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IGCSE · Cambridge (CIE) · 0972

Plot speed-time graphs and identify motion states

Read speed from height and distinguish rest, constant speed, acceleration and deceleration.

Motion pathway · 0972 (9–1) · 1.2
Exam scope and assessment notes

Core and Extended · Physics 0972, 2026–2028, section 1.2. Core includes speed, velocity direction, distance–time and speed–time interpretation, straight distance–time gradients, speed–time areas and near-Earth free-fall acceleration. Numerical acceleration and the resistance/terminal-velocity explanation are Supplement requirements, taught in separately labelled Extended lessons. Written practice is self-checked; cumulative assessment, supervised practical experience and human subject-teacher review remain pending. Cambridge states that IGCSE 0972 has the same subject content as IGCSE 0625, with 9–1 grading. This StudyForA pathway maps the 2026–2028 syllabus only. This 9–1 graded qualification is available only in a limited number of administrative zones. Confirm that your centre can enter you for this code and exam series with Cambridge International. Cambridge has published a separate syllabus for 2029. StudyForA has not reconciled that version yet; this page supports exams in 2026, 2027 and 2028 only.

Before you begin

  • Plot time-value coordinate pairs.
  • Distinguish speed from distance.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

What is the vertical quantity on a speed–time graph?

What you will learn

  • Plot a speed–time record with labelled axes.
  • Interpret horizontal and rising or falling sections.
Speed in m/s against time in seconds through (0,0), (4,8), (7,8), (9,0), with straight sections. Areas are 16, 24 and 8 metres, totalling 48 metres. Gradients are +2, 0 and −4 m/s² for straight motion in one unchanged positive direction. A horizontal positive-speed section is continued motion. The graph alone does not supply a direction.Speed area gives distanceSpeed / (m/s)0480479Time / sAreas: 16 + 24 + 8 = 48 mFixed-direction gradients: +2, 0, −4Acceleration units: m/s²Horizontal positive speed: still moving
Speed in m/s against time in seconds through (0,0), (4,8), (7,8), (9,0), with straight sections. Areas are 16, 24 and 8 metres, totalling 48 metres. Gradients are +2, 0 and −4 m/s² for straight motion in one unchanged positive direction. A horizontal positive-speed section is continued motion. The graph alone does not supply a direction.

Height is speed on these axes

A speed–time graph has time on the horizontal axis and speed on the vertical axis. The points (0 s, 0 m/s), (4 s, 8 m/s), (7 s, 8 m/s), (9 s, 0 m/s) joined by straight sections show speeding up, then constant speed, then slowing to rest. The vertical height at six seconds is 8 m/s.

A horizontal line at positive speed means continuing motion at constant speed. A horizontal line on the zero-speed axis means rest. These interpretations differ from a distance–time graph, where any horizontal cumulative-distance segment means rest. Check the axis quantity before describing motion.

Interpret changes over time

A rising speed line shows acceleration in the qualitative sense of speeding up; a falling one shows deceleration. A steeper change means speed changes more quickly. The numerical rate of change and units m/s² belong to the separately labelled Supplement lessons.

A single speed–time graph does not supply the direction of motion, so it cannot distinguish two journeys with equal speed histories but different directions. Plotting line segments between supplied points assumes the stated change is linear in each interval; isolated speed measurements alone do not establish the exact motion between them.

Pause and explain

What does the horizontal 4–7 s section at 8 m/s mean?

Put the idea to work

Worked example

Interpret the straight sections through (0,0), (4,8), (7,8), (9,0) in s and m/s.

Show the worked solution
  1. 0–4 s: speed increases from zero to 8 m/s.
  2. 4–7 s: speed stays at 8 m/s.
  3. 7–9 s: speed falls to zero, ending at rest.

Answer Accelerates; constant speed; decelerates to rest.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Plot straight speed sections through (0,0), (4,8), (7,8), (9,0). Describe each interval.

Give me a hint

Read rising, horizontal and falling speed values.

Compare my reasoning
  1. Label time in seconds and speed in m/s.
  2. Plot and join the stated straight sections.
  3. Interpret acceleration, constant speed and deceleration to rest.

Accelerates 0–4 s; constant 4–7 s; decelerates 7–9 s.

Look for these in your work

  • Label the axes.
  • Interpret positive horizontal speed correctly.
2 · Independent

A speed graph is horizontal at 6 m/s for five seconds, then at zero for two seconds. Describe both states.

Give me a hint

Horizontal means unchanged speed; its height determines whether motion continues.

Compare my reasoning
  1. The first interval has speed 6 m/s.
  2. That is constant non-zero motion.
  3. The second interval has zero speed and is rest.

Constant speed for five seconds, then rest for two seconds.

Look for these in your work

  • Use the vertical value.
  • Distinguish constant speed from rest.
3 · Transfer

A student labels every horizontal graph section as rest. Explain how to correct this for distance–time and speed–time graphs.

Give me a hint

First identify what the vertical axis measures.

Compare my reasoning
  1. Horizontal cumulative distance means no additional path is travelled.
  2. Horizontal positive speed means a fixed non-zero rate.
  3. Only a zero-speed horizontal section means rest on the speed graph.

Use the vertical quantity; horizontal positive speed is continued motion.

Look for these in your work

  • Compare both graph types.
  • Include the zero-speed condition.

Common mistakes

  • Positive horizontal speed is motion, not rest.
  • A speed graph does not specify direction.
  • Do not call the graph's vertical reading a distance.
Recall without your notes

What can you explain now?

What does a horizontal speed–time line at 8 m/s mean?

Compare with the explanation

Constant speed of 8 m/s.

The speed remains positive and unchanged, so the object keeps moving.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

Draw matching distance–time and speed–time graphs for constant-speed travel followed by a stop.

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Physics (9-1)

Course scope and assessment

491 sequenced Physics lessons provide 1473 guided, independent and application problems. 58 of 58 syllabus sections have full linked teaching sequences; 0 sections remain pending. Three earlier starter overviews remain available but are not counted as full sequences. The map covers all six subject areas for 2026–2028 and keeps review and assessment limits visible. This is available content, not full programme completion, an exam grade or certified mastery. Written practice is self-checked. Supervised practical experience, cumulative assessment and human subject-teacher review remain pending. Paper method exercises do not demonstrate practical competence or complete either practical-assessment route. This is the separate 9–1 qualification 0972; Cambridge states that its 2026–2028 subject content is otherwise the same as 0625. This 9–1 graded qualification is available only in a limited number of administrative zones. Confirm that your centre can enter you for this code and exam series with Cambridge International. The 2029 syllabus is separately published at https://www.cambridgeinternational.org/Images/764368-2029-syllabus.pdf and is not yet mapped here. This course supports exams in 2026, 2027 and 2028 only.

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