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IGCSE · Cambridge (CIE) · 0970

Trace bacterial production of a human protein

A human gene can be cut and joined into a bacterial plasmid, transferred to bacteria, multiplied and expressed to make the human protein.

Genetic modification pathway · 0970 (9–1) · 21.3
Exam scope and assessment notes

Extended only (Supplement) · Biology 0970, 2026–2028. Use the stated specimen features and evidence. Diagrams are schematic. Written practice is self-checked; human subject-teacher review, supervised practical competence and cumulative assessment remain pending. Cambridge states that IGCSE 0970 has the same subject content as IGCSE 0610, with 9–1 grading. This StudyForA pathway maps the 2026–2028 syllabus only. This 9–1 graded qualification is available only in a limited number of administrative zones. Confirm that your centre can enter you for this code and exam series with Cambridge International. Cambridge has published a separate syllabus for 2029. StudyForA has not reconciled that version yet; this page supports exams in 2026, 2027 and 2028 only.

Before you begin

  • Know that genes are sections of DNA and that organisms use enzymes in cellular processes.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

What does DNA ligase do in the taught genetic-modification process?

What you will learn

  • Sequence the syllabus steps for bacterial production of a human protein
  • Explain the roles of restriction enzymes, sticky ends, DNA ligase and recombinant plasmids

Build a recombinant plasmid

A restriction enzyme cuts DNA at a particular sequence. It is used to isolate the DNA making up a human gene and to cut bacterial plasmid DNA with the same enzyme, forming complementary sticky ends.

The matching ends allow the human gene to join with the plasmid DNA. DNA ligase joins the DNA to form a recombinant plasmid containing the human gene.

Transfer, multiply and express the gene

The recombinant plasmid is inserted into bacteria. The bacteria containing recombinant plasmids multiply, increasing the number of gene copies. The human gene is expressed in bacteria, which make the human protein.

The syllabus does not require specific details of how recombinant plasmids enter the bacteria. Keep the sequence clear: cut gene and plasmid with the same restriction enzyme, join with ligase, transfer the plasmid, multiply bacteria and express the gene.

Pause and explain

Why are the same restriction enzymes used on the gene DNA and plasmid?

Put the idea to work

Worked example

Put these steps in order: bacterial gene expression, ligase joins DNA, bacteria multiply, plasmid and human gene cut with the same restriction enzyme, recombinant plasmid enters bacteria.

Show the worked solution
  1. Joining happens after DNA has matching ends.
  2. Transfer precedes bacterial multiplication and expression.

Answer Cut the human gene and plasmid with the same restriction enzyme; ligase joins them into a recombinant plasmid; insert the plasmid into bacteria; bacteria multiply; the gene is expressed to make the human protein.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Outline the steps from cutting the human gene and plasmid to making a human protein in bacteria.

Give me a hint

Keep the operations in order.

Compare my reasoning
  1. Same restriction enzyme cuts the gene and plasmid, forming complementary sticky ends.
  2. Ligase joins them; the recombinant plasmid enters bacteria, which multiply and express the gene.

Restriction enzymes cut the human gene and bacterial plasmid with the same enzyme, forming complementary sticky ends. DNA ligase joins them into a recombinant plasmid. The plasmid is inserted into bacteria; bacteria multiply and express the human gene to make the protein.

Look for these in your work

  • Correct order
  • Enzyme roles accurate
2 · Independent

State the roles of restriction enzymes and DNA ligase.

Give me a hint

One cuts DNA; the other joins DNA.

Compare my reasoning
  1. Restriction enzymes cut at specific sequences and form sticky ends.
  2. DNA ligase joins the human gene and plasmid DNA.

Restriction enzymes cut the human gene DNA and plasmid DNA with matching sticky ends. DNA ligase joins the gene into the plasmid to form recombinant DNA.

Look for these in your work

  • Both enzymes named
  • Roles distinguished
3 · Transfer

Why must bacteria containing the recombinant plasmid multiply before large-scale protein production?

Give me a hint

Link cell multiplication with the number of gene copies and producing cells.

Compare my reasoning
  1. Multiplication increases the number of bacteria carrying the plasmid.
  2. More such cells can express the human gene.

Multiplication increases the number of bacteria carrying the recombinant plasmid, so many cells can express the human gene and produce the protein.

Look for these in your work

  • Plasmid-carrying cells identified
  • Multiplication linked to production

Common mistakes

  • Using different restriction enzymes for the two DNA sources in the taught outline
  • Saying DNA ligase cuts DNA
  • Putting protein production before gene expression
Recall without your notes

What can you explain now?

What does DNA ligase do in the taught genetic-modification process?

Compare with the explanation

Joins the human gene to plasmid DNA

Ligase joins DNA to form a recombinant plasmid.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

Sequence the gene-transfer process and distinguish restriction enzymes, DNA ligase, plasmid transfer and gene expression.

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Biology (9-1)

Course scope and assessment

780 sequenced lessons provide 2340 guided, independent and application problems in characteristics, classification, cells, organisation, specimen size, membrane transport, biological molecules, enzymes, plant and human nutrition, plant transport, circulatory systems, the heart, blood vessels, blood, disease transmission, body defences, immunity, gas exchange in humans, respiration energy uses and investigations, aerobic respiration, anaerobic respiration and recovery, excretion in humans, coordination and response, sense organs, hormones, homeostasis, tropic responses, drugs, asexual reproduction, sexual reproduction, sexual reproduction in plants, sexual reproduction in humans, sex hormones in humans, sexually transmitted infections, chromosomes, genes and proteins, mitosis, meiosis, monohybrid inheritance, variation, adaptive features, selection, energy flow, food chains and webs, nutrient cycles, population, community, ecosystem, population-growth phases, food supply, habitat destruction, pollution, conservation, biotechnology and genetic modification. 61 of 61 syllabus sections have linked teaching and staged practice. The earlier inheritance overview remains introductory, and the monohybrid pathway develops the relevant Core and Supplement requirements. This is not full programme completion or guaranteed exam readiness. Written practice is self-checked. This is the separate 9–1 qualification 0970; Cambridge states that its 2026–2028 subject content is otherwise the same as 0610. This 9–1 graded qualification is available only in a limited number of administrative zones. Confirm that your centre can enter you for this code and exam series with Cambridge International. The 2029 syllabus is separately published at https://www.cambridgeinternational.org/Images/764352-2029-syllabus.pdf and is not yet mapped here. This course supports exams in 2026, 2027 and 2028 only.

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