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IGCSE · Cambridge (CIE) · 0652

Calculate electrical energy using current potential difference and time

Use E = IVt for a stated constant electrical input and distinguish energy amounts from input rates.

Electrical energy · Cambridge IGCSE Physical Science 0652 · P4.4

Cross-referenced from the related Cambridge IGCSE Chemistry 0620 or Physics 0625 teaching to the 0652 syllabus. Exact 0652 Core/Supplement objective coverage and this final-series course’s examiner fit still need specialist review. Written practice is self-checked and does not predict a Cambridge grade or demonstrate supervised laboratory competence.

Before you begin

  • Calculate power using P = IV.
  • Convert minutes to seconds.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

How many seconds are in 2 minutes?

What you will learn

  • Calculate electrical energy with seconds, amperes and volts.
  • Keep the component's input separate from useful output.
Original staged electrical-energy account uses 0.5 A at 6 V for 20 s and 1 A at 6 V for 10 s. Equal 60 J stage amounts total 120 J, averaging 4 W over 30 s. Rectangular area represents energy; unequal durations must be retained.Add the two stage amountsPower / W3602030Time / s60 J60 JTotal = 120 J over 30 sAverage input power = 4 W
Original staged electrical-energy account uses 0.5 A at 6 V for 20 s and 1 A at 6 V for 10 s. Equal 60 J stage amounts total 120 J, averaging 4 W over 30 s. Rectangular area represents energy; unequal durations must be retained.

Add the duration to the power

For constant matching I and V over a specified interval, E = IVt. Amperes, volts and seconds give joules. A component at 6 V carrying 0.5 A for 120 s receives 6 × 0.5 × 120 = 360 J. Its power is 3 W; 360 J is the accumulated amount over the interval.

Convert time before substitution: two minutes is 120 s, not 2 s. Convert prefixed current as well: 200 mA is 0.200 A. The equation refers to the measured component voltage and current, rather than an unrelated whole-source voltage.

Interpret the input energy

E = IVt gives electrical input under the stated conditions. It does not by itself tell you how much heats a separate water sample or lifts a load. Some energy can increase the device's own internal store or be transferred elsewhere. Use additional measured outputs or efficiency information for those questions.

If current or voltage changes, treat the interval in stated steady stages or use an appropriately supplied average power. A single initial current reading is not proof that it lasted throughout the interval. These practice conditions specify constant d.c. values so the simple product is justified.

Sources for this lesson

Pause and explain

At constant 6 V, 0.5 A and 120 s, what is E?

Put the idea to work

Worked example

Find input energy at constant 6 V and 0.5 A over 2 minutes.

Show the worked solution
  1. Time = 2 × 60 = 120 s.
  2. P = 6 × 0.5 = 3 W.
  3. E = 3 × 120 = 360 J.

Answer 360 J.

Try a topic test

Choose Easy, Normal or Difficult. Save your answers and open worked review after finishing.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Find input energy at 6 V and 0.5 A for 120 s.

Give me a hint

Calculate the electrical input rate and multiply by duration.

Compare my reasoning
  1. P = 6 × 0.5 = 3 W.
  2. t = 120 s.
  3. E = 3 × 120 = 360 J.

360 J.

Look for these in your work

  • State joules.
  • Keep duration explicit.
2 · Independent

Find input energy at 12 V carrying 200 mA steadily for 5 minutes.

Give me a hint

Convert both the current prefix and the time unit first.

Compare my reasoning
  1. I = 0.200 A and t = 300 s.
  2. P = 12 × 0.200 = 2.4 W.
  3. E = 2.4 × 300 = 720 J.

720 J.

Look for these in your work

  • Convert both units.
  • Use the component input.
3 · Transfer

A heater receives 720 J electrically. Is the energy gained by its water necessarily 720 J?

Give me a hint

Check the heater, container and surroundings as well as the water.

Compare my reasoning
  1. The electrical input is known.
  2. Other stores and transfers can take part.
  3. The water's gain is not separately supplied.

No; the water's gain needs further energy-account information.

Look for these in your work

  • Name other destinations.
  • Do not assume all input reaches one sample.

Common mistakes

  • Use seconds for a joule answer.
  • State the constant-condition assumption.
  • Input does not equal useful output without evidence.
Recall without your notes

What can you explain now?

Which quantity is missing if power alone is known but energy is requested?

Compare with the explanation

The transfer duration.

An energy amount needs the power rate and the interval over which it acts.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

Compute a constant electrical input in joules and explain the duration, units and output boundary.

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

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Course scope and assessment

This page maps the 2025–2026 Cambridge IGCSE Physical Science 0652 syllabus: 38 Chemistry sections and 46 Physics sections. Every section links to original 0620/0625 teaching or one of five new 0652 lessons, with guided, independent and transfer practice and explained answers. Cambridge limits entry to Administrative Zone 3 and identifies November 2026 as the final exam series. The section crosswalk is complete as a first coverage map; a numbered-objective and Core/Supplement audit, independent subject-teacher review and cumulative assessment are still needed. Written practice does not award a Cambridge grade. Online activities cannot demonstrate supervised laboratory competence or complete Paper 5/6.

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