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IGCSE · Cambridge (CIE) · 0973

Balance the photosynthesis chemical equation

Count atoms while keeping conditions separate from coefficients.

Photosynthesis · Cambridge IGCSE 0973 · B6.1
Exam scope and assessment notes

Mapped to the named 0973 section using teaching from the corresponding single-science course. A 0973-specific review of every Core and Supplement objective is still in progress. Written practice is self-checked; it does not demonstrate supervised laboratory competence or award an official Cambridge grade. This qualification reports two grades on the 9–1 scale; confirm the entry route for your zone and exam series.

Before you begin

  • Recall chloroplasts, enzymes and the difference between photosynthesis and respiration.
  • Use the stated observations, quantities and controls; diagrams are schematic.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

How many oxygen atoms are in 6CO₂?

What you will learn

  • Count atoms while keeping conditions separate from coefficients.
  • Use the stated evidence to explain the method and its limits.
6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂, with light and chlorophyll. Each side contains 6 carbon, 12 hydrogen and 18 oxygen atoms. The coefficients describe the balanced reaction, not a guarantee that all oxygen made appears in a gas collector.Conserve the atom counts6CO₂ + 6H₂OLight + chlorophyllC₆H₁₂O₆ + 6O₂Same atoms on each sideCarbon: 6 · hydrogen: 12Oxygen: 18Reaction ratio ≠ collected gas yield
6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂, with light and chlorophyll. Each side contains 6 carbon, 12 hydrogen and 18 oxygen atoms. The coefficients describe the balanced reaction, not a guarantee that all oxygen made appears in a gas collector.

Use the required overall equation

The Extended balanced chemical equation is 6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂, with light and chlorophyll as conditions. A coefficient multiplies a whole formula; the small subscript belongs to the formula and should not be changed merely to balance the equation.

Carbon counts are 6 on each side and hydrogen counts are 12 on each side. Oxygen on the left totals 12 from carbon dioxide plus 6 from water; the right totals 6 in glucose plus 12 in oxygen gas. Both sides have 18 oxygen atoms in the stated molecule-count model.

Use ratios without inventing yield

The coefficients give the simplified overall ratio 6 carbon dioxide : 6 water : 1 glucose : 6 oxygen. This is not a rate measurement, and a whole plant’s net gas release need not follow that ratio because it also respires and the measurement can miss gas.

For a specified idealised conversion, two glucose molecules correspond to 12 carbon dioxide and 12 water molecules in the overall equation. That count exercise does not require a plant to produce only whole glucose molecules at a particular moment or establish a real experimental yield.

Sources for this lesson

Pause and explain

How many carbon dioxide molecules correspond to two glucose molecules in the stated equation ratio?

Put the idea to work

Worked example

Check whether 6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂ conserves the three atom types.

Show the worked solution
  1. Carbon: 6 left and 6 right.
  2. Hydrogen: 12 left and 12 right.
  3. Oxygen: 12 + 6 = 18 left; 6 + 12 = 18 right.

Answer The equation is balanced: C = 6, H = 12 and O = 18 on each side.

Try a topic test

Choose Easy, Normal or Difficult. Save your answers and open worked review after finishing.

Test this topic →

From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Write the balanced overall photosynthesis equation required for Extended.

Give me a hint

Use the word-equation substances with their fixed formulas.

Compare my reasoning
  1. Place 6 before CO₂ and H₂O.
  2. Use C₆H₁₂O₆ and 6O₂ as products.
  3. Include light and chlorophyll as conditions.

6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂, with light and chlorophyll.

Look for these in your work

  • Correct formulas and coefficients.
  • Retain conditions separately.
2 · Independent

Count total oxygen atoms on each side of the balanced equation.

Give me a hint

Include oxygen in both products and both reactants.

Compare my reasoning
  1. Left: 6 × 2 + 6 × 1 = 18.
  2. Right: 6 in glucose + 6 × 2 = 18.

18 oxygen atoms on each side.

Look for these in your work

  • Include glucose oxygen.
  • Compare both totals.
3 · Transfer

A plant’s collected oxygen release does not match the ideal equation ratio during an experiment. Why is that not automatically evidence that atoms are unbalanced?

Give me a hint

The apparatus observes net collected release, not every reaction molecule.

Compare my reasoning
  1. Respiration uses oxygen.
  2. Some gas can dissolve or escape collection.
  3. The equation is an overall chemical ratio, not a guaranteed collection yield.

Net exchange and collection losses can differ from the overall reaction ratio without violating atom conservation.

Look for these in your work

  • Distinguish equation and measurement.
  • Give at least one relevant experimental effect.

Common mistakes

  • Do not change H₂O into another substance to balance atoms.
  • Coefficients describe a ratio, not a measured gas rate.
Recall without your notes

What can you explain now?

How many carbon dioxide molecules correspond to two glucose molecules in the stated equation ratio?

Compare with the explanation

12.

Each glucose corresponds to six carbon dioxide molecules.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

Reconstruct the equation and independently count each atom type.

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Sciences — Co-ordinated (9-1)

Course scope and assessment

This 9–1 pathway maps all 152 detailed subject-content sections in the published 0973 syllabus for exams in 2028 and 2029. The course map follows the same 2028–2029 section codes as Cambridge's A*–G 0654 syllabus, while keeping 0973's grading and entry rules separate. It adapts lessons from the related single-science courses and excludes clear single-science-only topics. A 0973-specific objective-by-objective review, Core/Supplement audit, human subject-teacher review, supervised laboratory experience and cumulative assessment remain in progress. Written practice is self-checked and does not predict an official grade. The separate 2025–2027 syllabus has not been reconciled here. Cambridge lists 0973 only in a limited number of administrative zones: June in zone 3 and centres in Oman and the UAE; November in zone 3 only. Confirm entry with your centre.

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