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IGCSE · Cambridge (CIE) · 0610

Calculate chromosome counts from stipulated diploid models

Use set counts without assuming cross-species compatibility.

Sexual reproduction pathway · 16.2

Extended only (Supplement); Biology 0610, 2026–2028. Use the stated specimen features and evidence. Diagrams are schematic. Written practice is self-checked

Before you begin

  • Recall DNA, inherited characteristics, nuclei and the distinction between growth and reproduction.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

Model B has a diploid count of eighteen. What is its stipulated gamete count?

What you will learn

  • Calculate n and 2n consistently
  • Keep counts separate from DNA copying and compatibility

Calculate chromosome counts from stipulated diploid models

Stipulated diploid counts A 12, B 18, C 24 give compatible haploid counts 6, 9, 12. Count sums do not establish cross-species compatibility. Original teaching model.

Stipulated diploid chromosome counts — compatible gametes within each model
ModelDiploid (2n)Haploid (n)
Model A126
Model B189
Model C2412
Sexual reproduction model reference
FeatureMeaning
Model A2n = 12; n = 6
Model B2n = 18; n = 9
Model C2n = 24; n = 12
LimitStipulated counts, not measured species or viability evidence

Calculate n and 2n consistently

The invented table gives diploid counts of twelve, eighteen and twenty-four for model organisms A, B and C. In the stipulated ordinary diploid model, the compatible gamete count is half of the diploid count: six, nine and twelve. Calculate within each organism, rather than using the same number for every species or interpreting n as the number of nuclei.

Compatible gamete nuclei of A contribute six plus six chromosomes to form a twelve-chromosome diploid zygote nucleus. For C, twelve plus twelve gives twenty-four. These sums restore the supplied two-set count. Showing the contribution sum explains the result better than writing a number with no statement of whether it describes a gamete or the zygote.

Keep counts separate from DNA copying and compatibility

Later DNA copying before a cell division is a different event from adding a new gamete contribution. Copying genetic material does not by itself establish another fertilisation or another complete contributor set. The lesson does not require a detailed chromatids account; use the initial fusion record for the zygote count and avoid silently doubling that answer because growth follows.

If a question combines gametes from different unspecified organisms, adding their counts alone does not prove compatibility, a viable zygote or an ordinary diploid outcome. Chromosome number is one part of a reproductive record, not a universal permission for any two gametes to fuse successfully. The table is a stipulated teaching model, not measured species data or a clinical interpretation.

Pause and explain

Does adding two gamete counts prove a viable cross between any organisms?

Put the idea to work

Worked example

An ordinary diploid model has 2n = 10. Find a compatible gamete count and the zygote count.

Show the worked solution
  1. Half of ten is five per gamete.
  2. Five plus five restores ten in the zygote.

Answer Gamete n = 5; zygote 2n = 10.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Find the gamete chromosome count for model A with diploid count twelve.

Give me a hint

Calculate one of its two sets.

Compare my reasoning
  1. Two sets contain twelve.
  2. One set contains half that count.

Six chromosomes in a compatible haploid gamete nucleus.

Look for these in your work

  • Halve the diploid count
  • Name the gamete nucleus
2 · Independent

Two compatible model C gamete nuclei each contribute twelve chromosomes. Find the initial zygote count and ploidy.

Give me a hint

Combine both complete sets.

Compare my reasoning
  1. Twelve plus twelve is twenty-four.
  2. Two sets mean diploid.

Twenty-four chromosomes in the diploid zygote nucleus.

Look for these in your work

  • Add both contributions
  • State diploid
3 · Transfer

An unfamiliar record adds a six-chromosome gamete to a nine-chromosome gamete from unspecified organisms. Does fifteen prove a viable ordinary diploid zygote?

Give me a hint

A numerical sum is not a compatibility test.

Compare my reasoning
  1. The counts sum to fifteen.
  2. Compatibility and corresponding complete sets are not established.

No. The sum is fifteen, but the record does not establish compatibility, a viable zygote or an ordinary diploid chromosome arrangement.

Look for these in your work

  • Calculate the sum
  • Keep biological evidence separate

Common mistakes

  • Halving a count without naming the resulting stage.
  • Using a sum to prove compatibility across unspecified organisms.
Recall without your notes

What can you explain now?

Does adding two gamete counts prove a viable cross between any organisms?

Compare with the explanation

No; compatibility and development need separate evidence

A sum alone is insufficient.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

Calculate gamete and zygote counts and explain why arithmetic alone cannot prove compatibility.

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Biology

Course scope and assessment

780 sequenced lessons provide 2340 guided, independent and application problems in characteristics, classification, cells, organisation, specimen size, membrane transport, biological molecules, enzymes, plant and human nutrition, plant transport, circulatory systems, the heart, blood vessels, blood, disease transmission, body defences, immunity, gas exchange in humans, respiration energy uses and investigations, aerobic respiration, anaerobic respiration and recovery, excretion in humans, coordination and response, sense organs, hormones, homeostasis, tropic responses, drugs, asexual reproduction, sexual reproduction, sexual reproduction in plants, sexual reproduction in humans, sex hormones in humans, sexually transmitted infections, chromosomes, genes and proteins, mitosis, meiosis, monohybrid inheritance, variation, adaptive features, selection, energy flow, food chains and webs, nutrient cycles, population, community, ecosystem, population-growth phases, food supply, habitat destruction, pollution, conservation, biotechnology and genetic modification. 61 of 61 syllabus sections have linked teaching and staged practice. The earlier inheritance overview remains introductory, and the monohybrid pathway develops the relevant Core and Supplement requirements. This is not full programme completion or guaranteed exam readiness. Written practice is self-checked.

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