A Level · Cambridge (CIE) · 9709

Use integration by parts and given substitutions in differential equations

Integrate a product on the independent-variable side, use a supplied substitution and check the interval after taking tangent or exponential.

Pure Mathematics 3 · Differential equations · 3.8

Exam scope and assessment notes

Pure Mathematics 3 (Paper 3, A Level) · Mathematics 9709, 2026–2027, section 3.8. Paper 1 calculus and Paper 3 Integration are assumed. This pathway uses first-order separable equations, including Paper 3 integration methods, with all context assumptions supplied. Second-order equations and integrating-factor methods are beyond this mapped requirement. Check factors before dividing, retain equilibrium solutions, and state the interval and physical meaning of an initial-value solution. Written practice is self-checked; human subject-teacher review remains pending.

Before you begin

Use integration by parts with exponential and trigonometric functions.
Transform a given substitution and differentiate composite tangent or exponential functions.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

With u = t², which differential replaces t dt?

What you will learn

Apply single or repeated parts and a given substitution after separating variables.
Use the initial value and verify a composite solution without losing its allowed interval.

Choose a method after the equation is separated

For dy/dx = xe^(−x)(1 + y²), separation gives dy/(1 + y²) = xe^(−x) dx. On the right, parts with u = x and dv = e^(−x) dx gives −(x + 1)e^(−x) + C. With y(0) = 0, arctan y = 1 − (x + 1)e^(−x). For x ≥ 0 this angle increases from 0 towards 1 radian, remaining below π/2; taking tangent therefore defines a finite solution throughout that forward interval.

Repeated parts can arise in the same way. For y′ = x²e^(−x)y and y(0) = 1, integrate dy/y = x²e^(−x) dx using parts twice to obtain ln y = 2 − (x² + 2x + 2)e^(−x). Thus y = exp[2 − (x² + 2x + 2)e^(−x)]. Differentiate the exponent to check x²e^(−x), and then apply the exponential chain rule. The original equation separately has equilibrium y = 0.

Transform the independent variable consistently

For dy/dt = te^(t²)(1 + y²), a given substitution u = t² gives du = 2t dt. Consequently ∫te^(t²) dt = (1/2)e^(t²) + C. With y(0) = 0, arctan y = (e^(t²) − 1)/2. The tangent solution stays on the branch through zero only while that angle lies between −π/2 and π/2. For forward t this requires 0 ≤ t < √ln(1 + π).

A trigonometric product may instead need parts: ∫x cos x dx = x sin x + cos x + C. If it becomes an inverse-tangent relation, the final solution's interval must also exclude tangent poles. Verify the primitive before composing it with tangent or exponential. A valid integral is only one step: an incorrect initial constant, branch or inner derivative still produces an incorrect differential-equation solution.

Pause and explain

If arctan y = F(x), can y = tan F(x) be continued through a tangent pole as the same finite solution?

Put the idea to work

Worked example

Solve y′ = xe^(−x)(1 + y²), y(0) = 0, for x ≥ 0.

Show the worked solution

Separate and integrate: arctan y = −(x + 1)e^(−x) + C.
The initial condition gives C = 1, hence y = tan[1 − (x + 1)e^(−x)].
The inner derivative is xe^(−x), so y′ = xe^(−x)(1 + y²); the inner angle stays in [0,1) for x ≥ 0.

Answer y = tan[1 − (x + 1)e^(−x)], x ≥ 0.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Solve y′ = xe^x y with y(0) = 2.

Give me a hint

Separate dy/y = xe^x dx and integrate the product by parts.

Compare my reasoning

Parts gives ∫xe^x dx = (x − 1)e^x + C.
The initial condition gives ln 2 = −1 + C, hence ln y = (x − 1)e^x + 1 + ln 2.
Thus y = 2exp[(x − 1)e^x + 1]; its exponent derivative is xe^x and its value at zero is 2.

y = 2exp[(x − 1)e^x + 1], for all real x.

Look for these in your work

Apply parts and the initial condition with the correct constant.
Check the exponential chain rule against the original equation.

2 · Independent

Solve y′ = x cos x(1 + y²), y(0) = 1, stating the branch condition around zero.

Give me a hint

Integrate x cos x by parts on the separated x side.

Compare my reasoning

Integrate to obtain arctan y = x sin x + cos x + C.
At zero, π/4 = 1 + C, so C = π/4 − 1.
The solution is tan[x sin x + cos x + π/4 − 1], on the interval through zero where the inner angle stays between −π/2 and π/2.

y = tan[x sin x + cos x + π/4 − 1], on the branch through zero with inner angle in (−π/2, π/2).

Look for these in your work

Keep the positive cos x term from parts.
Use the initial angle and exclude poles of the composed tangent.

3 · Transfer

A supplied dimensionless response obeys dy/dt = te^(t²)(1 + y²), y(0) = 0. Use the given substitution u = t² to find y and its value at t = √ln 2, on the forward branch.

Give me a hint

The given substitution converts t dt to du/2.

Compare my reasoning

Separation and substitution give arctan y = (1/2)e^(t²) + C.
The initial value gives C = −1/2, so y = tan[(e^(t²) − 1)/2], for 0 ≤ t < √ln(1 + π).
At t = √ln 2 the inner angle is 1/2 radian, giving y = tan(1/2), approximately 0.546.

y = tan[(e^(t²) − 1)/2], 0 ≤ t < √ln(1 + π); requested value tan(1/2) ≈ 0.546.

Look for these in your work

Use the given substitution with its differential multiplier.
Check the forward branch and evaluate the dimensionless response in radians.

Common mistakes

Integrate the separated product rather than integrating its factors independently.
Keep the factor 1/2 from the given substitution u = t².
Check the allowed angle interval before composing an implicit result with tangent.

Recall without your notes

What can you explain now?

What is ∫xe^(−x) dx?

Compare with the explanation

−(x + 1)e^(−x) + C.

Differentiating by the product rule cancels the constant exponential term and leaves xe^(−x).

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Make it stick

Separate before choosing an integration method. Verify a parts or substitution primitive, apply the initial condition and check the domain of the final composition.

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Mathematics

Check the official syllabus 2026–2027

Course scope and assessment

312 sequenced lessons provide 936 guided, independent and application problems covering the 160 objectives in sections 1.1–1.8, 2.1–2.6, 3.1–3.9, 4.1–4.5, 5.1–5.5 and 6.1–6.5. The map lists all 38 sections across six alternative components; all eight Pure Mathematics 1 sections and all six Pure Mathematics 2 sections, from Paper 2 Algebra through Numerical solution of equations, currently have full teaching sequences. Paper 3 Algebra, section 3.1, links the six shared foundation lessons plus six lessons on partial fractions and rational binomial expansions; Paper 3 logarithms, trigonometry and numerical equations use the shared lessons, with the Paper 1 graph foundation linked into trigonometry. Paper 3 differentiation combines the shared methods with its inverse-tangent derivative lesson. Paper 3 Integration links four shared standard and identity lessons plus seven advanced lessons, covering all six section 3.5 requirements. Eight Vectors lessons cover all six section 3.7 requirements, with 2D and 3D line and solid applications. Nine Differential equations lessons cover all four section 3.8 requirements, including Paper 3 integration techniques, initial conditions, equilibrium solutions and conditional model interpretations. Eleven Complex numbers lessons cover all eight section 3.9 requirements, with seven Argand diagrams and explicit argument and boundary checks. All nine Pure Mathematics 3 sections now have teaching linked to every mapped requirement. Nine Forces and equilibrium lessons cover all seven section 4.1 requirements, with six force diagrams, signed incline-friction intervals, reaction-dependent pull and push limits and separate-body third-law checks. Nine Kinematics lessons cover the four official section 4.2 requirements, with the graph requirement mapped to three relationships. Six motion diagrams support directed quantities, graph slopes and signed areas, Paper 1 time-calculus methods, reversal distances, constant-acceleration stages and shared-clock particle meetings. Six Momentum lessons cover both section 4.3 requirements, including signed system totals, conservation assumptions, outgoing velocities, coalescence, unknown masses and successive impacts. Four diagrams show system momentum through the stipulated events, and supplied kinetic-energy checks distinguish conservation of momentum from changes in kinetic energy. Twelve Newton’s laws lessons cover all four section 4.4 requirements, with vertical support and release stages, rough horizontal and incline motion, inferred parameters, hanging and surface pulley systems, rigid tow-bar thrust and slack-string transitions. Seven force diagrams support the separate-particle balances. Nine Energy, work and power lessons cover all five section 4.5 requirements, with angle-dependent work, kinetic and reference potential energy, signed net-work balances, smooth curved slides, rough and driven slopes, ideal connected-system energy and instantaneous power on hills. Five diagrams distinguish the energy inputs, losses and valid positive-speed force model. All five Mechanics sections now have teaching and staged practice linked to their mapped requirements. Thirteen Representation of data lessons cover all five section 5.1 requirements, including choice and limitations of displays, ordered and back-to-back stems, raw summaries and box plots, unequal-width density histograms, cumulative-frequency interpolation, descriptive moment calculations, grouped estimates, coding, combining two datasets and correcting totals. Six accessible diagrams retain repeated observations and distinguish numerical spread, frequency area and estimated readings. Ten Permutations and combinations lessons cover both official section 5.2 requirements, with selection and ordered roles, repeated objects, adjacency blocks, non-adjacency gaps, leading-zero cases, labelled multi-row seating and mixed restrictions. Six accessible diagrams show outcome trees, ordered versus unordered choices, repeated copies, blocks, gaps and distinct row seats. Eleven Probability lessons cover all four section 5.3 requirements, with equiprobable elementary outcomes, selection-based probabilities, complements and disjoint regions, independence tests, restricted sample spaces, two-way tables, replacement and removal trees, reversed conditions and unknown parameters. Seven accessible diagrams show dice outcomes, random subsets, event regions, a conditioned grid, a count table and two probability trees. Twelve Discrete random variables lessons cover all three official section 5.4 requirements, with complete probability tables, moment and parameter checks, binomial assumptions, exact probabilities and moments, geometric first-success probabilities, tails, expectation and integer reliability thresholds. Six accessible diagrams distinguish outcome grouping, weighted moments, fixed trials, discrete probability bars, waiting conventions and integer tail deadlines. Twelve Normal distribution lessons cover all three official section 5.5 requirements, with continuous-area interpretation, MF19 cumulative tables, full standardisation, tail and interval regions, conditional probabilities, percentiles, one- and two-parameter inference, binomial suitability, continuity corrections and approximate integer thresholds. Seven accessible diagrams show model areas, table reading, aligned scales, intervals, quantiles, matched binomial and normal shapes and whole integer cells. All five Statistics 1 sections now have teaching and staged practice linked to their mapped requirements. Fourteen Poisson distribution lessons cover all five official section 6.1 requirements, with homogeneous event-count assumptions, exposure scaling, exact masses and tails, conditional count events, moments, parameter inference, probability duration targets, disjoint and overlapping windows, rare-count binomial approximations, matched normal approximations and continuity corrections. Nine accessible diagrams show event exposures, unit conversions, discrete bars, complete tail complements, population moments, shared windows, approximate count models and integer cells. Exact checks distinguish approximate and exact close-target decisions. Fourteen Linear combinations lessons cover the six listed results in official section 6.2, with affine moments, signed scales and constant cases, expectation without independence, independent squared variance contributions, fixed and random fees, independent copies versus reused values, affine normal events, independent normal sums and differences, weighted and conditional areas, coefficient inference, exact independent Poisson sums and overlapping exposure limits. Nine accessible diagrams distinguish scale changes, variance contributions, component costs, copy mechanisms, aligned normal scales, summed areas, Poisson count pairs and unsupported distribution claims. Fourteen Continuous random variables lessons cover both official section 6.3 requirements, with density validity and units, support-aware intervals, complements and conditional regions, first and second moments, percentiles by direct density areas, symmetry checks, parameter inference, infinite-support power and exponential integrals, divergent-moment limits and combined applications. Nine accessible diagrams distinguish density height from probability, normalisation, negative-density failures, central and conditional areas, mean versus median, percentile locations and partial infinite tails. Explicit cumulative distribution function knowledge is not required. Eighteen Sampling and estimation lessons cover all eight official section 6.4 requirements, with population and frame definitions, random-number selection, sampling-quality limits, independent sample-mean moments, normal means, CLT conditions, SE scaling, raw, summarised and coded unbiased estimates, known-variance and large-sample mean intervals, repeated-sampling interpretation, precision planning, proportion intervals, sparse-outcome limits and contextual applications. Ten accessible diagrams distinguish selection frames, number rejection, repeated sample means, population versus mean density, CLT models, variance divisors, interval targets, illustrative coverage, integer size checks and proportion margins. Eighteen Hypothesis tests lessons cover all five official section 6.5 requirements, with pre-specified alternatives, inclusive count tails, explicit equal-tail conventions, integer critical regions and actual significance, exposure-aware Poisson tests, continuity-corrected count approximations, normal and large-sample mean tests, confidence-interval connections, error classifications, fixed-region binomial, Poisson and normal error probabilities and sample-size power comparisons. Nine accessible diagrams show the testing procedure, exact count regions, unequal Poisson tails, discrete significance jumps, corrected count boundaries, matching mean intervals and alternative error distributions. All shared lessons are counted once in the course total. All 38 sections now link teaching and practice. Eight earlier overview lessons remain available, but do not count as full section coverage. This is a content-availability measure, not full programme completion or exam readiness. Written practice is self-checked, not officially marked. Check the 2028–2030 syllabus separately if sitting an examination from 2028; this teaching map uses 2026–2027 requirements.