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IGCSE · Cambridge (CIE) · 0652

Define a kilowatt-hour and convert between energy units

Interpret kWh as an energy amount, convert it to joules and calculate appliance energy from kW and hours.

Electrical energy · Cambridge IGCSE Physical Science 0652 · P4.4

Cross-referenced from the related Cambridge IGCSE Chemistry 0620 or Physics 0625 teaching to the 0652 syllabus. Exact 0652 Core/Supplement objective coverage and this final-series course’s examiner fit still need specialist review. Written practice is self-checked and does not predict a Cambridge grade or demonstrate supervised laboratory competence.

Before you begin

  • Distinguish energy from power.
  • Convert kilowatts and hours.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

How many seconds are in one hour?

What you will learn

  • Define one kilowatt-hour as energy transferred at one kilowatt for one hour.
  • Convert kWh and joules while keeping power and energy distinct.
Original unit reference defines 1 kWh as 1 kW for 1 h, equal to 3 600 000 J. It is energy, not kW/h or a power rating independent of duration.An energy unit, not a rate1 kW for 1 hour1 kWh1000 W × 3600 s3 600 000 JMultiply kW by hoursDo not write kW / h
Original unit reference defines 1 kWh as 1 kW for 1 h, equal to 3 600 000 J. It is energy, not kW/h or a power rating independent of duration.

Multiply a power by a duration

One kilowatt-hour is the energy transferred at a constant rate of one kilowatt for one hour. Since 1 kW = 1000 W and 1 h = 3600 s, 1 kWh = 3 600 000 J. The unit is a product of power and time; it is not 'kilowatts per hour', which would describe a different kind of rate.

For an appliance with a stated constant electrical input, energy in kWh equals power in kW multiplied by time in hours. A 2 kW appliance operating for 0.5 h uses 1 kWh. A 500 W appliance for 2 h also uses 1 kWh after converting 500 W to 0.5 kW.

Keep the units attached

For a joule calculation, use watts and seconds. For a kWh calculation, use kilowatts and hours. Do not multiply a value in watts by hours and label the result kWh without converting: 500 W × 2 h is 1000 Wh, equal to 1 kWh.

A device rated 2 kW has an input rate at its specified condition, not a fixed lifetime energy use of 2 kWh. Its actual accumulated energy depends on duration and control cycles. Use measured meter energy or stated average power if the appliance cycles on and off.

Sources for this lesson

Pause and explain

How much energy does 2 kW use over 0.5 h at constant input?

Put the idea to work

Worked example

Define 1 kWh and convert it to joules.

Show the worked solution
  1. It is 1 kW operating for 1 h.
  2. Convert to 1000 W and 3600 s.
  3. Energy = 1000 × 3600 = 3 600 000 J.

Answer 1 kWh = 3 600 000 J.

Try a topic test

Choose Easy, Normal or Difficult. Save your answers and open worked review after finishing.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Convert 1 kWh to joules.

Give me a hint

Change both parts of the product into watts and seconds.

Compare my reasoning
  1. 1 kW = 1000 W.
  2. 1 h = 3600 s.
  3. 1 kWh = 3 600 000 J.

3 600 000 J.

Look for these in your work

  • Convert both units.
  • State energy in joules.
2 · Independent

Find energy in kWh and joules for a steady 500 W input over 2 h.

Give me a hint

Use kW and hours first, then the kWh-to-joule conversion.

Compare my reasoning
  1. 500 W = 0.5 kW.
  2. Energy = 0.5 × 2 = 1 kWh.
  3. Energy = 3 600 000 J.

1 kWh; 3 600 000 J.

Look for these in your work

  • Convert watts to kilowatts.
  • Retain the duration.
3 · Transfer

A label states 2 kW. Can its daily energy use be read as 2 kWh without any timing or control information?

Give me a hint

A power rating lacks the day's effective operating duration.

Compare my reasoning
  1. 2 kW is a rate at a specified condition.
  2. Daily energy depends on operating time and control cycling.
  3. No unique daily kWh amount is established.

No; duration or measured daily energy is needed.

Look for these in your work

  • Separate rate and amount.
  • Identify missing usage data.

Common mistakes

  • kWh is an energy unit.
  • kWh is not kW/h.
  • A rated power does not supply operating duration.
Recall without your notes

What can you explain now?

Which combination directly gives kWh?

Compare with the explanation

Kilowatts multiplied by hours.

The matching power and duration units make the accumulated amount a kilowatt-hour value.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

Define kWh, convert to joules and select power–time units that give the requested energy unit.

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Physical Science

Course scope and assessment

This page maps the 2025–2026 Cambridge IGCSE Physical Science 0652 syllabus: 38 Chemistry sections and 46 Physics sections. Every section links to original 0620/0625 teaching or one of five new 0652 lessons, with guided, independent and transfer practice and explained answers. Cambridge limits entry to Administrative Zone 3 and identifies November 2026 as the final exam series. The section crosswalk is complete as a first coverage map; a numbered-objective and Core/Supplement audit, independent subject-teacher review and cumulative assessment are still needed. Written practice does not award a Cambridge grade. Online activities cannot demonstrate supervised laboratory competence or complete Paper 5/6.

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Original teaching content and links to official sources. Check your exam year and qualification before using a resource.