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IGCSE · Cambridge (CIE) · 0970

Infer genotypes in a stated dominant pedigree using a recessive offspring

A declared dominant-key pedigree can resolve Tt from a recessive offspring and known partner.

Monohybrid inheritance pathway · 0970 (9–1) · 17.4
Exam scope and assessment notes

Core and Extended · Biology 0970, 2026–2028. Use the stated specimen features and evidence. Diagrams are schematic. Written practice is self-checked; human subject-teacher review, supervised practical competence and cumulative assessment remain pending. Cambridge states that IGCSE 0970 has the same subject content as IGCSE 0610, with 9–1 grading. This StudyForA pathway maps the 2026–2028 syllabus only. This 9–1 graded qualification is available only in a limited number of administrative zones. Confirm that your centre can enter you for this code and exam series with Cambridge International. Cambridge has published a separate syllabus for 2029. StudyForA has not reconciled that version yet; this page supports exams in 2026, 2027 and 2028 only.

Before you begin

  • Recall chromosomes, genes and alleles, meiosis, haploid gametes and fertilisation restoring two chromosome sets.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

What does an unfilled individual mean in this pedigree?

What you will learn

  • Apply the dominant trait key to parents and offspring
  • Use known gamete contributions to resolve a dominant genotype

Original teaching model. Pedigrees and records are fictional; allele and probability assumptions are stated.

Infer genotypes in a stated dominant pedigree using a recessive offspringA declared dominant-key pedigree can resolve Tt from a recessive offspring and known partner.Original fictional pedigreeFilled = pigment present; unfilled= pigment absent (tt)IIII-1TtI-2ttII-1ttII-2TtShapes, shading and inferredgenotypes follow the stated key
A declared dominant-key pedigree can resolve Tt from a recessive offspring and known partner.
Allele, phenotype and evidence key
FeatureMeaning
Filled trait keyPigment present: TT or Tt before further evidence
Unfilled I-2 and II-1Pigment absent: tt
I-1 after offspring evidenceT for pigment and transmitted t: Tt
Filled II-2 with tt parentMust be Tt, not TT

Apply the dominant trait key to parents and offspring

Use the same T/t pigment gene with a different shading key: in this pedigree, filled means pigment present, the dominant feature. Parent I-1 is filled and parent I-2 is unfilled. Offspring II-1 is unfilled and II-2 is filled. Square and circle shapes follow the supplied male/female symbol key, but the gene is autosomal and the phenotype rule is the same for either shape.

The unfilled I-2 parent has genotype tt, since pigment absence requires no T. Unfilled offspring II-1 is also tt. That offspring received t from each parent, so the filled I-1 parent must have t as well as T for its own pigment phenotype. I-1 is therefore Tt, not TT. This resolves a previously ambiguous dominant phenotype by using the linked offspring evidence.

Use known gamete contributions to resolve a dominant genotype

Filled offspring II-2 must receive t from the tt parent I-2. To show pigment it must receive T from I-1, making its genotype Tt. It cannot be TT in this normal model because the tt parent supplies no T. If only II-2 had been observed, without the recessive II-1 record, I-1 could still have been TT or Tt; the exact evidence supporting the deduction matters.

The resulting Tt × tt parental cross predicts pigment present to absent as 1:1. It does not require an alternating sequence or a perfectly balanced finite pedigree. Nor does filled always mean dominant in other diagrams: compare this key with the preceding recessive-key example. Read the current trait key, expression rule and family lines each time rather than carrying shading assumptions between pedigrees.

Pause and explain

Why must filled I-1 be Tt when its linked offspring is tt?

Put the idea to work

Worked example

A pigment-producing I-1 with a tt partner has a tt child. Infer I-1 and a pigment-producing sibling.

Show the worked solution
  1. The tt child establishes that I-1 supplied t. Its pigment phenotype also establishes T, giving Tt.
  2. The pigment-producing sibling receives t from the tt partner and must receive T for pigment, giving Tt rather than TT.

Answer Filled I-1 with unfilled tt partner has an unfilled tt offspring: I-1 must be Tt. A filled offspring with that tt parent is Tt, not TT.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

In the declared dominant-key pedigree, assign the genotypes of unfilled parent I-2 and unfilled offspring II-1.

Give me a hint

Unfilled means pigment absent under this key.

Compare my reasoning
  1. Apply absence requires tt to I-2.
  2. Apply the same rule to II-1.

I-2 is tt and II-1 is tt in this normal model.

Look for these in your work

  • Correct parent tt
  • Correct offspring tt
2 · Independent

Filled I-1 shows pigment and supplied t to II-1. Determine I-1 and filled offspring II-2, whose other parent is tt.

Give me a hint

Use both phenotype and parental contribution evidence.

Compare my reasoning
  1. Assign Tt to I-1.
  2. Use t from I-2 for II-2.
  3. Add T to produce II-2’s pigment phenotype.

I-1 is Tt. II-2 is Tt because it receives t from its tt parent and T for the dominant phenotype from I-1.

Look for these in your work

  • Correct I-1 Tt
  • Correct II-2 Tt with source explanation
3 · Transfer

If the pedigree recorded only the filled offspring II-2 and the same parents, explain which genotypes could fit filled I-1 and why the unfilled II-1 record resolves the uncertainty.

Give me a hint

A filled parent could be TT or Tt until t transmission is established.

Compare my reasoning
  1. List TT and Tt from I-1’s phenotype alone.
  2. Use the tt offspring to establish a t contribution.

Without II-1, I-1 could be TT or Tt. The tt offspring II-1 establishes that I-1 supplied t; combined with its pigment phenotype, this identifies Tt under the stated normal model.

Look for these in your work

  • Retains TT or Tt before extra evidence
  • Explains why tt offspring resolves I-1 as Tt

Common mistakes

  • Carrying the previous diagram’s shading meaning into this one
  • Calling every dominant phenotype TT
  • Ignoring the known tt parent when assigning a filled offspring genotype
Recall without your notes

What can you explain now?

Why must filled I-1 be Tt when its linked offspring is tt?

Compare with the explanation

It carries T for its own phenotype and supplied t to that offspring

Both pieces of evidence identify its allele pair.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

Without your notes, apply the dominant trait key to parents and offspring and use known gamete contributions to resolve a dominant genotype. Use the supplied allele key and state what the evidence can establish.

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Biology (9-1)

Course scope and assessment

780 sequenced lessons provide 2340 guided, independent and application problems in characteristics, classification, cells, organisation, specimen size, membrane transport, biological molecules, enzymes, plant and human nutrition, plant transport, circulatory systems, the heart, blood vessels, blood, disease transmission, body defences, immunity, gas exchange in humans, respiration energy uses and investigations, aerobic respiration, anaerobic respiration and recovery, excretion in humans, coordination and response, sense organs, hormones, homeostasis, tropic responses, drugs, asexual reproduction, sexual reproduction, sexual reproduction in plants, sexual reproduction in humans, sex hormones in humans, sexually transmitted infections, chromosomes, genes and proteins, mitosis, meiosis, monohybrid inheritance, variation, adaptive features, selection, energy flow, food chains and webs, nutrient cycles, population, community, ecosystem, population-growth phases, food supply, habitat destruction, pollution, conservation, biotechnology and genetic modification. 61 of 61 syllabus sections have linked teaching and staged practice. The earlier inheritance overview remains introductory, and the monohybrid pathway develops the relevant Core and Supplement requirements. This is not full programme completion or guaranteed exam readiness. Written practice is self-checked. This is the separate 9–1 qualification 0970; Cambridge states that its 2026–2028 subject content is otherwise the same as 0610. This 9–1 graded qualification is available only in a limited number of administrative zones. Confirm that your centre can enter you for this code and exam series with Cambridge International. The 2029 syllabus is separately published at https://www.cambridgeinternational.org/Images/764352-2029-syllabus.pdf and is not yet mapped here. This course supports exams in 2026, 2027 and 2028 only.

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