Learn in your language
Skip to content
IGCSE · Cambridge (CIE) · 0972

Explain white-light dispersion by a glass prism

Follow different wavelengths through two nonparallel faces and explain the separated spectrum.

Light pathway · 0972 (9–1) · 3.2.4
Exam scope and assessment notes

Core and Extended · Physics 0972, 2026–2028. Follow the selected Light section; ray diagrams use an ideal thin-lens or plane-boundary model. Written work is self-checked. Human teacher review, supervised practical competence and cumulative assessment remain pending. Cambridge states that IGCSE 0972 has the same subject content as IGCSE 0625, with 9–1 grading. This StudyForA pathway maps the 2026–2028 syllabus only. This 9–1 graded qualification is available only in a limited number of administrative zones. Confirm that your centre can enter you for this code and exam series with Cambridge International. Cambridge has published a separate syllabus for 2029. StudyForA has not reconciled that version yet; this page supports exams in 2026, 2027 and 2028 only.

Before you begin

  • Trace entry and exit refraction at transparent boundaries.
  • Distinguish a prism from a parallel-sided block.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

Why can white light form a prism spectrum?

What you will learn

  • Describe prism dispersion of white light.
  • Explain why the emergent colours have different deviations.
Original prism construction traces three representative components with supplied indices 1.50, 1.55 and 1.60 through two nonparallel faces using local normal angles. The red model ray deviates least and violet most. White light's visible range is continuous; three shown paths do not mean exactly three frequencies or calibrated intensity.White light → representative pathsWhite inputRed less · violet more deviationTwo nonparallel facesContinuous range · three shown rays
Original prism construction traces three representative components with supplied indices 1.50, 1.55 and 1.60 through two nonparallel faces using local normal angles. The red model ray deviates least and violet most. White light's visible range is continuous; three shown paths do not mean exactly three frequencies or calibrated intensity.

Different wavelengths refract differently

White light contains a range of visible frequencies and wavelengths. A glass prism refracts the light on entering and leaving its nonparallel faces. For ordinary visible-light dispersion in glass, the refractive index is generally greater for violet than for red, so the components follow different paths and leave with different overall deviations.

In the usual prism spectrum, red is deviated least and violet most; intermediate colours appear between them. The prism separates existing components rather than manufacturing colours from one frequency. A narrow white-light input and suitable projection arrangement make the spread easier to observe than a wide overlapping beam.

Read an ordinary spectrum with the right scope

A ray sketch can show representative red, green and violet paths while the real visible spectrum is continuous. The traditional seven names label regions of that continuous range, not seven isolated frequencies with empty spaces between them. The supplied original prism geometry is a teaching model, not a performed spectrum measurement.

A single-frequency input can still be refracted and deviated by the prism, but it cannot be dispersed into the full range already present in white light. A parallel-sided block can give wavelength-dependent lateral shifts while restoring parallel emergence in the matching outside medium; the prism's nonparallel faces make the separated net directions clear.

Pause and explain

Which visible colour has the greatest usual deviation in a glass-prism spectrum?

Put the idea to work

Worked example

A narrow white beam passes through an ordinary glass prism. Compare its red and violet emergent directions.

Show the worked solution
  1. Both components refract at entry and exit.
  2. The glass's index differs for the two components.
  3. Violet shows greater overall deviation than red in the usual model.

Answer Red deviates least and violet most; the emergent spectrum separates white-light components.

Try a topic test

Choose Easy, Normal or Difficult. Save your answers and open worked review after finishing.

Test this topic →

From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Explain how a glass prism disperses a narrow white beam.

Give me a hint

Follow both boundaries and compare the components.

Compare my reasoning
  1. White light contains different visible components.
  2. Their refraction differs at the prism faces.
  3. They emerge in different directions as a spectrum.

Wavelength-dependent refraction at nonparallel faces separates the components.

Look for these in your work

  • Use both boundaries.
  • Keep the components' origin in the input.
2 · Independent

Compare red and violet deviation in the ordinary prism model.

Give me a hint

Use the usual visible-light dispersion ordering.

Compare my reasoning
  1. Red and violet both undergo refraction.
  2. Violet has the greater usual glass index.
  3. Violet is deviated more and red less.

Violet most; red least.

Look for these in your work

  • State the correct order.
  • Link it to differing refraction.
3 · Transfer

A diagram shows only red, green and violet rays. Does this prove the spectrum contains exactly three frequencies?

Give me a hint

Representative drawing paths are not a full frequency inventory.

Compare my reasoning
  1. The three paths illustrate different deviations.
  2. White light has a continuous visible range.
  3. The drawing omits intermediate components for clarity.

No; representative rays illustrate a continuous spectrum.

Look for these in your work

  • Distinguish model from inventory.
  • Avoid inventing gaps between named colours.

Common mistakes

  • The prism separates components rather than creating frequencies.
  • Violet has greater usual prism deviation than red.
  • Seven named colours describe a continuous visible spectrum.
Recall without your notes

What can you explain now?

Does a prism turn one single frequency into all seven white-light colours?

Compare with the explanation

No.

Dispersion separates the frequencies present in the input.

After trying it yourself, choose your next review. This is your self-assessment.

Your review choice appears on Today. Sign in to sync it across devices.

Make it stick

Explain prism dispersion, the red/violet ordering and the meaning of representative spectrum rays.

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Physics (9-1)

Course scope and assessment

491 sequenced Physics lessons provide 1473 guided, independent and application problems. 58 of 58 syllabus sections have full linked teaching sequences; 0 sections remain pending. Three earlier starter overviews remain available but are not counted as full sequences. The map covers all six subject areas for 2026–2028 and keeps review and assessment limits visible. This is available content, not full programme completion, an exam grade or certified mastery. Written practice is self-checked. Supervised practical experience, cumulative assessment and human subject-teacher review remain pending. Paper method exercises do not demonstrate practical competence or complete either practical-assessment route. This is the separate 9–1 qualification 0972; Cambridge states that its 2026–2028 subject content is otherwise the same as 0625. This 9–1 graded qualification is available only in a limited number of administrative zones. Confirm that your centre can enter you for this code and exam series with Cambridge International. The 2029 syllabus is separately published at https://www.cambridgeinternational.org/Images/764368-2029-syllabus.pdf and is not yet mapped here. This course supports exams in 2026, 2027 and 2028 only.

StudyForA · Learn with understanding

Original teaching content and links to official sources. Check your exam year and qualification before using a resource.