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A Level · Cambridge (CIE) · 9702

Describe couples and calculate their torque

Identify a couple as two equal, opposite, separated forces and calculate its torque from the perpendicular separation.

Forces, density and pressure · Cambridge International AS & A Level Physics 9702 · 4.1

AS Level; Cambridge International Physics 9702, 2025–2027 syllabus, Topic 4. These original explanations and numerical practice support theory study; they do not demonstrate supervised practical competence. Full timed assessment and human subject-teacher review remain outstanding.

Before you begin

  • Use SI units, resolve perpendicular components, and distinguish force from pressure.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

What is the resultant force of an ideal couple?

What you will learn

  • Describe how a couple produces rotation only
  • Identify the equal and opposite forces and their separation
  • Calculate the torque of a couple

A couple has two forces and no resultant force

A couple consists of two equal-magnitude, parallel forces acting in opposite directions along different lines. Their resultant force is zero, but because the lines are separated they produce a turning effect.

For a pure couple, the pair tends to rotate the object without giving it a resultant translational force. Examples include turning a steering wheel with two hands or twisting a jar lid.

Torque uses the separation between the force lines

The torque of a couple is the magnitude of either force multiplied by the perpendicular separation between the two lines of action. Torque = Fd. Its SI unit is N m.

Use the perpendicular separation between the forces, not the distance from an arbitrary pivot. Do not double the answer by separately adding the two individual moments: their combined effect is already F times the full separation.

torque of a couple = either force magnitude × perpendicular separation of the force lines

Pause and explain

Why can a couple rotate an object despite zero resultant force?

Put the idea to work

Worked example

Two hands apply equal and opposite 15 N forces to a wheel. Their lines of action are 0.40 m apart. Find the torque of the couple.

Show the worked solution
  1. The forces are equal, opposite and parallel, so they form a couple.
  2. Torque = Fd = 15 × 0.40.
  3. Use the full perpendicular separation between the two force lines once.

Answer 6.0 N m.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

A couple is made by two opposite 8.0 N forces whose lines of action are 0.30 m apart. Calculate its torque.

Give me a hint

Use one force magnitude and the full perpendicular separation.

Compare my reasoning
  1. Torque = Fd.
  2. Torque = 8.0 × 0.30.
  3. Give the unit N m.

2.4 N m.

Look for these in your work

  • Couple relationship used
  • Separation used once
  • Correct unit
2 · Independent

A mechanic applies a torque of 5.0 N m with two equal opposite forces separated by 0.25 m. Find either force magnitude.

Give me a hint

Rearrange torque = force × separation.

Compare my reasoning
  1. F = torque/d.
  2. F = 5.0/0.25.
  3. Check that N m divided by m gives N.

20 N for each force, acting in opposite directions.

Look for these in your work

  • Equation rearranged
  • Magnitude calculated
  • Paired directions stated
3 · Transfer

A student pushes a door with two equal opposite forces along lines 0.50 m apart. The torque is 4.0 N m. Find each force and state the couple's resultant force.

Give me a hint

Use the separation of the lines and distinguish torque from net force.

Compare my reasoning
  1. F = torque/d = 4.0/0.50 = 8.0 N.
  2. Each force has magnitude 8.0 N.
  3. Because they are equal and opposite, their resultant force is zero.

Each force is 8.0 N; resultant force is zero while torque is 4.0 N m.

Look for these in your work

  • Either force found
  • Equal opposite pair retained
  • Torque and resultant force distinguished

Common mistakes

  • Using the distance from a chosen pivot instead of the separation of force lines
  • Adding both force magnitudes before multiplying by the separation
  • Calling a single off-centre force a couple
Recall without your notes

What can you explain now?

What is the resultant force of an ideal couple?

Compare with the explanation

Zero

Its two forces have equal magnitudes and opposite directions.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

How can a force pair have zero resultant force but non-zero torque?

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

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Course scope and assessment

One hundred and sixty-two original lessons cover all 12 published subject-content outcomes in Topic 1 (sections 1.1–1.4), all nine outcomes in Topic 2 (section 2.1), all 13 outcomes in Topic 3 (sections 3.1–3.3), all 13 outcomes in Topic 4 (sections 4.1–4.3), all 11 outcomes in Topic 5 (sections 5.1–5.2), all 10 outcomes in Topic 6 (sections 6.1–6.2), all 16 outcomes in Topic 7 (sections 7.1–7.5), all 12 outcomes in Topic 8 (sections 8.1–8.4), all 15 outcomes in Topic 9 (sections 9.1–9.3), all 16 outcomes in Topic 10 (sections 10.1–10.3), all 18 outcomes in Topic 11 (sections 11.1–11.2), all seven outcomes in Topic 12 (sections 12.1–12.2), all 12 outcomes in Topic 13 (sections 13.1–13.4), all eight outcomes in Topic 14 (sections 14.1–14.3), and all nine outcomes in Topic 15 (sections 15.1–15.3), plus all four outcomes in Topic 16 (sections 16.1–16.2), and all ten outcomes in Topic 17 (sections 17.1–17.3), plus all 12 outcomes in Topic 18 (sections 18.1–18.5), all nine outcomes in Topic 19 (sections 19.1–19.3), all 19 outcomes in Topic 20 (sections 20.1–20.5), and all eight outcomes in Topic 21 (sections 21.1–21.2), and all 17 outcomes in Topic 22 (sections 22.1–22.4), and all 13 outcomes in Topic 23 (sections 23.1–23.2), and all 16 outcomes in Topic 24 (sections 24.1–24.3), and all 11 outcomes in Topic 25 (sections 25.1–25.3), of the 2025–2027 syllabus. Each lesson has guided, independent and application practice with explained answers. All 25 syllabus topics now have mapped teaching and practice; the 2028–2030 changes outside Topics 23–25 still need reconciliation. Online study cannot demonstrate supervised Paper 3 laboratory competence. Paper 5 planning and analysis, full timed cumulative assessment and human subject-teacher review remain outstanding.

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