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IGCSE · Cambridge (CIE) · 0652

Distinguish voltage from charge current and total energy

Use volts for p.d. and separate energy per charge, charge amount, charge-flow rate and transferred energy.

Electromotive force and potential difference · Cambridge IGCSE Physical Science 0652 · P4.2.3

Cross-referenced from the related Cambridge IGCSE Chemistry 0620 or Physics 0625 teaching to the 0652 syllabus. Exact 0652 Core/Supplement objective coverage and this final-series course’s examiner fit still need specialist review. Written practice is self-checked and does not predict a Cambridge grade or demonstrate supervised laboratory competence.

Before you begin

  • Define component p.d.
  • Recognise joules, coulombs and amperes.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

Which is a charge-flow rate unit?

What you will learn

  • State volts as the p.d. unit.
  • Interpret a p.d. label without assigning unprovided current or total energy.
Original two-point component reference contrasts potential difference, charge and current. P.d. accounts for the complete electrical work per charge through the component, not solely its useful output.Work per charge in componentPoint APoint BP.d. between A and BUnit: volt (J per C)Complete component transferNot useful output alone
Original two-point component reference contrasts potential difference, charge and current. P.d. accounts for the complete electrical work per charge through the component, not solely its useful output.

Keep four quantities distinct

Potential difference between two points is measured in volts, V. A 4 V p.d. means 4 J of work per 1 C passing through the stated component. The p.d. unit is neither an ampere nor a coulomb. The energy transferred for each charge and the amount of charge that passes are separate pieces of information.

Charge is an amount measured in C; current is a flow rate measured in A; work or energy is measured in J; p.d. is energy per charge measured in V. A component can have the same p.d. in two trials but different total transferred energy if different amounts of charge pass.

Read voltage units and assumptions

Voltage prefixes use the normal powers of ten: 250 mV = 0.250 V and 2 kV = 2000 V. A prefix conversion changes the numeric scale, not voltage into a current or energy quantity. The later numerical work–charge lesson uses the same volt meaning explicitly in an equation.

A stated component p.d. does not alone determine its current without an operating relationship or measurement. Nor does it establish a fixed amount of work without passed-charge or compatible power-time data. Name the given quantity and stop at the conclusion supported by the information.

Sources for this lesson

Pause and explain

Which interpretation of a 4 V p.d. is supported?

Put the idea to work

Worked example

A component has p.d. 4 V. Interpret the work done for each 1 C and identify what is not supplied by this value alone.

Show the worked solution
  1. 4 V means 4 J per C across the component.
  2. The total passed charge is not stated.
  3. The current and total transferred energy are not determined.

Answer 4 J per 1 C; current and total energy are not determined by p.d. alone.

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Choose Easy, Normal or Difficult. Save your answers and open worked review after finishing.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

State the p.d. unit and interpret 4 V for each 1 C through the component.

Give me a hint

Use the volt's energy-per-charge meaning.

Compare my reasoning
  1. The unit is volt, V.
  2. One volt means one joule per coulomb.
  3. 4 V means 4 J per 1 C.

Volts; 4 J of component work per 1 C.

Look for these in your work

  • State the unit.
  • Keep the component account per charge.
2 · Independent

Convert 250 mV and 2 kV into volts.

Give me a hint

Use milli = 10⁻³ and kilo = 10³ for voltage.

Compare my reasoning
  1. 250 mV = 250 × 10⁻³ V.
  2. 2 kV = 2 × 10³ V.
  3. The values are 0.250 V and 2000 V.

0.250 V; 2000 V.

Look for these in your work

  • Use both prefixes correctly.
  • Retain volt units.
3 · Transfer

A learner concludes a component at 6 V always transfers exactly 6 J and carries 6 A. Assess both conclusions.

Give me a hint

Identify the missing charge amount and current relationship.

Compare my reasoning
  1. 6 V means 6 J per C, not a fixed energy total.
  2. The amount of charge passing is not given.
  3. No current relationship or measurement is supplied.

Neither follows; 6 V supplies energy per charge, not total energy or current.

Look for these in your work

  • Correct both quantity confusions.
  • State what further data would be needed.

Common mistakes

  • Volts are not amperes or coulombs.
  • P.d. is not a fixed total energy.
  • A voltage prefix conversion does not change the quantity.
Recall without your notes

What can you explain now?

What unit measures p.d. between two points?

Compare with the explanation

Volt (V).

Potential difference measures electrical work per unit charge.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

Use volt units and separate p.d., current, charge and total energy in a component account.

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Physical Science

Course scope and assessment

This page maps the 2025–2026 Cambridge IGCSE Physical Science 0652 syllabus: 38 Chemistry sections and 46 Physics sections. Every section links to original 0620/0625 teaching or one of five new 0652 lessons, with guided, independent and transfer practice and explained answers. Cambridge limits entry to Administrative Zone 3 and identifies November 2026 as the final exam series. The section crosswalk is complete as a first coverage map; a numbered-objective and Core/Supplement audit, independent subject-teacher review and cumulative assessment are still needed. Written practice does not award a Cambridge grade. Online activities cannot demonstrate supervised laboratory competence or complete Paper 5/6.

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