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IGCSE · Cambridge (CIE) · 0652

Combine the e m f of sources in series

Add aiding source rises and subtract opposing ones using their labelled polarities.

Series and parallel circuits · Cambridge IGCSE Physical Science 0652 · P4.3.2

Cross-referenced from the related Cambridge IGCSE Chemistry 0620 or Physics 0625 teaching to the 0652 syllabus. Exact 0652 Core/Supplement objective coverage and this final-series course’s examiner fit still need specialist review. Written practice is self-checked and does not predict a Cambridge grade or demonstrate supervised laboratory competence.

Before you begin

  • Read long positive and short negative plates.
  • Add signed numbers consistently.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

Which cell-symbol terminal is positive?

What you will learn

  • Calculate combined e.m.f. of several series sources.
  • Keep source polarity and ideal-terminal assumptions explicit.
Original series-source strip has two aiding 1.5 V cells and one opposing 1.5 V cell. A chosen left-to-right traversal yields +1.5 +1.5 −1.5 = +1.5 V. The diagram calculates combined e.m.f., not real-source connection suitability.Chosen traversal: left to right+1.5 V+1.5 V−1.5 V+1.5 +1.5 −1.5Net +1.5 V
Original series-source strip has two aiding 1.5 V cells and one opposing 1.5 V cell. A chosen left-to-right traversal yields +1.5 +1.5 −1.5 = +1.5 V. The diagram calculates combined e.m.f., not real-source connection suitability.

Choose a traversal direction

For aiding sources in series, each is connected so its negative terminal leads toward the next source positive terminal in the assembly, giving additive rises between the outer terminals. Three aiding 1.5 V cells give a combined e.m.f. of 4.5 V. Include all supplied sources, not just the nearest one.

More generally, choose one traversal direction through the source assembly. A passage from a source negative to positive contributes a rise; a positive-to-negative passage contributes a fall. Add those signed contributions. A reversed cell therefore opposes the others rather than increasing the total by its magnitude.

Distinguish the specified source account

Two aiding 1.5 V sources and one opposing 1.5 V source give 1.5 V net in the direction of the aiding pair. A zero net sum does not mean individual source e.m.f.s are zero. It means their signed rises and falls balance under the model.

Combined e.m.f. is a source work-per-charge account. Terminal p.d. under load can differ for non-ideal sources with internal resistance. Introductory questions assume ideal sources or ask for combined e.m.f.; do not present a diagram calculation as a practical instruction to connect arbitrary real power supplies together.

Sources for this lesson

Pause and explain

Three 1.5 V cells contain two aiding and one opposing contribution. What is the net e.m.f.?

Put the idea to work

Worked example

Three 1.5 V cells are in series, with two aiding and one opposing the chosen direction. Calculate the combined e.m.f.

Show the worked solution
  1. Assign +1.5 V to each aiding cell.
  2. Assign −1.5 V to the opposing cell.
  3. Add 1.5 + 1.5 − 1.5 = 1.5 V.

Answer 1.5 V net in the aiding-pair direction.

Try a topic test

Choose Easy, Normal or Difficult. Save your answers and open worked review after finishing.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Calculate combined e.m.f. of three aiding 1.5 V cells.

Give me a hint

All rises have the same sign.

Compare my reasoning
  1. Choose the aiding traversal direction.
  2. Add 1.5 + 1.5 + 1.5.
  3. The total is 4.5 V.

4.5 V.

Look for these in your work

  • Include all three sources.
  • State volts.
2 · Independent

Sources contribute +6 V, +3 V and −2 V along a chosen traversal. Find the net e.m.f. and direction.

Give me a hint

Add the signed contributions, retaining the reference.

Compare my reasoning
  1. The aiding total is 6 + 3 = 9 V.
  2. Subtract the opposing 2 V.
  3. The net is +7 V in the chosen direction.

+7 V in the chosen traversal direction.

Look for these in your work

  • Use the opposing sign.
  • State the reference direction.
3 · Transfer

Two equal 2 V sources oppose in an ideal diagram. A learner says both sources have no e.m.f. Explain the distinction.

Give me a hint

Compare individual work-per-charge accounts with the assembly sum.

Compare my reasoning
  1. Each source still has 2 V e.m.f.
  2. Their signed contributions are +2 V and −2 V.
  3. The combined net is 0 V without eliminating either individual source.

Net 0 V; each source still has its individual 2 V e.m.f.

Look for these in your work

  • State individual and net values.
  • Do not infer real-source connection suitability.

Common mistakes

  • Use polarity rather than adding every magnitude.
  • Zero net e.m.f. does not make each cell zero.
  • Terminal p.d. under load needs the stated source model.
Recall without your notes

What can you explain now?

How are aiding series e.m.f.s combined?

Compare with the explanation

Add their values.

Aiding rises have the same sign in the chosen traversal.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

Choose a direction and add aiding and opposing source e.m.f.s with signs.

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Physical Science

Course scope and assessment

This page maps the 2025–2026 Cambridge IGCSE Physical Science 0652 syllabus: 38 Chemistry sections and 46 Physics sections. Every section links to original 0620/0625 teaching or one of five new 0652 lessons, with guided, independent and transfer practice and explained answers. Cambridge limits entry to Administrative Zone 3 and identifies November 2026 as the final exam series. The section crosswalk is complete as a first coverage map; a numbered-objective and Core/Supplement audit, independent subject-teacher review and cumulative assessment are still needed. Written practice does not award a Cambridge grade. Online activities cannot demonstrate supervised laboratory competence or complete Paper 5/6.

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