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IGCSE · Cambridge (CIE) · 0970

Infer genotypes in a stated recessive pedigree while keeping ambiguity explicit

Use the stated recessive rule to infer parents, while an unfilled sibling can remain ambiguous.

Monohybrid inheritance pathway · 0970 (9–1) · 17.4
Exam scope and assessment notes

Core and Extended · Biology 0970, 2026–2028. Use the stated specimen features and evidence. Diagrams are schematic. Written practice is self-checked; human subject-teacher review, supervised practical competence and cumulative assessment remain pending. Cambridge states that IGCSE 0970 has the same subject content as IGCSE 0610, with 9–1 grading. This StudyForA pathway maps the 2026–2028 syllabus only. This 9–1 graded qualification is available only in a limited number of administrative zones. Confirm that your centre can enter you for this code and exam series with Cambridge International. Cambridge has published a separate syllabus for 2029. StudyForA has not reconciled that version yet; this page supports exams in 2026, 2027 and 2028 only.

Before you begin

  • Recall chromosomes, genes and alleles, meiosis, haploid gametes and fertilisation restoring two chromosome sets.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

Which genotype gives pigment absence under this rule?

What you will learn

  • Use a recessive offspring to infer parental allele contributions
  • Keep an unfilled sibling’s two possible genotypes separate

Original teaching model. Pedigrees and records are fictional; allele and probability assumptions are stated.

Infer genotypes in a stated recessive pedigree while keeping ambiguity explicitUse the stated recessive rule to infer parents, while an unfilled sibling can remain ambiguous.Original fictional pedigreeFilled = pigment absent (tt); T isdominant for pigmentIIII-1TtI-2TtII-1ttII-2TT or TtShapes, shading and inferredgenotypes follow the stated key
Use the stated recessive rule to infer parents, while an unfilled sibling can remain ambiguous.
Allele, phenotype and evidence key
FeatureMeaning
Filled trait keyPigment absent, recessive tt
I-1 and I-2Pigment present; each supplied t; both Tt
II-1Filled offspring: tt
II-2Unfilled offspring: TT or Tt

Use a recessive offspring to infer parental allele contributions

Use this declared autosomal pigment model: T gives pigment when present and tt gives pigment absence. In this pedigree, filled symbols mean pigment absence, the recessive feature. Both parents I-1 and I-2 are unfilled and therefore show pigment. Their offspring II-1 is filled and has no pigment, while II-2 is unfilled and shows pigment. The pedigree is invented and follows the stated normal inheritance rule.

The filled II-1 individual has genotype tt because absence is expressed only without T. One t contribution must come from each parent. Each unfilled parent also shows the dominant pigment feature, so each must contain T. Combining these two deductions gives Tt for both I-1 and I-2. The inference uses both the phenotype rule and the supplied parent-child links, not shading alone.

Keep an unfilled sibling’s two possible genotypes separate

The unfilled sibling II-2 has pigment, so its genotype can be TT or Tt under this rule. Having a recessive sibling does not choose between those possibilities. Both are possible in the parental Tt × Tt square. Write the ambiguity explicitly instead of assigning Tt to every unfilled symbol or claiming all siblings must share one genotype.

For a later offspring under the same independent normal model, the cross predicts three pigment to one absence in phenotypes. The already observed pedigree does not force the next offspring to compensate toward a perfect ratio. These deductions rely on the supplied gene, expression rule, parentage and normal transmission assumptions; the diagram does not independently establish a mechanism for an unspecified real characteristic.

Pause and explain

What are the two pigment-producing parents’ genotypes if they have a tt offspring in this normal model?

Put the idea to work

Worked example

In the supplied recessive-key pedigree, what can be inferred from two pigment-producing parents and a tt offspring?

Show the worked solution
  1. A tt child received t from each parent under normal transmission. Each parent must therefore contain t.
  2. The parents have pigment and thus also contain T: both are Tt. A pigment-producing sibling could be TT or Tt, so retain that uncertainty.

Answer Unfilled pigment-producing parents with a filled tt offspring must each contribute t and also carry T: both are Tt. The unfilled sibling remains TT or Tt.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Use the filled recessive offspring II-1 to determine its genotype and the allele it received from each parent.

Give me a hint

The declared recessive phenotype requires two t alleles.

Compare my reasoning
  1. Assign tt to II-1.
  2. Trace one t contribution from each linked parent.

II-1 is tt and received t from I-1 and t from I-2 in this normal model.

Look for these in your work

  • Correct tt genotype
  • One t contribution from each parent
2 · Independent

Both parents show pigment and each supplied t. Determine their genotypes and list possible genotypes for pigment-producing sibling II-2.

Give me a hint

Each parent needs T for its phenotype and t for the observed transmission.

Compare my reasoning
  1. Combine T and t in each parent.
  2. Identify pigment-producing offspring genotypes in Tt × Tt.

I-1 and I-2 are both Tt. II-2 can be TT or Tt; its pigment phenotype does not distinguish those possibilities.

Look for these in your work

  • Both parental Tt genotypes
  • Sibling ambiguity TT or Tt retained
3 · Transfer

A student predicts the next child must show pigment because one recessive offspring is already present in the pedigree. Correct this under the independent model.

Give me a hint

An observed outcome does not impose balancing on the next event.

Compare my reasoning
  1. Retain the Tt × Tt cross.
  2. State the predicted phenotype probabilities.
  3. Reject compulsory compensation.

The next offspring has pigment probability 3/4 and absence probability 1/4 under the model. The existing recessive offspring does not guarantee the next phenotype or force the pedigree into a perfect ratio.

Look for these in your work

  • Correct three-quarter and one-quarter probabilities
  • No forced-compensation claim

Common mistakes

  • Assigning recessiveness from shading without the key
  • Calling every pigment-producing sibling Tt
  • Treating the observed pedigree as a compulsory future ratio
Recall without your notes

What can you explain now?

What are the two pigment-producing parents’ genotypes if they have a tt offspring in this normal model?

Compare with the explanation

Both Tt

Each supplied t to the offspring and also has T for its own phenotype.

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Make it stick

Without your notes, use a recessive offspring to infer parental allele contributions and keep an unfilled sibling’s two possible genotypes separate. Use the supplied allele key and state what the evidence can establish.

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Biology (9-1)

Course scope and assessment

780 sequenced lessons provide 2340 guided, independent and application problems in characteristics, classification, cells, organisation, specimen size, membrane transport, biological molecules, enzymes, plant and human nutrition, plant transport, circulatory systems, the heart, blood vessels, blood, disease transmission, body defences, immunity, gas exchange in humans, respiration energy uses and investigations, aerobic respiration, anaerobic respiration and recovery, excretion in humans, coordination and response, sense organs, hormones, homeostasis, tropic responses, drugs, asexual reproduction, sexual reproduction, sexual reproduction in plants, sexual reproduction in humans, sex hormones in humans, sexually transmitted infections, chromosomes, genes and proteins, mitosis, meiosis, monohybrid inheritance, variation, adaptive features, selection, energy flow, food chains and webs, nutrient cycles, population, community, ecosystem, population-growth phases, food supply, habitat destruction, pollution, conservation, biotechnology and genetic modification. 61 of 61 syllabus sections have linked teaching and staged practice. The earlier inheritance overview remains introductory, and the monohybrid pathway develops the relevant Core and Supplement requirements. This is not full programme completion or guaranteed exam readiness. Written practice is self-checked. This is the separate 9–1 qualification 0970; Cambridge states that its 2026–2028 subject content is otherwise the same as 0610. This 9–1 graded qualification is available only in a limited number of administrative zones. Confirm that your centre can enter you for this code and exam series with Cambridge International. The 2029 syllabus is separately published at https://www.cambridgeinternational.org/Images/764352-2029-syllabus.pdf and is not yet mapped here. This course supports exams in 2026, 2027 and 2028 only.

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