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IGCSE · Cambridge (CIE) · 0625

Calculate electrical energy using current potential difference and time

Use E = IVt for a stated constant electrical input and distinguish energy amounts from input rates.

Electrical energy and power pathway · 4.2.5

Core and Extended; Physics 0625, 2026–2028. Use the stated source, operating conditions and meter ranges. Written practice is self-checked.

Before you begin

  • Calculate power using P = IV.
  • Convert minutes to seconds.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

How many seconds are in 2 minutes?

What you will learn

  • Calculate electrical energy with seconds, amperes and volts.
  • Keep the component's input separate from useful output.
Original staged electrical-energy account uses 0.5 A at 6 V for 20 s and 1 A at 6 V for 10 s. Equal 60 J stage amounts total 120 J, averaging 4 W over 30 s. Rectangular area represents energy; unequal durations must be retained.Add the two stage amountsPower / W3602030Time / s60 J60 JTotal = 120 J over 30 sAverage input power = 4 W
Original staged electrical-energy account uses 0.5 A at 6 V for 20 s and 1 A at 6 V for 10 s. Equal 60 J stage amounts total 120 J, averaging 4 W over 30 s. Rectangular area represents energy; unequal durations must be retained.

Add the duration to the power

For constant matching I and V over a specified interval, E = IVt. Amperes, volts and seconds give joules. A component at 6 V carrying 0.5 A for 120 s receives 6 × 0.5 × 120 = 360 J. Its power is 3 W; 360 J is the accumulated amount over the interval.

Convert time before substitution: two minutes is 120 s, not 2 s. Convert prefixed current as well: 200 mA is 0.200 A. The equation refers to the measured component voltage and current, rather than an unrelated whole-source voltage.

Interpret the input energy

E = IVt gives electrical input under the stated conditions. It does not by itself tell you how much heats a separate water sample or lifts a load. Some energy can increase the device's own internal store or be transferred elsewhere. Use additional measured outputs or efficiency information for those questions.

If current or voltage changes, treat the interval in stated steady stages or use an appropriately supplied average power. A single initial current reading is not proof that it lasted throughout the interval. These practice conditions specify constant d.c. values so the simple product is justified.

Pause and explain

At constant 6 V, 0.5 A and 120 s, what is E?

Put the idea to work

Worked example

Find input energy at constant 6 V and 0.5 A over 2 minutes.

Show the worked solution
  1. Time = 2 × 60 = 120 s.
  2. P = 6 × 0.5 = 3 W.
  3. E = 3 × 120 = 360 J.

Answer 360 J.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Find input energy at 6 V and 0.5 A for 120 s.

Give me a hint

Calculate the electrical input rate and multiply by duration.

Compare my reasoning
  1. P = 6 × 0.5 = 3 W.
  2. t = 120 s.
  3. E = 3 × 120 = 360 J.

360 J.

Look for these in your work

  • State joules.
  • Keep duration explicit.
2 · Independent

Find input energy at 12 V carrying 200 mA steadily for 5 minutes.

Give me a hint

Convert both the current prefix and the time unit first.

Compare my reasoning
  1. I = 0.200 A and t = 300 s.
  2. P = 12 × 0.200 = 2.4 W.
  3. E = 2.4 × 300 = 720 J.

720 J.

Look for these in your work

  • Convert both units.
  • Use the component input.
3 · Transfer

A heater receives 720 J electrically. Is the energy gained by its water necessarily 720 J?

Give me a hint

Check the heater, container and surroundings as well as the water.

Compare my reasoning
  1. The electrical input is known.
  2. Other stores and transfers can take part.
  3. The water's gain is not separately supplied.

No; the water's gain needs further energy-account information.

Look for these in your work

  • Name other destinations.
  • Do not assume all input reaches one sample.

Common mistakes

  • Use seconds for a joule answer.
  • State the constant-condition assumption.
  • Input does not equal useful output without evidence.
Recall without your notes

What can you explain now?

Which quantity is missing if power alone is known but energy is requested?

Compare with the explanation

The transfer duration.

An energy amount needs the power rate and the interval over which it acts.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

Compute a constant electrical input in joules and explain the duration, units and output boundary.

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Physics

Course scope and assessment

491 sequenced Physics lessons provide 1473 guided, independent and application problems. 58 of 58 syllabus sections have full linked teaching sequences; 0 sections remain pending. Three earlier starter overviews remain available but are not counted as full sequences. The map covers all six subject areas for 2026–2028 and keeps review and assessment limits visible. This is available content, not full programme completion, an exam grade or certified mastery. Written practice is self-checked. Supervised practical experience, cumulative assessment and human subject-teacher review remain pending. Paper method exercises do not demonstrate practical competence or complete either practical-assessment route.

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