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IGCSE · Cambridge (CIE) · 0973

Rearrange density equations and convert cubic units

Find mass or volume and convert g/cm³ to kg/m³ using a cubic length conversion.

Density · Cambridge IGCSE 0973 · P1.4
Exam scope and assessment notes

Mapped to the named 0973 section using teaching from the corresponding single-science course. A 0973-specific review of every Core and Supplement objective is still in progress. Written practice is self-checked; it does not demonstrate supervised laboratory competence or award an official Cambridge grade. This qualification reports two grades on the 9–1 scale; confirm the entry route for your zone and exam series.

Before you begin

  • Rearrange a division equation.
  • Cube the factor in a length-unit conversion.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

How many cm³ are in 1 m³?

What you will learn

  • Use m = ρV and V = m/ρ.
  • Convert density and volume units consistently.

Isolate the required quantity

From ρ = m/V, multiply by V to get m = ρV. A material of density 2.7 g/cm³ occupying 15 cm³ has mass 40.5 g. For mass 54 g at density 2.7 g/cm³, rearrange to V = m/ρ = 20 cm³.

Check units before substituting. Multiplying g/cm³ by cm³ leaves g. Dividing g by g/cm³ leaves cm³. If the volume is supplied in m³ while density is in g/cm³, convert one of them first rather than multiplying incompatible numerical values.

A cubic conversion uses the length factor three times

One metre is 100 cm, so one cubic metre contains 100³ = 1,000,000 cm³. Thus 1 cm³ = 10⁻⁶ m³. Also 1 g = 0.001 kg, so 1 g/cm³ = 0.001/10⁻⁶ = 1000 kg/m³. A density of 2.7 g/cm³ is 2700 kg/m³.

For a cross-check, 54 g becomes 0.054 kg and 20 cm³ becomes 0.000020 m³. Dividing gives 2700 kg/m³, the same density. Do not convert cm³ to m³ by dividing by only 100: that is a length conversion, not a volume conversion.

Sources for this lesson

Pause and explain

What is 2.7 g/cm³ in kg/m³?

Put the idea to work

Worked example

Convert 2.7 g/cm³ to kg/m³ and find the volume of 54 g at that density.

Show the worked solution
  1. Multiply the density by 1000 to obtain 2700 kg/m³.
  2. Using the original matched units, V = 54/2.7.
  3. V = 20 cm³ = 0.000020 m³.

Answer 2700 kg/m³; 20 cm³ or 0.000020 m³.

Try a topic test

Choose Easy, Normal or Difficult. Save your answers and open worked review after finishing.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Find the mass of 15 cm³ at density 2.7 g/cm³.

Give me a hint

Multiply density by volume with matching cubic-centimetre units.

Compare my reasoning
  1. Use m = ρV.
  2. 2.7 × 15 = 40.5.
  3. The remaining unit is g.

40.5 g.

Look for these in your work

  • Rearrange correctly.
  • Cancel volume units.
2 · Independent

Find the volume of 54 g at 2.7 g/cm³, then express both density and volume in SI units.

Give me a hint

Calculate in matched units, then apply the mass and cubic-volume factors.

Compare my reasoning
  1. V = 54/2.7 = 20 cm³.
  2. Density is 2700 kg/m³.
  3. Volume is 20 × 10⁻⁶ = 0.000020 m³.

20 cm³; 2700 kg/m³; 0.000020 m³.

Look for these in your work

  • Use m/ρ for volume.
  • Apply the cubic conversion.
3 · Transfer

A liquid density is 800 kg/m³ and its volume is 250 ml. Find mass in kg and g.

Give me a hint

One ml equals one cm³; convert the volume into m³.

Compare my reasoning
  1. 250 ml = 250 cm³ = 0.000250 m³.
  2. m = 800 × 0.000250 = 0.200 kg.
  3. Convert to 200 g.

0.200 kg; 200 g.

Look for these in your work

  • Convert the volume fully.
  • Retain consistent density units.

Common mistakes

  • Cube the length conversion for volume.
  • A density conversion combines mass and volume factors.
  • Use compatible units in m = ρV.
Recall without your notes

What can you explain now?

What mass occupies 15 cm³ at 2.7 g/cm³?

Compare with the explanation

40.5 g.

Multiply the density by the volume.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

Derive the g/cm³ to kg/m³ factor from its two unit conversions without memorising it alone.

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Sciences — Co-ordinated (9-1)

Course scope and assessment

This 9–1 pathway maps all 152 detailed subject-content sections in the published 0973 syllabus for exams in 2028 and 2029. The course map follows the same 2028–2029 section codes as Cambridge's A*–G 0654 syllabus, while keeping 0973's grading and entry rules separate. It adapts lessons from the related single-science courses and excludes clear single-science-only topics. A 0973-specific objective-by-objective review, Core/Supplement audit, human subject-teacher review, supervised laboratory experience and cumulative assessment remain in progress. Written practice is self-checked and does not predict an official grade. The separate 2025–2027 syllabus has not been reconciled here. Cambridge lists 0973 only in a limited number of administrative zones: June in zone 3 and centres in Oman and the UAE; November in zone 3 only. Confirm entry with your centre.

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