Distinguish overcurrent trips from residual-current protection
Explain resettable interruption and separate excess-current detection from live–neutral imbalance.
Exam scope and assessment notes
Core and Extended · Physics 0972, 2026–2028. Use the stated source, operating conditions and meter ranges. Written practice is self-checked. Human subject-teacher review, supervised practical competence and cumulative assessment remain pending. Cambridge states that IGCSE 0972 has the same subject content as IGCSE 0625, with 9–1 grading. This StudyForA pathway maps the 2026–2028 syllabus only. This 9–1 graded qualification is available only in a limited number of administrative zones. Confirm that your centre can enter you for this code and exam series with Cambridge International. Cambridge has published a separate syllabus for 2029. StudyForA has not reconciled that version yet; this page supports exams in 2026, 2027 and 2028 only.
Before you begin
- Identify live and neutral roles.
- Calculate a difference and convert A to mA.
Work on paper. Try each question before revealing help, and explain why your method works.
Quick readiness check
What happens when a protective trip opens its contacts?
What you will learn
- Explain resettable interruption and separate excess-current detection from live–neutral imbalance.
- Distinguish a current-limit trip from a live–neutral imbalance trip and retain each device’s limits.
A trip opens contacts
An overcurrent circuit breaker or trip switch opens contacts when its specified operating conditions are reached. In a common electromagnetic model, increased current strengthens an electromagnet until its mechanism releases the contacts. Many real devices also use thermal mechanisms; do not assume every trip switch has the same design.
Unlike a melted fuse, a breaker can be reset after the cause is safely addressed. This reset capability does not justify repeated resetting into an unresolved fault. A nominal rating is not a universal promise of instantaneous opening at any tiny excess; actual timing follows its specified characteristics.
Residual-current detection is a different comparison
A residual-current device, RCD, compares current in the live and neutral conductors. In normal operation these have equal magnitudes through that device. A difference can indicate current returning by another path, such as earth, and trigger disconnection. It responds to imbalance rather than simply to the total appliance load current.
An RCD alone does not provide overload protection; a combined RCBO includes both functions. Even residual-current protection cannot make deliberate live contact safe or guarantee protection in every fault path. For example, equal live-to-neutral contact current need not produce an imbalance. These comparisons explain device roles without prescribing mains tests.
Pause and explain
A plain RCD has equal live and neutral currents of 18 A. Does equality prove a 13 A lead is not overloaded?
Worked example
A supplied detector reads live 5.03 A and neutral 5.00 A. Find its residual difference and identify the detection role.
Show the worked solution
- Compare magnitudes passing through the device.
- 5.03 − 5.00 = 0.03 A.
- This is a residual-current imbalance, not the total load-current value.
Answer 0.03 A = 30 mA imbalance; residual-current detection.
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Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.
Explain a supplied electromagnetic overcurrent trip from increasing current to open contacts.
Give me a hint
Link magnetic strength to its release mechanism.
Compare my reasoning
- Excess current strengthens the electromagnet in this model.
- The mechanism releases the contacts.
- The contacts separate and interrupt the path.
Specified excess current activates the mechanism and opens contacts.
Look for these in your work
- State the given mechanism.
- Do not claim all devices have identical construction.
A supplied residual detector has live 5.03 A and neutral 5.00 A. Calculate the imbalance in A and mA.
Give me a hint
Subtract magnitudes, then multiply amperes by 1000.
Compare my reasoning
- The difference is 0.03 A.
- 0.03 × 1000 = 30 mA.
- It is an imbalance, not the 5 A load current.
0.03 A or 30 mA.
Look for these in your work
- Keep units distinct.
- Identify the compared currents.
An 18 A load on a supplied 13 A lead has equal live and neutral currents, and its plain RCD does not trip. Explain why this does not approve the load.
Give me a hint
Compare the residual test with the shared-current limit.
Compare my reasoning
- Equal magnitudes give zero residual difference.
- 18 A still exceeds 13 A.
- Overcurrent protection is a separate required function.
The lead is overloaded; zero residual imbalance does not rule out excess-current heating.
Look for these in your work
- Explain both device criteria.
- Do not treat one protective device as universal.
Common mistakes
- An RCD alone is not overload protection.
- A reset is not a fault repair.
- A nominal rating is not an instantaneous timing rule.
What can you explain now?
What does an RCD compare?
Compare with the explanation
Live and neutral current magnitudes
An imbalance can reveal current using a different return path.
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Make it stick
Distinguish a current-limit trip from a live–neutral imbalance trip and retain each device’s limits.
If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.