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IGCSE · Cambridge (CIE) · 0973

Balance the yeast anaerobic chemical equation

Conserve atoms while forming ethanol and carbon dioxide.

Respiration · Cambridge IGCSE 0973 · B12.1
Exam scope and assessment notes

Mapped to the named 0973 section using teaching from the corresponding single-science course. A 0973-specific review of every Core and Supplement objective is still in progress. Written practice is self-checked; it does not demonstrate supervised laboratory competence or award an official Cambridge grade. This qualification reports two grades on the 9–1 scale; confirm the entry route for your zone and exam series.

Before you begin

  • Recall cell processes, enzymes and the distinction between gas exchange and breathing.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

How many hydrogen atoms are in one C₂H₅OH?

What you will learn

  • Use the ethanol formula correctly
  • Check all element totals

Balance the yeast anaerobic chemical equation

Respiration model reference
FeatureMeaning
Glucose inputC6 · H12 · O6
2 ethanolC4 · H12 · O2
2 carbon dioxideC2 · H0 · O4
Combined productsC6 · H12 · O6
Original teaching model. The ethanol formula contains six hydrogen atoms per molecule. Glucose oxygen atoms appear in products without O₂ being a reactant.

Use the ethanol formula correctly

The Supplement yeast equation is C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂. Ethanol is written C₂H₅OH: each molecule contains two carbon, six hydrogen and one oxygen atoms. The final OH contributes one hydrogen, so counting only the five written next to H gives an incorrect total.

Two ethanol molecules contain four carbon, twelve hydrogen and two oxygen atoms. Two carbon-dioxide molecules add two carbon and four oxygen atoms. The combined products therefore contain six carbon, twelve hydrogen and six oxygen atoms, matching one glucose molecule. Oxygen is conserved in the products even though no O₂ reactant is used.

Check all element totals

Balance by coefficients rather than changing the substance formulae. A coefficient of two multiplies the entire ethanol formula, including its OH group. Equal atom totals do not require equal numbers of molecules: one glucose corresponds to four product molecules in this overall model.

This is the specified yeast pathway and not the aerobic or muscle equation. State energy release alongside the chemical equation without treating it as extra matter. The balanced equation gives relative amounts for the described overall reaction; it is not a complete account of all reactions that can occur in a yeast culture.

Sources for this lesson

Pause and explain

Which is the balanced yeast equation?

Put the idea to work

Worked example

How many hydrogen atoms are in 2C₂H₅OH?

Show the worked solution
  1. Each ethanol has five plus one hydrogen atoms.
  2. Two times six is twelve.

Answer Twelve hydrogen atoms.

Try a topic test

Choose Easy, Normal or Difficult. Save your answers and open worked review after finishing.

Test this topic →

From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

State the balanced anaerobic yeast equation.

Give me a hint

Both product coefficients are two.

Compare my reasoning
  1. Use the correct ethanol formula.
  2. Balance with two ethanol and two CO₂.

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂.

Look for these in your work

  • Preserve the formulae
  • Give both coefficients
2 · Independent

Count carbon, hydrogen and oxygen atoms in the products.

Give me a hint

Multiply each whole formula by its coefficient.

Compare my reasoning
  1. Two ethanol supply C4 H12 O2.
  2. Two CO₂ supply C2 O4.

Products total C6 H12 O6, matching one glucose molecule.

Look for these in your work

  • Include OH hydrogen
  • Combine both products
3 · Transfer

How can oxygen atoms appear in the products when the pathway does not use O₂?

Give me a hint

Look at the glucose formula.

Compare my reasoning
  1. Glucose already contains six oxygen atoms.
  2. Those atoms are conserved in ethanol and CO₂.

The oxygen atoms are already in glucose and are redistributed into the products; O₂ is not needed as a reactant in this model.

Look for these in your work

  • Identify the atom source
  • Separate oxygen atoms from O₂ use

Common mistakes

  • Omitting the hydrogen in OH.
  • Adding oxygen as a reactant to balance this anaerobic model.
Recall without your notes

What can you explain now?

Which is the balanced yeast equation?

Compare with the explanation

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

All three elements balance.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

Count all ethanol atoms and state the balanced equation.

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Sciences — Co-ordinated (9-1)

Course scope and assessment

This 9–1 pathway maps all 152 detailed subject-content sections in the published 0973 syllabus for exams in 2028 and 2029. The course map follows the same 2028–2029 section codes as Cambridge's A*–G 0654 syllabus, while keeping 0973's grading and entry rules separate. It adapts lessons from the related single-science courses and excludes clear single-science-only topics. A 0973-specific objective-by-objective review, Core/Supplement audit, human subject-teacher review, supervised laboratory experience and cumulative assessment remain in progress. Written practice is self-checked and does not predict an official grade. The separate 2025–2027 syllabus has not been reconciled here. Cambridge lists 0973 only in a limited number of administrative zones: June in zone 3 and centres in Oman and the UAE; November in zone 3 only. Confirm entry with your centre.

StudyForA · Learn with understanding

Original teaching content and links to official sources. Check your exam year and qualification before using a resource.