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IGCSE · Cambridge (CIE) · 0652

Find missing transformer turn counts and input voltages

Rearrange the simple voltage-turn ratio to solve unknown primary or secondary values and check the labelled winding roles.

Transformers · Cambridge IGCSE Physical Science 0652 · P4.6.3

Cross-referenced from the related Cambridge IGCSE Chemistry 0620 or Physics 0625 teaching to the 0652 syllabus. Exact 0652 Core/Supplement objective coverage and this final-series course’s examiner fit still need specialist review. Written practice is self-checked and does not predict a Cambridge grade or demonstrate supervised laboratory competence.

Before you begin

  • Use the transformer voltage ratio.
  • Rearrange a proportion.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

What must an exact physical turn count be in this simple winding model?

What you will learn

  • Rearrange the simple voltage-turn ratio to solve unknown primary or secondary values and check the labelled winding roles.
  • Rearrange each named transformer unknown and distinguish compatible turn counts from real design specifications.
Original supplied missing-turn example uses primary 240 V, secondary 12 V and 50 secondary turns. Np = Ns × Vp/Vs gives 1000 primary turns. The mathematical requirement does not certify winding wire, insulation or operating ratings.Solve corresponding winding countsVp = 240 V · Vs = 12 VNs = 50 turnsNp = Ns × Vp/Vs50 × 240/12 = 1000 turnsPositive whole turn countsNo safe-rating inference
Original supplied missing-turn example uses primary 240 V, secondary 12 V and 50 secondary turns. Np = Ns × Vp/Vs gives 1000 primary turns. The mathematical requirement does not certify winding wire, insulation or operating ratings.

Solve the unknown without reversing roles

From Vp/Vs = Np/Ns, a missing primary turn count is Np = Ns × Vp/Vs; a missing secondary count is Ns = Np × Vs/Vp. For Vp = 240 V, Vs = 12 V and Ns = 50, the ratio is 20 and Np = 1000. Primary has more turns in this step-down model.

A missing input voltage can be found from Vp = Vs × Np/Ns. Identify the unknown first and show the rearrangement. Copying a memorised multiplier into every question can invert the ratio when the unknown changes.

Use realistic mathematical checks

Turn counts must be positive whole numbers for an actual winding. A fractional result in a supplied design can indicate an approximate target, inconsistent data or a choice needing refinement; do not silently call a fraction of a physical turn an exact count in the simple whole-turn model.

Questions here use exact compatible supplied counts. The voltage ratio does not specify wire thickness, safe insulation, current capacity or a full real-transformer design. Keep a solved turn count as a mathematical requirement of the given model, not an assembly approval.

Sources for this lesson

Pause and explain

Vp = 120 V, Vs = 24 V and Np = 600. What is Ns?

Put the idea to work

Worked example

Find Np for a supplied 240 V primary, 12 V secondary and 50 secondary turns.

Show the worked solution
  1. Rearrange Np = Ns × Vp/Vs.
  2. Substitute 50 × 240/12.
  3. The result is 1000 primary turns.

Answer 1000 turns.

Try a topic test

Choose Easy, Normal or Difficult. Save your answers and open worked review after finishing.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Find primary turns for 240 V/12 V and 50 secondary turns.

Give me a hint

Multiply secondary turns by the input-to-output voltage ratio.

Compare my reasoning
  1. 240/12 = 20.
  2. Np = 50 × 20.
  3. Primary needs 1000 turns in the model.

1000 turns.

Look for these in your work

  • Show the corresponding ratio.
  • State turns rather than volts.
2 · Independent

Find secondary turns for Vp = 120 V, Vs = 24 V and Np = 600.

Give me a hint

Use the secondary-to-primary voltage ratio.

Compare my reasoning
  1. 24/120 = 1/5.
  2. Ns = 600/5.
  3. The result is 120 turns.

120 turns.

Look for these in your work

  • Solve the named unknown.
  • Check step-down consistency.
3 · Transfer

A model has Np = 600, Ns = 150 and Vs = 30 V. Find Vp, then say whether this establishes safe wire ratings.

Give me a hint

Use the primary-to-secondary turn ratio, then separate the design claim.

Compare my reasoning
  1. Vp = 30 × 600/150.
  2. The input is 120 V.
  3. Wire and insulation ratings are not supplied by the ratio.

120 V; safe operating ratings are not established.

Look for these in your work

  • Calculate the input voltage.
  • Retain the missing-specification limitation.

Common mistakes

  • Name the unknown role.
  • Show the rearrangement.
  • Turn counts do not establish safe ratings.
Recall without your notes

What can you explain now?

What rearrangement finds secondary turns?

Compare with the explanation

Ns = Np × Vs/Vp

The output-to-input voltage ratio equals the corresponding secondary-to-primary turn ratio.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

Rearrange each named transformer unknown and distinguish compatible turn counts from real design specifications.

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Physical Science

Course scope and assessment

This page maps the 2025–2026 Cambridge IGCSE Physical Science 0652 syllabus: 38 Chemistry sections and 46 Physics sections. Every section links to original 0620/0625 teaching or one of five new 0652 lessons, with guided, independent and transfer practice and explained answers. Cambridge limits entry to Administrative Zone 3 and identifies November 2026 as the final exam series. The section crosswalk is complete as a first coverage map; a numbered-objective and Core/Supplement audit, independent subject-teacher review and cumulative assessment are still needed. Written practice does not award a Cambridge grade. Online activities cannot demonstrate supervised laboratory competence or complete Paper 5/6.

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