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IGCSE · Cambridge (CIE) · 0444

Add vectors by components and a parallelogram

Add matching components · Translate an arrow for head-to-tail addition · Distinguish the sum's magnitude from a sum of magnitudes

Mathematics (US) 0444 · historical 2025 study · E5.4
Exam scope and assessment notes

Extended content; not a Core requirement. Historical study of Cambridge IGCSE Mathematics (US) 0444, 2025 Version 2. The final assessment was June 2025; the syllabus was available only to schools in Arizona, USA. This is not a current exam-entry option. Original self-check teaching and explained practice are not Cambridge papers, official marks or predicted grades. Linked teaching foundations do not establish full syllabus mastery. Calibrated cumulative assessment, reliable drawn-work review and qualified mathematics-teacher review remain unfinished.

Before you begin

  • Components and magnitude
  • Signed arithmetic

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

What should you establish before applying the method in this lesson?

What you will learn

  • Add matching components
  • Translate an arrow for head-to-tail addition
  • Distinguish the sum's magnitude from a sum of magnitudes
Head-to-tail and parallelogram addition-3-2-10123456-3-2-112345xyOaba + ba =31b =12a+b =43
Vector a is [3; 1] and b is [1; 2]. Shift b unchanged to the head of a for head-to-tail addition. The resultant is [4; 3], the diagonal of the parallelogram, with magnitude 5. Separate magnitudes √10 and √5 do not add to that resultant magnitude. A vector's position can change without changing its components.

Two representations of one sum

For a = [a₁; a₂] and b = [b₁; b₂], a+b = [a₁+b₁; a₂+b₂]. Draw a, then place an unchanged copy of b at its head; the sum arrow joins the first tail to the last head. With both tails at the same point, the parallelogram diagonal gives the same sum.

Changing an arrow's starting location does not change its vector. Addition is commutative, so exchanging the head-to-tail order gives the same endpoint.

Straight displacement and path length

The diagram uses a = [3; 1], b = [1; 2], giving a+b = [4; 3] and magnitude 5. Their separate lengths total √10+√5, which exceeds 5. Magnitudes do not generally add when the directions differ.

Equal same-direction displacements can have additive magnitudes; do not replace the general warning by an always-unequal claim. For [3; 0] then [0; 4], path length is 7 but resultant displacement length is 5.

Sources for this lesson

Pause and explain

Must |a+b| equal |a|+|b|?

Put the idea to work

Worked example

Add [3; 1] and [1; 2] and calculate the sum's magnitude.

Show the worked solution
  1. Component sum is [4; 3].
  2. Its length is √(16+9) = 5, not √10+√5.

Answer Sum [4; 3]; magnitude 5.

Try a topic test

Choose Easy, Normal or Difficult. Save your answers and open worked review after finishing.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Add [2; 1] and [−1; 3].

Give me a hint

Add each pair of matching components.

Compare my reasoning
  1. Horizontal: 2−1 = 1.
  2. Vertical: 1+3 = 4.

[1; 4].

Look for these in your work

  • Match component positions
  • Check signs
2 · Independent

Add [−3; 4] and [2; −6], then find the exact resultant magnitude.

Give me a hint

Calculate the vector before its length.

Compare my reasoning
  1. Sum = [−1; −2].
  2. Magnitude = √(1+4) = √5.

[−1; −2]; magnitude √5.

Look for these in your work

  • Keep direction in the sum
  • Take the length afterwards
3 · Transfer

A walker moves 3 m east then 4 m north. Compare total distance walked with the displacement vector and its length.

Give me a hint

A path and its straight resultant are different.

Compare my reasoning
  1. Distance walked is 3+4 = 7 m.
  2. Displacement is [3; 4] m, whose length is 5 m.

Distance 7 m; displacement [3; 4] m, magnitude 5 m.

Look for these in your work

  • Identify the requested quantity
  • Use the endpoint-to-endpoint displacement

Common mistakes

  • Add horizontal to horizontal and vertical to vertical.
  • The magnitudes of a and b are not generally additive.
Recall without your notes

What can you explain now?

Must |a+b| equal |a|+|b|?

Compare with the explanation

No; different directions can give a shorter resultant.

For perpendicular lengths 3 and 4, the resultant is 5 rather than 7.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

Must |a+b| equal |a|+|b|?

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Mathematics (US)

Course scope and assessment

191 original lessons provide 573 guided, independent and application tasks. All 142 tier entries have linked teaching foundations: 55 Core and 87 Extended entries across 87 unique numbered sections in ten areas. Extended includes Core, so the tier-entry count is not a percentage of teaching time or student mastery. This is not full programme completion: qualified mathematics-teacher review, cumulative and exam-length assessment, and reliable drawn-work review remain unfinished. Historical study of Cambridge IGCSE Mathematics (US) 0444, 2025 Version 2. The final assessment was June 2025; the syllabus was available only to schools in Arizona, USA. This is not a current exam-entry option. Original self-check teaching and explained practice are not Cambridge papers, official marks or predicted grades. Linked teaching foundations do not establish full syllabus mastery. Calibrated cumulative assessment, reliable drawn-work review and qualified mathematics-teacher review remain unfinished.

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