Learn in your language
Skip to content
A Level · Cambridge (CIE) · 9702

Describe period, frequency and peak value

Read the period, frequency and peak value of an alternating current or voltage from its cycle and waveform.

Alternating currents · Cambridge International AS & A Level Physics 9702 · 21.1

A Level; Cambridge International Physics 9702, 2025–2027 syllabus, Topic 21. These original explanations and calculations are study aids; full timed assessment and human subject-teacher review remain outstanding.

Before you begin

  • Use period, frequency, sine graphs, current, voltage, power, diodes, capacitors and SI units.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

What is the period of an alternating voltage?

What you will learn

  • Define period and frequency for an alternating quantity
  • Identify peak value from a waveform
  • Convert between period and frequency

An alternating quantity repeats its cycle

An alternating current or voltage changes with time and reverses direction or polarity. One complete cycle returns the waveform to the same value and direction of change. The period T is the time for one cycle, measured in seconds.

Frequency f is the number of complete cycles per second, measured in hertz (Hz). Period and frequency are reciprocals: f = 1/T and T = 1/f. Read a time axis carefully: measure between equivalent points on successive cycles, such as peak to next peak.

Peak value is the maximum magnitude

The peak value x₀ is the greatest magnitude reached by the alternating current or voltage from its zero reference. A symmetric sinusoid with peak value 6 A ranges from +6 A to −6 A; its peak-to-peak value is 12 A, not 6 A.

On a graph, use the vertical scale to read the distance from zero to a crest or trough, and use the horizontal scale to read T. A larger peak-to-peak span does not change the definition of peak value: it is half that span for a symmetric waveform.

T = time for one full cycle · f = 1/T · peak value = maximum distance from zero

Pause and explain

A current has period 0.025 s. What is its frequency?

Put the idea to work

Worked example

A sinusoidal voltage completes 50 cycles in 1.0 s and reaches +325 V and −325 V. Find its frequency, period and peak value.

Show the worked solution
  1. Frequency is cycles per second.
  2. Use T = 1/f.
  3. Read the peak from zero, not peak-to-peak.

Answer f = 50 Hz, T = 1/50 = 0.020 s, and peak value V₀ = 325 V.

Try a topic test

Choose Easy, Normal or Difficult. Save your answers and open worked review after finishing.

Test this topic →

From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

A sinusoidal current completes 25 cycles in 0.50 s. Calculate its frequency and period.

Give me a hint

Find cycles per second, then take the reciprocal for period.

Compare my reasoning
  1. f = 25/0.50 = 50 Hz.
  2. T = 1/f.
  3. T = 1/50 = 0.020 s.

f = 50 Hz and T = 0.020 s.

Look for these in your work

  • Frequency calculated
  • Reciprocal relation used
  • Units stated
2 · Independent

A symmetric voltage waveform reaches +12 V and −12 V. State its peak and peak-to-peak values.

Give me a hint

Measure each quantity relative to the zero line and between opposite extremes.

Compare my reasoning
  1. The crest is 12 V above zero.
  2. The peak value is therefore 12 V.
  3. Peak-to-peak span is 12 − (−12) = 24 V.

Peak value = 12 V; peak-to-peak value = 24 V.

Look for these in your work

  • Peak measured from zero
  • Both extremes used
  • Values distinguished
3 · Transfer

A device receives an alternating current whose frequency changes from 50 Hz to 100 Hz. Compare the periods and describe the cycle rate.

Give me a hint

Use T = 1/f for both frequencies.

Compare my reasoning
  1. At 50 Hz, T = 1/50 = 0.020 s.
  2. At 100 Hz, T = 1/100 = 0.010 s.
  3. The second current completes twice as many cycles each second and each cycle takes half as long.

The period halves from 0.020 s to 0.010 s while the cycle rate doubles.

Look for these in your work

  • Both periods calculated
  • Period ratio compared
  • Frequency meaning applied

Common mistakes

  • Calling the positive-to-negative span the peak value
  • Measuring half a cycle as the period
  • Using f = T instead of f = 1/T
  • Giving frequency in seconds rather than hertz
Recall without your notes

What can you explain now?

What is the period of an alternating voltage?

Compare with the explanation

Time for one complete cycle

Period measures one full repetition in seconds.

After trying it yourself, choose your next review. This is your self-assessment.

Your review choice appears on Today. Sign in to sync it across devices.

Make it stick

How do period, frequency and peak value describe different features of an AC waveform?

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Physics

Course scope and assessment

One hundred and sixty-two original lessons cover all 12 published subject-content outcomes in Topic 1 (sections 1.1–1.4), all nine outcomes in Topic 2 (section 2.1), all 13 outcomes in Topic 3 (sections 3.1–3.3), all 13 outcomes in Topic 4 (sections 4.1–4.3), all 11 outcomes in Topic 5 (sections 5.1–5.2), all 10 outcomes in Topic 6 (sections 6.1–6.2), all 16 outcomes in Topic 7 (sections 7.1–7.5), all 12 outcomes in Topic 8 (sections 8.1–8.4), all 15 outcomes in Topic 9 (sections 9.1–9.3), all 16 outcomes in Topic 10 (sections 10.1–10.3), all 18 outcomes in Topic 11 (sections 11.1–11.2), all seven outcomes in Topic 12 (sections 12.1–12.2), all 12 outcomes in Topic 13 (sections 13.1–13.4), all eight outcomes in Topic 14 (sections 14.1–14.3), and all nine outcomes in Topic 15 (sections 15.1–15.3), plus all four outcomes in Topic 16 (sections 16.1–16.2), and all ten outcomes in Topic 17 (sections 17.1–17.3), plus all 12 outcomes in Topic 18 (sections 18.1–18.5), all nine outcomes in Topic 19 (sections 19.1–19.3), all 19 outcomes in Topic 20 (sections 20.1–20.5), and all eight outcomes in Topic 21 (sections 21.1–21.2), and all 17 outcomes in Topic 22 (sections 22.1–22.4), and all 13 outcomes in Topic 23 (sections 23.1–23.2), and all 16 outcomes in Topic 24 (sections 24.1–24.3), and all 11 outcomes in Topic 25 (sections 25.1–25.3), of the 2025–2027 syllabus. Each lesson has guided, independent and application practice with explained answers. All 25 syllabus topics now have mapped teaching and practice; the 2028–2030 changes outside Topics 23–25 still need reconciliation. Online study cannot demonstrate supervised Paper 3 laboratory competence. Paper 5 planning and analysis, full timed cumulative assessment and human subject-teacher review remain outstanding.

StudyForA · Learn with understanding

Original teaching content and links to official sources. Check your exam year and qualification before using a resource.