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IGCSE · Cambridge (CIE) · 0973

Distinguish chromosome copying from reduction in a meiotic count model

Copying increases DNA amount; reduction changes the complete sets per product nucleus.

Cell division · Cambridge IGCSE 0973 · B16.2
Exam scope and assessment notes

Mapped to the named 0973 section using teaching from the corresponding single-science course. A 0973-specific review of every Core and Supplement objective is still in progress. Written practice is self-checked; it does not demonstrate supervised laboratory competence or award an official Cambridge grade. This qualification reports two grades on the 9–1 scale; confirm the entry route for your zone and exam series.

Before you begin

  • Recall chromosomes, genes and alleles, complete chromosome sets, mitosis and fusion of gamete nuclei.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

Does copying the DNA automatically change a diploid nucleus to haploid?

What you will learn

  • Separate DNA copying from chromosome-set reduction
  • Interpret four-product counts without functional-gamete promises

Original teaching model. Counts, source combinations and sample records are stipulated; drawings are schematic.

Distinguish chromosome copying from reduction in a meiotic count modelCopying increases DNA amount; reduction changes the complete sets per product nucleus.Stipulated n = 3 count modelDiploid precursor: 2n = 61A1B2A2B3A3BDNA copying is preparation1A1B2A2B3A3B6 attached structures; 12 DNA moleculesFinal meiotic products: onecomplete set EACH123Product 1: 3123Product 2: 3123Product 3: 3123Product 4: 3Four boundaries; 3 chromosomes in eachType labels do not show all allelecombinations
Copying increases DNA amount; reduction changes the complete sets per product nucleus.
Chromosome sets, combinations and evidence key
FeatureMeaning
Before copying6 chromosomes represented by 6 DNA molecules
Attached copies6 replicated structures represented by 12 DNA molecules
Four final nuclei3 individual chromosomes in each haploid nucleus
Combined final count4 × 3 = 12 across four nuclei; not per nucleus

Separate DNA copying from chromosome-set reduction

A chromosome can be copied before division, producing attached sister copies. In the supplied count convention, the attached structure is counted as one replicated chromosome until its copies separate. Copying the DNA does not itself remove a chromosome set or make a diploid nucleus haploid. The precursor still represents two corresponding sets; the amount of DNA and the number of sets answer different questions.

Consider a normal schematic with a diploid complement of six. Before copying it has six chromosomes represented by six DNA molecules. After copying it has six replicated chromosome structures represented by twelve DNA molecules. At the end of a complete meiotic model there are four haploid product nuclei, each containing three individual chromosomes. Detailed named stages are not required for this syllabus section.

Interpret four-product counts without functional-gamete promises

Across those four final nuclei, the combined count is twelve chromosomes. In the stipulated no-loss count model that matches the twelve copied DNA molecules distributed among the products. It does not mean the starting diploid nucleus contained twelve chromosomes under the attached-copy convention, and it does not mean each final product has twelve. Keep time point, boundary and counting convention explicit.

The model explains how copying and subsequent division can leave each product with one complete set. It is not a claim that every organism produces four equivalent functional gametes. The number of mature gametes and their later development depend on the supplied biological context. If a question asks only for reduction, state two sets to one and the halved per-nucleus complement instead of inventing unrequested stage names.

Sources for this lesson

Pause and explain

In the supplied n = 3 complete model, how many chromosomes are in each final haploid nucleus?

Put the idea to work

Worked example

Trace a stipulated n = 3 precursor through copying and the final product count.

Show the worked solution
  1. Before copying, six chromosomes are represented by six DNA molecules.
  2. Copying gives six attached replicated structures represented by twelve DNA molecules.
  3. Four final haploid nuclei contain three chromosomes each, twelve across four boundaries.

Answer DNA copying is preparation; two-set to one-set reduction concerns the final complement per nucleus.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

A diploid model has six unreplicated chromosomes. Each is copied with its two sister copies still attached. State the replicated-structure count and DNA-molecule count under the supplied convention.

Give me a hint

Attached sisters remain one replicated structure.

Compare my reasoning
  1. Retain six attached structures.
  2. Count two DNA molecules per structure.

Six replicated chromosome structures and twelve DNA molecules; the precursor remains diploid in this model.

Look for these in your work

  • Six structures
  • Twelve DNA molecules without claiming haploid status
2 · Independent

A stipulated species has n = 4. A complete normal meiotic schematic ends with four haploid nuclei. State the precursor diploid count, each final count and the combined final count.

Give me a hint

Keep 2n, n and four separate nuclei apart.

Compare my reasoning
  1. Calculate 2 × 4 for the precursor.
  2. Use four per haploid nucleus.
  3. Add 4 × 4 only for the combined total.

Eight chromosomes in the diploid precursor, four in each final haploid nucleus and sixteen across the four final nuclei.

Look for these in your work

  • Eight precursor and four per product
  • Sixteen only across four nuclei
3 · Transfer

A student sees twelve DNA molecules after copying in the n = 3 model and concludes reduction has already occurred. Explain the error.

Give me a hint

Copying changes DNA amount; reduction changes complete sets per nucleus.

Compare my reasoning
  1. Identify the six attached replicated structures.
  2. Retain two complete sets at that time point.
  3. Reserve reduction for the later haploid products.

Twelve DNA molecules represent copies in six attached replicated structures. The nucleus still has two sets; the later products are haploid with three chromosomes each. DNA copying alone is not reduction.

Look for these in your work

  • Distinguishes DNA molecules from attached structures
  • Places reduction in the later one-set products

Common mistakes

  • Calling DNA copying a reduction to haploid
  • Counting each attached sister copy as a separate chromosome without stating a different convention
  • Assuming four equivalent functional gametes from a count diagram
Recall without your notes

What can you explain now?

In the supplied n = 3 complete model, how many chromosomes are in each final haploid nucleus?

Compare with the explanation

Three

Each product receives one complete set of three types.

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Make it stick

Without your notes, separate dna copying from chromosome-set reduction and interpret four-product counts without functional-gamete promises. State the chromosome number per nucleus and distinguish chromosome-set reduction from fertilisation.

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Sciences — Co-ordinated (9-1)

Course scope and assessment

This 9–1 pathway maps all 152 detailed subject-content sections in the published 0973 syllabus for exams in 2028 and 2029. The course map follows the same 2028–2029 section codes as Cambridge's A*–G 0654 syllabus, while keeping 0973's grading and entry rules separate. It adapts lessons from the related single-science courses and excludes clear single-science-only topics. A 0973-specific objective-by-objective review, Core/Supplement audit, human subject-teacher review, supervised laboratory experience and cumulative assessment remain in progress. Written practice is self-checked and does not predict an official grade. The separate 2025–2027 syllabus has not been reconciled here. Cambridge lists 0973 only in a limited number of administrative zones: June in zone 3 and centres in Oman and the UAE; November in zone 3 only. Confirm entry with your centre.

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