the chords lie below the downward-bending curve.
- Both comparisons use the signed integral. Their exact differences are +1/3 and −1/3 respectively.
Answer x²: overestimate 3 versus 8/3. 4 − x²: underestimate 5 versus 16/3.
Try a topic test
Choose Easy, Normal or Difficult. Save your answers and open worked review after finishing.
Test this topic →From guided practice to a new situation
Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.
For f(x) = x² − 4 on [0, 2], find its two-strip trapezium estimate and exact integral. Explain both the signed and geometric comparisons.
Give me a hint
Use ordinates −4, −3, 0, retaining their signs, then integrate the polynomial.
Compare my reasoning
- T = (1/2)[−4 + 0 + 2(−3)] = −5.
- The exact integral is [x³/3 − 4x] from 0 to 2 = −16/3, so −5 is a signed overestimate.
- The positive straight-sided area magnitude 5 is below exact geometric area 16/3; the curve is non-positive throughout.
Signed estimate −5 versus exact −16/3: overestimate. Positive area magnitude 5 versus 16/3: underestimate.
Look for these in your work
- Keep the ordinates signed when estimating the integral.
- Explain why the geometric magnitude comparison differs.
Use two equal intervals to estimate ∫ from 0 to 4 of √x dx and compare with its exact value. Explain why an increasing graph gives an underestimate here.
Give me a hint
The width is 2 and the graph bends downward; use ordinates 0, √2, 2.
Compare my reasoning
- The estimate is (2/2)[0 + 2 + 2√2] = 2 + 2√2.
- The exact integral is [(2/3)x^(3/2)] from 0 to 4 = 16/3.
- Since 2 + 2√2 < 16/3, the estimate is low: the increasing but downward-bending curve lies above its chords.
Estimate 2 + 2√2 < exact 16/3; an underestimate despite the curve increasing.
Look for these in your work
- Use the correct width and exact ordinates.
- Justify the estimate direction by chord position rather than increasing behaviour alone.
For sin x on [0, 2π], use four equal trapezium intervals. Compare the signed estimate with the exact integral and explain why it does not describe total area.
Give me a hint
Use the symmetric ordinates 0, 1, 0, −1, 0 and inspect both lobes.
Compare my reasoning
- With h = π/2, opposite interior ordinates cancel, giving T = 0.
- The exact signed integral is [−cos x] from 0 to 2π = 0; the agreement comes from cancellation in this case, not one fixed bending direction.
- The exact total area is 2 + 2 = 4, found by splitting at π; a zero signed integral does not mean no area.
Signed estimate and exact integral are both 0; exact total geometric area is 4.
Look for these in your work
- Use signed ordinates and recognise symmetry-based cancellation.
- Separate a signed estimate from geometric area and avoid a whole-interval curvature claim.
Common mistakes
- Increasing does not automatically mean overestimate, and decreasing does not automatically mean underestimate.
- For a below-axis curve, compare signed integrals separately from positive area magnitudes.
- Changed curvature or changed mesh alone does not establish a universal total-error bound.
What can you explain now?
Is the trapezium rule exact for a straight-line function on each strip?
Compare with the explanation
Yes.
The straight interpolation coincides with the original function, so there is no gap between chord and curve.
After trying it yourself, choose your next review. This is your self-assessment.
Your review choice appears on Today. Sign in to sync it across devices.
Make it stick
Sketch one upward-bending and one downward-bending example and compare their chords with the curves. Explain a below-axis case and why mixed curvature needs more care.
If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.